結果

問題 No.1984 [Cherry 4th Tune *] Dilemma
ユーザー sotanishy
提出日時 2022-06-17 23:22:41
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 110 ms / 2,000 ms
コード長 3,293 bytes
コンパイル時間 229 ms
コンパイル使用メモリ 82,304 KB
実行使用メモリ 77,952 KB
最終ジャッジ日時 2024-11-08 14:05:15
合計ジャッジ時間 10,398 ms
ジャッジサーバーID
(参考情報)
judge3 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
other AC * 68
権限があれば一括ダウンロードができます

ソースコード

diff #

import sys
input = sys.stdin.readline

class Dinic:
    class Edge:
        def __init__(self, v, cap, rev):
            self.v = v
            self.cap = cap
            self.rev = rev

    def __init__(self, V):
        self.V = V
        self.G = [[] for _ in range(V)]

    def add_edge(self, u, v, cap):
        self.G[u].append(self.Edge(v, cap, len(self.G[v])))
        self.G[v].append(self.Edge(u, 0, len(self.G[u])-1))

    # calculate the shortest distance from s
    def bfs(self, s):
        from collections import deque

        self.level = [-1] * self.V
        self.level[s] = 0
        queue = deque()
        queue.append(s)
        while queue:
            u = queue.popleft()
            for e in self.G[u]:
                if e.cap > 0 and self.level[e.v] == -1:
                    self.level[e.v] = self.level[u] + 1
                    queue.append(e.v)

    # find a path
    def dfs(self, u, t, f):
        if u == t:
            return f
        i = self.iter[u]
        while i < len(self.G[u]):
            e = self.G[u][i]
            if e.cap > 0 and self.level[u] < self.level[e.v]:
                d = self.dfs(e.v, t, min(f, e.cap))
                if d > 0:
                    e.cap -= d
                    self.G[e.v][e.rev].cap += d
                    return d
            i += 1
            self.iter[u] += 1
        return 0

    # find the max flow from s to v
    def max_flow(self, s, t):
        flow = 0
        INF = 10**18
        while True:
            self.bfs(s)
            if self.level[t] == -1:
                return flow
            self.iter = [0] * self.V
            while True:
                f = self.dfs(s, t, INF)
                if f == 0:
                    break
                flow += f

    def min_cut(self, s):
        visited = [False] * self.V
        st = [s]
        visited[s] = True
        while st:
            u = st.pop()
            for e in self.G[u]:
                if e.cap > 0 and not visited[e.v]:
                    visited[e.v] = True
                    st.append(e.v)
        return visited



N, M, K, P = map(int, input().split())
E = list(map(int, input().split()))
F = list(map(int, input().split()))
V = list(map(int, input().split()))
flow = Dinic(N+M+K+2)
s = N+M+K
t = s+1
ans = 0
for i in range(N):
    flow.add_edge(s, i, E[i])
    flow.add_edge(i, t, 0)
    ans += E[i]
for i in range(M):
    flow.add_edge(s, N+i, 0)
    flow.add_edge(N+i, t, F[i])
    ans += F[i]
for i in range(K):
    flow.add_edge(s, N+M+i, 0)
    flow.add_edge(N+M+i, t, V[i])
for i in range(N):
    _, *A = list(map(int, input().split()))
    for a in A:
        a -= 1
        flow.add_edge(i, N+M+a, 10**18)
for i in range(P):
    I, J = map(int, input().split())
    I -= 1
    J -= 1
    flow.add_edge(I, N+J, 10**18)
ans -= flow.max_flow(s, t)
use = flow.min_cut(s)
goals = []
actions = []
preps = []
for i in range(N+M+K):
    if i < N:
        if use[i]:
            goals.append(i+1)
    elif i < N+M:
        if not use[i]:
            actions.append(i-N+1)
    else:
        if use[i]:
            preps.append(i-N-M+1)
print(ans)
print(len(goals) + len(actions) + len(preps))
for i in preps:
    print("Preparation", i)
for i in goals:
    print("Goal", i)
for i in actions:
    print("Action", i)
0