結果
| 問題 |
No.1979 [Cherry 4th Tune A] I min !
|
| コンテスト | |
| ユーザー |
|
| 提出日時 | 2022-06-17 21:21:31 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 2 ms / 2,000 ms |
| コード長 | 4,199 bytes |
| コンパイル時間 | 3,256 ms |
| コンパイル使用メモリ | 162,408 KB |
| 実行使用メモリ | 6,820 KB |
| 最終ジャッジ日時 | 2024-10-09 06:47:02 |
| 合計ジャッジ時間 | 3,998 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge4 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 24 |
ソースコード
#include <iostream>
#include <algorithm>
#include <vector>
#include <string>
#include <math.h>
#include <iomanip>
#include <fstream>
#include <map>
#include <set>
#include <queue>
#include <list>
#include <iomanip>
#include <numeric>
#include <bitset>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
template<typename T1, typename T2>
class myPair : public std::pair<T1, T2>{
using std::pair<T1, T2>::pair;
public:
inline const myPair<T1, T2> operator+(const myPair<T1, T2> &p) { return {this->first + p.first, this->second + p.second}; }
inline const myPair<T1, T2> operator-(const myPair<T1, T2> &p) { return {this->first - p.first, this->second - p.second}; }
template<typename U> inline const myPair<T1, T2> operator*(const U &p) { return {this->first * p, this->second * p}; }
template<typename U> inline const myPair<T1, T2> operator/(const U &p) { return {this->first / p, this->second / p}; }
inline myPair& operator+=(const myPair<T1, T2> &p) {
*this = *this + p;
return *this;
}
inline myPair& operator-=(const myPair<T1, T2> &p) {
*this = *this - p;
return *this;
}
template<typename U> inline myPair& operator*=(const U &x) {
*this = *this * x;
return *this;
}
template<typename U> inline myPair& operator/=(const U &x) {
*this = *this / x;
return *this;
}
};
#define pair myPair
using ll = long long;
using mint = modint1000000007;
using mint_ = modint998244353;
using P = pair<int,int>;
using PL = pair<ll,ll>;
using V = vector<int>;
using VL = vector<ll>;
using VD = vector<double>;
using VC = vector<char>;
using VP = vector<P>;
using VS = vector<string>;
using VM = vector<mint>;
using VM_ = vector<mint_>;
using VV = vector<V>;
using VVL = vector<VL>;
using VVD = vector<VD>;
using VVC = vector<VC>;
using VVP = vector<VP>;
using VVS = vector<VS>;
using VVM = vector<VM>;
using VVM_ = vector<VM_>;
const int INF = 1001001001;
const ll INFL = 1001001001001001001;
const ll MOD = 1000000007;
const ll MOD_ = 998244353;
const V DH = {0,1,0,-1};
const V DW = {1,0,-1,0};
struct grid{int h, w;};
#define rep(i, j, n) for(ll i = (ll)(j); i < (ll)(n); i++)
#define repb(i, j, n) for(ll i = (ll)(n-1); i >= (ll)(j); i--)
#define reps(i, j, n) for(ll i = (ll)(j); i <= (ll)(n); i++)
#define repsb(i, j, n) for(ll i = (ll)(n); i >= (ll)(j); i--)
#define all(a) (a).begin(),(a).end()
template<typename T>
ostream &operator<<(ostream &os, const vector< T > &v) {
for(int i=0; i<(int)v.size(); i++){
os << v[i] << (i+1 != (int)v.size() ? " " : "");
}
return os;
}
template<typename T>
istream &operator>>(istream &is, vector<T> &v){
for(T &in : v) is >> in;
return is;
}
template<typename T1, typename T2>
ostream &operator<<(ostream &os, const pair<T1, T2>& p) {
os << p.first << " " << p.second;
return os;
}
template<typename T1, typename T2>
istream &operator>>(istream &is, pair<T1, T2> &p) {
is >> p.first >> p.second;
return is;
}
template<class T>
vector<int> compress(vector<T> &v, int a = 0){
vector<T> w = v;
vector<int> ret(v.size());
sort(w.begin(), w.end());
w.erase(unique(w.begin(), w.end()), w.end());
for(int i=0; i<v.size(); i++){
ret[i] = lower_bound(w.begin(), w.end(), v[i]) - w.begin() + a;
}
return ret;
}
void Yes(bool a){
if(a) cout << "Yes\n";
else cout << "No\n";
}
template<class T> bool chmin(T& a, T b){
if(a > b){
a = b;
return true;
}
return false;
}
template<class T> bool chmax(T& a, T b){
if(a < b){
a = b;
return true;
}
return false;
}
template<class T> T power(T x, ll n) {
T ret = 1;
while (n > 0) {
if (n & 1) ret = ret * x/* % MOD*/;
x = x * x/* % MOD*/;
n >>= 1;
}
return ret;
}
ll round_up(ll a, ll b){
return (a + b - 1) / b;
}
ll gcd(ll a, ll b){
if(a % b == 0){
return(b);
}else{
return(gcd(b, a % b));
}
}
ll lcm(ll a, ll b){
return a / gcd(a, b) * b ;
}
int main(void){
//input
int i,j,k;
cin >> i >> j >> k;
//calculate
Yes(i <= j && i <= k);
}