結果

問題 No.5006 Hidden Maze
ユーザー 👑 NachiaNachia
提出日時 2022-06-12 15:10:41
言語 C++17(gcc12)
(gcc 12.3.0 + boost 1.87.0)
結果
RE  
実行時間 -
コード長 3,730 bytes
コンパイル時間 968 ms
実行使用メモリ 22,888 KB
スコア 19,176
平均クエリ数 43.15
最終ジャッジ日時 2022-06-12 15:10:50
合計ジャッジ時間 8,454 ms
ジャッジサーバーID
(参考情報)
judge16 / judge15
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 20 RE * 80
権限があれば一括ダウンロードができます

ソースコード

diff #


#include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#include <map>
#include <queue>
#include <cmath>
#include <atcoder/modint>

using namespace std;
using u32 = unsigned int;
using i64 = long long;
using u64 = unsigned long long;
#define rep(i,n) for(int i=0; i<(int)(n); i++)


const i64 INF = 1001001001001001001;
using modint = atcoder::static_modint<1000000007>;

const int H = 20;
const int W = 20;

const int dx[4] = { 0, 1, 0, -1 };
const int dy[4] = { 1, 0, -1, 0 };
const string DIRCHAR = "DRUL";



template<class E>
using nega_queue = priority_queue<E, vector<E>, greater<E>>;

double p;
double log_p;

double HEdge[H-1][W];
double VEdge[H][W-1];
void initEdge(){
    rep(y,H-1) rep(x,W) HEdge[y][x] = 0.3;
    rep(y,H) rep(x,W-1) VEdge[y][x] = 0.3;
}


struct Pos {
    int y, x;
    Pos movedByDirection(int dir) const {
        Pos res;
        res.x = x + dx[dir];
        res.y = y + dy[dir];
        return res;
    }

    bool isInBoard() const {
        return 0 <= y && 0 <= x && y < H && x < W;
    }

    double& dirCostRef(int dir) const {
        if(!movedByDirection(dir).isInBoard()) exit(1);
        if(dir > 4) exit(1);
        switch(DIRCHAR[dir]){
        case 'L' : return VEdge[y][x-1];
        case 'R' : return VEdge[y][x];
        case 'U' : return HEdge[y-1][x];
        case 'D' : return HEdge[y][x];
        }
        exit(1);
    }

    double dirCost(int dir) const {
        if(!movedByDirection(dir).isInBoard()) return 1.0e100;
        if(dir > 4) return 1.0e100;
        switch(DIRCHAR[dir]){
        case 'L' : return VEdge[y][x-1];
        case 'R' : return VEdge[y][x];
        case 'U' : return HEdge[y-1][x];
        case 'D' : return HEdge[y][x];
        }
        return 1.0e100;
    }

    static Pos getGoal(){ return Pos{ H-1, W-1 }; }
};


vector<int> dijkstra(){
    static double dist[H][W];
    static int prevdir[H][W];
    rep(y,H) rep(x,W) dist[y][x] = 1.0e100;
    rep(y,H) rep(x,W) prevdir[y][x] = -1;
    dist[0][0] = 0;
    struct DijkstraNode{
        double d; Pos p;
        bool operator>(const DijkstraNode& r) const { return d > r.d; }
    };
    nega_queue<DijkstraNode> A;
    A.push({ 0.0, Pos{0, 0} });
    while(A.size()){
        auto [d,pos] = A.top();
        A.pop();
        if(dist[pos.y][pos.x] != d) continue;
        rep(dir,4){
            Pos nx = pos.movedByDirection(dir);
            if(!nx.isInBoard()) continue;
            double nxd = pos.dirCost(dir) + d;
            if(dist[nx.y][nx.x] <= nxd) continue;
            dist[nx.y][nx.x] = nxd;
            prevdir[nx.y][nx.x] = dir;
            A.push({ nxd, nx });
        }
    }
    
    Pos p = Pos::getGoal();
    vector<int> res;
    while(prevdir[p.y][p.x] != -1){
        res.push_back(prevdir[p.y][p.x]);
        p = p.movedByDirection(prevdir[p.y][p.x] ^ 2);
    }
    reverse(res.begin(), res.end());
    return res;
}


int ask(vector<int> D){
    string S;
    for(int d : D) S.push_back(DIRCHAR[d]);
    cout << S << '\n' << flush;
    int res; cin >> res;
    if(res == -1) exit(0);

    Pos p = { 0, 0 };
    for(int i=0; i<res; i++){
        int d = D[i];
        p.dirCostRef(d) = 0.0;
        p = p.movedByDirection(d);
        p.dirCostRef(d^2) = 0.0;
    }
    p.dirCostRef(D[res]) -= log_p;
    p = p.movedByDirection(D[res]);
    p.dirCostRef(D[res]) -= log_p;
    return res;
}

bool solve(){
    ask(dijkstra());
    return true;
}


int main(){
    initEdge();
    int h, w, pp; cin >> h >> w >> pp;
    p = pp / 100.0;
    log_p = log(p);
    while(solve());
    return 0;
}


struct ios_do_not_sync{
    ios_do_not_sync(){
        std::ios::sync_with_stdio(false);
        std::cin.tie(nullptr);
    }
} ios_do_not_sync_instance;


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