結果

問題 No.1974 2x2 Flipper
コンテスト
ユーザー Keroru
提出日時 2022-06-10 23:16:18
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 4,220 bytes
コンパイル時間 281 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 101,376 KB
最終ジャッジ日時 2024-09-21 06:49:55
合計ジャッジ時間 7,803 ms
ジャッジサーバーID
（参考情報） 		judge5 / judge3
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 20 WA * 4 RE * 1
権限があれば一括ダウンロードができます

ソースコード

diff # 

import sys
read=sys.stdin.buffer.read;readline=sys.stdin.buffer.readline;input=lambda:sys.stdin.readline().rstrip()
import bisect,string,math,time,functools,random,fractions
from bisect import*
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
from itertools import permutations,combinations,groupby
rep=range;R=range
def I():return int(input())
def LI():return [int(i) for i in input().split()]
def SLI():return sorted([int(i) for i in input().split()])
def LI_():return [int(i)-1 for i in input().split()]
def S_():return input()
def IS():return input().split()
def LS():return [i for i in input().split()]
def NI(n):return [int(input()) for i in range(n)]
def NI_(n):return [int(input())-1 for i in range(n)]
def NLI(n):return [[int(i) for i in input().split()] for i in range(n)]
def NLI_(n):return [[int(i)-1 for i in input().split()] for i in range(n)]
def StoLI():return [ord(i)-97 for i in input()]
def ItoS(n):return chr(n+97)
def LtoS(ls):return ''.join([chr(i+97) for i in ls])
def RLI(n=8,a=1,b=10):return [random.randint(a,b)for i in range(n)]
def RI(a=1,b=10):return random.randint(a,b)
def INP():
    N=3
    n=random.randint(1,N)
    n=3
    p=4
    mn,mx=1,100000000
    q=[[random.randint(mn,mx) for i in range(p)]for i in range(n)]
    return n,p,q
def Rtest(T):
    case,err=0,0
    for i in range(T):
        inp=INP()
        a1=naive(*inp)
        a2=solve(*inp)
        if a1!=a2:
            print(inp)
            print('naive',a1)
            print('solve',a2)
            err+=1
        case+=1
    print('Tested',case,'case with',err,'errors')
def GI(V,E,ls=None,Directed=False,index=1):
    org_inp=[];g=[[] for i in range(V)]
    FromStdin=True if ls==None else False
    for i in range(E):
        if FromStdin:
            inp=LI()
            org_inp.append(inp)
        else:
            inp=ls[i]
        if len(inp)==2:a,b=inp;c=1
        else:a,b,c=inp
        if index==1:a-=1;b-=1
        aa=a,c,;bb=b,c,;g[a].append(bb)
        if not Directed:g[b].append(aa)
    return g,org_inp
def RE(E):
    rt=[[]for i in range(len(E))]
    for i in range(len(E)):
        for nb,d in E[i]:
            rt[nb]+=(i,d),
    return rt
def GGI(h,w,search=None,replacement_of_found='.',mp_def={'#':1,'.':0},boundary=1):
    #h,w,g,sg=GGI(h,w,search=['S','G'],replacement_of_found='.',mp_def={'#':1,'.':0},boundary=1) # sample usage
    mp=[boundary]*(w+2);found={}
    for i in R(h):
        s=input()
        for char in search:
            if char in s:
                found[char]=((i+1)*(w+2)+s.index(char)+1)
                mp_def[char]=mp_def[replacement_of_found]
        mp+=[boundary]+[mp_def[j] for j in s]+[boundary]
    mp+=[boundary]*(w+2)
    return h+2,w+2,mp,found
def TI(n):return GI(n,n-1)
def accum(ls):
    rt=[0]
    for i in ls:rt+=[rt[-1]+i]
    return rt
def bit_combination(n,base=2):
    rt=[]
    for tb in R(base**n):s=[tb//(base**bt)%base for bt in R(n)];rt+=[s]
    return rt
def gcd(x,y):
    if y==0:return x
    if x%y==0:return y
    while x%y!=0:x,y=y,x%y
    return y
def RLE(it):
    rt=[]
    for i in it:
        if rt and rt[-1][0]==i:rt[-1][1]+=1
        else:rt+=[i,1],
    return rt
def YN(x):print(['NO','YES'][x])
def Yn(x):print(['No','Yes'][x])
def show(*inp,end='\n'):
    if show_flg:print(*inp,end=end)
def gcj(t,*a):
    print('Case #{}:'.format(t+1),*a)

mo=10**9+7
#mo=998244353
inf=float('inf')
FourNb=[(-1,0),(1,0),(0,1),(0,-1)];EightNb=[(-1,0),(1,0),(0,1),(0,-1),(1,1),(-1,-1),(1,-1),(-1,1)];compas=dict(zip('WENS',FourNb));cursol=dict(zip('LRUD',FourNb))
alp=[chr(ord('a')+i)for i in range(26)]
#sys.setrecursionlimit(10**7)


show_flg=False
show_flg=True

ans=0

h,w=LI()
d=[[1]*w for i in range(h)]
ans=h*w
if h==1 and w==1:
    print(0)
    print(0)
    exit()
    
if h%2==1 and w%2==0:
    ans-=w
    for i in range(w):
        d[0][i]=0
elif h%2==0 and w%2==1:
    ans-=h
    for i in range(h):
        d[i][0]=0
elif h%2==1 and w%2==1:
    ans-=3
    for i in range(3):
        d[i][2-i]=0
    if h>3:
        ans-=h-3
        for i in range(3,h):
            d[i][0]=0
    if w>3:
        ans-=w-3
        for i in range(3,w):
            d[0][i]=0

print(ans)
for i in d:
    print(*i)
0