結果
| 問題 |
No.1983 [Cherry 4th Tune C] 南の島のマーメイド
|
| コンテスト | |
| ユーザー |
lilictaka
|
| 提出日時 | 2022-06-20 12:48:53 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 2,324 ms / 4,000 ms |
| コード長 | 4,467 bytes |
| コンパイル時間 | 543 ms |
| コンパイル使用メモリ | 82,516 KB |
| 実行使用メモリ | 312,664 KB |
| 最終ジャッジ日時 | 2024-10-13 00:34:25 |
| 合計ジャッジ時間 | 40,895 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 41 |
ソースコード
from collections import defaultdict,deque
class UnionFind():
def __init__(self, n):
self.n = n
self.parents = [-1] * n
def find(self, x):
if self.parents[x] < 0:
return x
else:
self.parents[x] = self.find(self.parents[x])
return self.parents[x]
def union(self, x, y):
x = self.find(x)
y = self.find(y)
if x == y:
return
if self.parents[x] > self.parents[y]:
x, y = y, x
self.parents[x] += self.parents[y]
self.parents[y] = x
def size(self, x):
return -self.parents[self.find(x)]
def same(self, x, y):
return self.find(x) == self.find(y)
def members(self, x):
root = self.find(x)
return [i for i in range(self.n) if self.find(i) == root]
def roots(self):
return [i for i, x in enumerate(self.parents) if x < 0]
def group_count(self):
return len(self.roots())
def all_group_members(self):
group_members = defaultdict(list)
for member in range(self.n):
group_members[self.find(member)].append(member)
return group_members
def __str__(self):
return '\n'.join(f'{r}: {m}' for r, m in self.all_group_members().items())
def scc_decomposition(G):
n = len(G)
G_rev = [[] for _ in range(n)]
for u in range(n):
for v in G[u]:
G_rev[v].append(u)
# dfs
vs = []
visited = [False] * n
used = [False] * n
for u in range(n):
if visited[u]:
continue
stack = [u]
while stack:
v = stack.pop()
if used[v]:
continue
if not visited[v]:
visited[v] = True
else:
vs.append(v)
used[v] = True
continue
stack.append(v)
for c in G[v]:
if not visited[c]:
stack.append(c)
# reverse dfs
visited = [False] * n
component = [-1] * n
k = 0
for u in vs[::-1]:
if visited[u]:
continue
stack = [u]
while stack:
v = stack.pop()
visited[v] = True
component[v] = k
for c in G_rev[v]:
if not visited[c]:
stack.append(c)
k += 1
return component
# 強連結成分分解(SCC): グラフGに対するSCCを行う
# 入力: <N>: 頂点サイズ, <G>: 順方向の有向グラフ, <RG>: 逆方向の有向グラフ
# 出力: (<ラベル数>, <各頂点のラベル番号>)
def scc(N, G, RG):
order = []
used = [0]*N
group = [None]*N
def dfs(s):
used[s] = 1
for t in G[s]:
if not used[t]:
dfs(t)
order.append(s)
def rdfs(s, col):
group[s] = col
used[s] = 1
for t in RG[s]:
if not used[t]:
rdfs(t, col)
for i in range(N):
if not used[i]:
dfs(i)
used = [0]*N
label = 0
for s in reversed(order):
if not used[s]:
rdfs(s, label)
label += 1
return label, group
N,M,Q = map(int,input().split())
G0 = [[] for _ in range(N)]
for _ in range(M):
u,v = map(lambda x:int(x)-1,input().split())
G0[u].append(v)
G0[v].append(u)
query = []
for _ in range(Q):
x,y = map(lambda x:int(x)-1,input().split())
query.append((x,y))
cmp = scc_decomposition(G0)
cmpmemo = defaultdict(list)
for i in range(N):
cmpmemo[cmp[i]].append(i)
G = [[] for _ in range(N)]
RG = [[] for _ in range(N)]
seen = [0] * N
for key in cmpmemo.keys():
st = cmpmemo[key][0]
q = deque()
q.append((st,-1))
while q:
now,back = q.popleft()
if back != -1:
G[back].append(now)
RG[now].append(back)
if seen[now]:
continue
seen[now] += 1
for nx in G0[now]:
if nx == back:
continue
if seen[nx] <= 1:
q.appendleft((nx,now))
cmp = scc_decomposition(G)
cnt = defaultdict(int)
for i in range(N):
cnt[cmp[i]] += 1
uf = UnionFind(N)
G0set = [set() for _ in range(N)]
for u in range(N):
for v in G0[u]:
G0set[u].add(v)
if cmp[u] == cmp[v]:
continue
uf.union(u,v)
for x,y in query:
if uf.same(x,y):
print('Yes')
else:
print('No')
lilictaka