結果

問題 No.1984 [Cherry 4th Tune *] Dilemma
ユーザー milanis48663220
提出日時 2022-06-17 22:48:52
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 3 ms / 2,000 ms
コード長 3,136 bytes
コンパイル時間 1,947 ms
コンパイル使用メモリ 135,376 KB
最終ジャッジ日時 2025-01-29 22:30:25
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
other AC * 68
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <iostream>
#include <algorithm>
#include <iomanip>
#include <vector>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <tuple>
#include <cmath>
#include <numeric>
#include <functional>
#include <cassert>
#include <atcoder/maxflow>
#define debug_value(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << #x << "=" << x << endl;
#define debug(x) cerr << "line" << __LINE__ << ":<" << __func__ << ">:" << x << endl;
template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }
template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }
using namespace std;
typedef long long ll;
template<typename T>
vector<vector<T>> vec2d(int n, int m, T v){
return vector<vector<T>>(n, vector<T>(m, v));
}
template<typename T>
vector<vector<vector<T>>> vec3d(int n, int m, int k, T v){
return vector<vector<vector<T>>>(n, vector<vector<T>>(m, vector<T>(k, v)));
}
template<typename T>
void print_vector(vector<T> v, char delimiter=' '){
if(v.empty()) {
cout << endl;
return;
}
for(int i = 0; i+1 < v.size(); i++) cout << v[i] << delimiter;
cout << v.back() << endl;
}
const ll inf = 1e18;
using P = pair<string, int>;
const string Goal = "Goal";
const string Action = "Action";
const string Preparation = "Preparation";
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
cout << setprecision(10) << fixed;
int n, m, k, p; cin >> n >> m >> k >> p;
vector<ll> e(n);
vector<ll> f(m);
vector<ll> v(k);
for(int i = 0; i < n; i++) cin >> e[i];
for(int i = 0; i < m; i++) cin >> f[i];
for(int i = 0; i < k; i++) cin >> v[i];
auto goal_idx = [&](int i){
return i+1;
};
auto action_idx = [&](int j){
return j+n+1;
};
auto prepare_idx = [&](int k){
return k+n+m+1;
};
atcoder::mf_graph<ll> mf(n+m+k+2);
int s = 0, t = n+m+k+1;
for(int i = 0; i < n; i++) mf.add_edge(goal_idx(i), t, e[i]);
for(int j = 0; j < m; j++) mf.add_edge(s, action_idx(j), f[j]);
for(int kk = 0; kk < k; kk++) mf.add_edge(s, prepare_idx(kk), v[kk]);
for(int i = 0; i < n; i++){
int l; cin >> l;
for(int j = 0; j < l; j++){
int a; cin >> a; a--;
mf.add_edge(prepare_idx(a), goal_idx(i), inf);
}
}
for(int k = 0; k < p; k++){
int i, j; cin >> i >> j; i--; j--;
mf.add_edge(action_idx(j), goal_idx(i), inf);
}
ll ans = accumulate(e.begin(), e.end(), 0ll) + accumulate(f.begin(), f.end(), 0ll);
ans -= mf.flow(s, t);
cout << ans << endl;
auto reachable = mf.min_cut(s);
vector<P> order;
for(int kk = 0; kk < k; kk++){
if(!reachable[prepare_idx(kk)]) order.push_back(P(Preparation, kk));
}
for(int j = 0; j < m; j++){
if(reachable[action_idx(j)]) order.push_back(P(Action, j));
}
for(int i = 0; i < n; i++){
if(!reachable[goal_idx(i)]) order.push_back(P(Goal, i));
}
cout << order.size() << endl;
for(auto [kind, idx]: order) cout << kind << ' ' << idx+1 << endl;
}
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