結果

問題 No.1982 [Cherry 4th Tune B] 絶険
ユーザー xyz2606xyz2606
提出日時 2022-06-17 21:58:21
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
WA  
実行時間 -
コード長 5,910 bytes
コンパイル時間 3,104 ms
コンパイル使用メモリ 153,536 KB
実行使用メモリ 37,888 KB
最終ジャッジ日時 2024-04-17 13:50:13
合計ジャッジ時間 11,312 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 6 ms
19,928 KB
testcase_01 AC 7 ms
15,180 KB
testcase_02 AC 24 ms
31,168 KB
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
testcase_10 WA -
testcase_11 WA -
testcase_12 WA -
testcase_13 WA -
testcase_14 WA -
testcase_15 WA -
testcase_16 WA -
testcase_17 WA -
testcase_18 WA -
testcase_19 WA -
testcase_20 WA -
testcase_21 WA -
testcase_22 WA -
testcase_23 WA -
testcase_24 WA -
testcase_25 WA -
testcase_26 WA -
testcase_27 WA -
testcase_28 AC 135 ms
25,856 KB
testcase_29 WA -
testcase_30 AC 178 ms
27,920 KB
testcase_31 AC 151 ms
30,080 KB
testcase_32 WA -
testcase_33 WA -
testcase_34 WA -
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ソースコード

diff #

#include<vector>
#include<set>
#include<map>
#include<queue>
#include<string>
#include<algorithm>
#include<iostream>
#include<bitset>
#include<functional>
#include<chrono>
#include<numeric>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cassert>
#include<cmath>
#include<iomanip>
#include<random>
#include<ctime>
#include<complex>
#include<type_traits>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long LL;
typedef double D;
#define all(v) (v).begin(), (v).end()
mt19937 gene(chrono::system_clock::now().time_since_epoch().count());
typedef complex<double> Complex;
#define fi first
#define se second
#define ins insert
#define pb push_back
inline char GET_CHAR(){
    const int maxn = 131072;
    static char buf[maxn],*p1=buf,*p2=buf;
    return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++;
}
inline int getInt() {
    int res(0);
    char c = getchar();
    while(c < '0') c = getchar();
    while(c >= '0') {
        res = res * 10 + (c - '0');
        c = getchar();
    }
    return res;
}
inline LL fastpo(LL x, LL n, LL mod) {
    LL res(1);
    while(n) {
        if(n & 1) {
            res = res * (LL)x % mod;
        }
        x = x * (LL) x % mod;
        n /= 2;
    }
    return res;
}
template<LL mod> struct Num {
	LL a;
	Num operator + (const Num & b) { return Num{(a + b.a) % mod}; }
	Num operator - (const Num & b) { return Num{(a - b.a + mod) % mod}; }
	Num operator * (const Num & b) { return Num{a * b.a % mod}; }
	Num operator / (const Num & b) { return Num{a * fastpo(b.a, mod - 2, mod) % mod}; }
	void operator += (const Num & b) {if((a += b.a) >= mod) a -= mod;}
	void operator -= (const Num & b) {if((a -= b.a) < 0) a += mod;}
	void operator *= (const Num & b) { a = a * b.a % mod; }
	void operator /= (const Num & b) { a = a * fastpo(b.a, mod - 2, mod) % mod; }
	void operator = (const Num & b) { a = b.a; }
	void operator = (const LL & b) { a = b; }
};
template<LL mod> ostream & operator << (ostream & os, const Num<mod> & a) {
	os << a.a;
	return os;
}
LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; }

inline string itoa(LL x, int width = 0) {
	string res;
	if(x == 0) res.push_back('0');
	while(x) {
		res.push_back('0' + x % 10);
		x /= 10;
	}
	while((int)res.size() < width) res.push_back('0');
	reverse(res.begin(), res.end());
	return res;
}
const int _B = 131072;
char buf[_B];
int _bl = 0;
inline void flush() {
	fwrite(buf, 1, _bl, stdout);
	_bl = 0;
}
__inline void _putchar(char c) {
	if(_bl == _B) flush();
	buf[_bl++] = c;
}
inline void print(LL x, char c) {
	static char tmp[20];
	int l = 0;
	if(!x) tmp[l++] = '0';
	else {
		while(x) {
			tmp[l++] = x % 10 + '0';
			x /= 10;
		}
	}
	for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]);
	_putchar(c);
}
typedef double C;
struct P {
	C x, y;
	void scan() {
		double _x, _y;
		scanf("%lf%lf", &_x, &_y);
		x = _x; y = _y;
	}
	void print() {
		cout << '(' << x << ' ' << y << ')' << endl;
	}
	P operator + (const P & b) const { return P{x + b.x, y + b.y}; }
	P operator - (const P & b) const { return P{x - b.x, y - b.y}; }
	C operator * (const P & b) const { return x * b.y - y * b.x; }
	C operator % (const P & b) const { return x * b.x + y * b.y; }
};
P operator * (const C & x, const P & b) { return P{x * b.x, x * b.y}; }
const int N = 300033;
const int LOG = 20;
const int mod = 1e9 + 7;
const int inf = 1e9 + 7;
int n, m;
int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};
int rela[N];
int getr(int x) {
    int p = x;
    while(rela[p] != p) p = rela[p];
    int p1 = p; p = x;
    while(rela[p] != p) {
        int p2 = rela[p];
        rela[p] = p1;
        p = p2;
    }
    return p1;
}
int ans[N], l[N], r[N], c[N], h[N];
LL mn[N * 4];
LL delta[N * 4];
vector<pair<LL, int> > qu[N];
void pushdown(int k) {
	delta[k * 2] += delta[k];
	delta[k * 2 + 1] += delta[k];
	mn[k * 2] += delta[k];
	mn[k * 2 + 1] += delta[k];
	delta[k] = 0;
}
void collect(int k) {
	assert(delta[k] == 0);
	mn[k] = min(mn[k * 2], mn[k * 2 + 1]);
}
void build(int k, int le, int ri) {
	if(le == ri) {
		mn[k] = qu[le].back().fi;
	}else {
		int mid = (le + ri) / 2;
		build(k * 2, le, mid);
		build(k * 2 + 1, mid + 1, ri);
		collect(k);
	}
}
void fill(int k, int le, int ri, int ql, int qr, int col, int hei) {
	//cout << le << ' ' << ri << ' ' << col << ' ' << hei << endl;
	if(ql <= le && ri <= qr) {
		//cout << le << ' ' << ri << ' ' << col << ' ' << hei << endl;
		mn[k] -= hei;
		delta[k] -= hei;
		//cout << le << ' ' << mn[k] << endl;
	}else {
		int mid = (le + ri) / 2;
		pushdown(k);
		if(ql <= mid) fill(k * 2, le, mid, ql, qr, col, hei);
		if(qr >= mid + 1) fill(k * 2 + 1, mid + 1, ri, ql, qr, col, hei);
		collect(k);
		//cout << mn[k * 2 + 1] << ' ' << mn[k * 2] << ' ' << mn[k] << endl;
	}
}
int I;
void getmin(int k, int le, int ri) {
	if(mn[k] > 0) return; 
	if(le == ri) {
		while(mn[k] <= 0) {
			ans[qu[le].back().se] = I;
			mn[k] -= qu[le].back().fi;
			qu[le].pop_back();
			mn[k] += qu[le].back().fi;
		}
	}else {
		int mid = (le + ri) / 2;
		pushdown(k);
		getmin(k * 2, le, mid);
		getmin(k * 2 + 1, mid + 1, ri);
		collect(k);
	}
}
int main() {
	int n, k, q;
	scanf("%d%d%d", &n, &k, &q);
	for(int i = 1; i <= k; i++) {
		scanf("%d%d%d%d", &l[i], &r[i], &c[i], &h[i]);
	}
	for(int i = 1; i <= q; i++) {
		int x, y;
		scanf("%d%d", &x, &y);
		qu[x].pb({(LL)y, i});
	}
	for(int i = 1; i <= n; i++) {
		qu[i].pb({inf * (LL)inf, 0});
		sort(all(qu[i]));
		reverse(all(qu[i]));
	}
	for(int i = 1; i <= q; i++) {
		ans[i] = -1;
	}
	build(1, 1, n);
	//cout << mn[1] << endl;
	for(int i = 1; i <= k; i++) {
		I = c[i];
		fill(1, 1, n, l[i], r[i], c[i], h[i]);
		//cout << mn[1] << endl;
		getmin(1, 1, n);
	}
	for(int i = 1; i <= q; i++) {
		printf("%d\n", ans[i]);
	}
}





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