結果

問題 No.1984 [Cherry 4th Tune *] Dilemma
ユーザー sotanishy
提出日時 2022-06-17 23:20:00
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 3,327 bytes
コンパイル時間 457 ms
コンパイル使用メモリ 82,176 KB
実行使用メモリ 78,208 KB
最終ジャッジ日時 2024-11-08 14:05:04
合計ジャッジ時間 11,416 ms
ジャッジサーバーID
(参考情報)
judge1 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 42 WA * 26
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ソースコード

diff #
プレゼンテーションモードにする

import sys
input = sys.stdin.readline
class Dinic:
class Edge:
def __init__(self, v, cap, rev):
self.v = v
self.cap = cap
self.rev = rev
def __init__(self, V):
self.V = V
self.G = [[] for _ in range(V)]
def add_edge(self, u, v, cap):
self.G[u].append(self.Edge(v, cap, len(self.G[v])))
self.G[v].append(self.Edge(u, 0, len(self.G[u])-1))
# calculate the shortest distance from s
def bfs(self, s):
from collections import deque
self.level = [-1] * self.V
self.level[s] = 0
queue = deque()
queue.append(s)
while queue:
u = queue.popleft()
for e in self.G[u]:
if e.cap > 0 and self.level[e.v] == -1:
self.level[e.v] = self.level[u] + 1
queue.append(e.v)
# find a path
def dfs(self, u, t, f):
if u == t:
return f
i = self.iter[u]
while i < len(self.G[u]):
e = self.G[u][i]
if e.cap > 0 and self.level[u] < self.level[e.v]:
d = self.dfs(e.v, t, min(f, e.cap))
if d > 0:
e.cap -= d
self.G[e.v][e.rev].cap += d
return d
i += 1
self.iter[u] += 1
return 0
# find the max flow from s to v
def max_flow(self, s, t):
flow = 0
INF = 10**18
while True:
self.bfs(s)
if self.level[t] == -1:
return flow
self.iter = [0] * self.V
while True:
f = self.dfs(s, t, INF)
if f == 0:
break
flow += f
def min_cut(self, s):
visited = [False] * self.V
st = [s]
visited[s] = True
while st:
u = st.pop()
for e in self.G[u]:
if e.cap > 0 and not visited[e.v]:
visited[e.v] = True
st.append(e.v)
return visited
N, M, K, P = map(int, input().split())
E = list(map(int, input().split()))
F = list(map(int, input().split()))
V = list(map(int, input().split()))
flow = Dinic(N+M+K+2)
s = N+M+K
t = s+1
ans = 0
for i in range(N):
flow.add_edge(s, i, E[i])
flow.add_edge(i, t, 0)
ans += E[i]
for i in range(M):
flow.add_edge(s, N+i, 0)
flow.add_edge(N+i, t, F[i])
ans += F[i]
for i in range(K):
flow.add_edge(s, N+M+i, 0)
flow.add_edge(N+M+i, t, V[i])
for i in range(N):
_, *A = list(map(int, input().split()))
for a in A:
a -= 1
flow.add_edge(i, N+M+a, 10**18)
for i in range(P):
I, J = map(int, input().split())
I -= 1
J -= 1
flow.add_edge(I, N+J, 10**18)
flow.add_edge(N+J, I, 10**18)
ans -= flow.max_flow(s, t)
use = flow.min_cut(s)
goals = []
actions = []
preps = []
for i in range(N+M+K):
if i < N:
if use[i]:
goals.append(i+1)
elif i < N+M:
if not use[i]:
actions.append(i-N+1)
else:
if use[i]:
preps.append(i-N-M+1)
print(ans)
print(len(goals) + len(actions) + len(preps))
for i in preps:
print("Preparation", i)
for i in goals:
print("Goal", i)
for i in actions:
print("Action", i)
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