結果

問題 No.1998 Manhattan Restaurant
ユーザー xyz2606xyz2606
提出日時 2022-07-01 22:40:38
言語 C++14
(gcc 13.2.0 + boost 1.83.0)
結果
AC  
実行時間 112 ms / 2,000 ms
コード長 5,396 bytes
コンパイル時間 2,899 ms
コンパイル使用メモリ 144,904 KB
実行使用メモリ 10,640 KB
最終ジャッジ日時 2023-08-17 10:13:52
合計ジャッジ時間 4,815 ms
ジャッジサーバーID
（参考情報） 		judge11 / judge14
このコードへのチャレンジ（β）

テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 3 ms
9,652 KB
testcase_01 AC 3 ms
9,724 KB
testcase_02 AC 2 ms
9,668 KB
testcase_03 AC 2 ms
9,880 KB
testcase_04 AC 2 ms
9,876 KB
testcase_05 AC 2 ms
9,752 KB
testcase_06 AC 3 ms
9,660 KB
testcase_07 AC 2 ms
9,620 KB
testcase_08 AC 3 ms
9,656 KB
testcase_09 AC 3 ms
9,656 KB
testcase_10 AC 2 ms
9,748 KB
testcase_11 AC 2 ms
9,724 KB
testcase_12 AC 2 ms
9,532 KB
testcase_13 AC 2 ms
9,676 KB
testcase_14 AC 2 ms
9,592 KB
testcase_15 AC 112 ms
10,356 KB
testcase_16 AC 29 ms
10,076 KB
testcase_17 AC 38 ms
10,188 KB
testcase_18 AC 29 ms
10,216 KB
testcase_19 AC 31 ms
10,216 KB
testcase_20 AC 111 ms
10,640 KB
testcase_21 AC 111 ms
10,368 KB
testcase_22 AC 111 ms
10,488 KB
testcase_23 AC 110 ms
10,340 KB
testcase_24 AC 110 ms
10,352 KB
testcase_25 AC 5 ms
9,608 KB
testcase_26 AC 31 ms
10,036 KB
testcase_27 AC 21 ms
9,852 KB
testcase_28 AC 31 ms
10,116 KB
testcase_29 AC 22 ms
9,900 KB
testcase_30 AC 45 ms
10,260 KB
testcase_31 AC 42 ms
10,200 KB
testcase_32 AC 6 ms
9,796 KB
testcase_33 AC 28 ms
10,144 KB
testcase_34 AC 34 ms
10,244 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<vector>
#include<set>
#include<map>
#include<queue>
#include<string>
#include<algorithm>
#include<iostream>
#include<bitset>
#include<functional>
#include<chrono>
#include<numeric>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cassert>
#include<cmath>
#include<iomanip>
#include<random>
#include<ctime>
#include<complex>
#include<type_traits>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long LL;
typedef double D;
#define all(v) (v).begin(), (v).end()
mt19937 gene(chrono::system_clock::now().time_since_epoch().count());
typedef complex<double> Complex;
#define fi first
#define se second
#define ins insert
#define pb push_back
inline char GET_CHAR(){
    const int maxn = 131072;
    static char buf[maxn],*p1=buf,*p2=buf;
    return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++;
}
inline int getInt() {
    int res(0);
    char c = getchar();
    while(c < '0') c = getchar();
    while(c >= '0') {
        res = res * 10 + (c - '0');
        c = getchar();
    }
    return res;
}
inline LL fastpo(LL x, LL n, LL mod) {
    LL res(1);
    while(n) {
        if(n & 1) {
            res = res * (LL)x % mod;
        }
        x = x * (LL) x % mod;
        n /= 2;
    }
    return res;
}
template<LL mod> struct Num {
	LL a;
	Num operator + (const Num & b) { return Num{(a + b.a) % mod}; }
	Num operator - (const Num & b) { return Num{(a - b.a + mod) % mod}; }
	Num operator * (const Num & b) { return Num{a * b.a % mod}; }
	Num operator / (const Num & b) { return Num{a * fastpo(b.a, mod - 2, mod) % mod}; }
	void operator += (const Num & b) {if((a += b.a) >= mod) a -= mod;}
	void operator -= (const Num & b) {if((a -= b.a) < 0) a += mod;}
	void operator *= (const Num & b) { a = a * b.a % mod; }
	void operator /= (const Num & b) { a = a * fastpo(b.a, mod - 2, mod) % mod; }
	void operator = (const Num & b) { a = b.a; }
	void operator = (const LL & b) { a = b; }
};
template<LL mod> ostream & operator << (ostream & os, const Num<mod> & a) {
	os << a.a;
	return os;
}
LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; }

inline string itoa(LL x, int width = 0) {
	string res;
	if(x == 0) res.push_back('0');
	while(x) {
		res.push_back('0' + x % 10);
		x /= 10;
	}
	while((int)res.size() < width) res.push_back('0');
	reverse(res.begin(), res.end());
	return res;
}
const int _B = 131072;
char buf[_B];
int _bl = 0;
inline void flush() {
	fwrite(buf, 1, _bl, stdout);
	_bl = 0;
}
__inline void _putchar(char c) {
	if(_bl == _B) flush();
	buf[_bl++] = c;
}
inline void print(LL x, char c) {
	static char tmp[20];
	int l = 0;
	if(!x) tmp[l++] = '0';
	else {
		while(x) {
			tmp[l++] = x % 10 + '0';
			x /= 10;
		}
	}
	for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]);
	_putchar(c);
}
typedef double C;
struct P {
	C x, y;
	void scan() {
		double _x, _y;
		scanf("%lf%lf", &_x, &_y);
		x = _x; y = _y;
	}
	void print() {
		cout << '(' << x << ' ' << y << ')' << endl;
	}
	P operator + (const P & b) const { return P{x + b.x, y + b.y}; }
	P operator - (const P & b) const { return P{x - b.x, y - b.y}; }
	C operator * (const P & b) const { return x * b.y - y * b.x; }
	C operator % (const P & b) const { return x * b.x + y * b.y; }
};
P operator * (const C & x, const P & b) { return P{x * b.x, x * b.y}; }
const int N = 300033;
const int LOG = 20;
const int mod = 1e9 + 7;
const int inf = 1e9 + 7;
int n, m;
int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};
int rela[N];
int getr(int x) {
    int p = x;
    while(rela[p] != p) p = rela[p];
    int p1 = p; p = x;
    while(rela[p] != p) {
        int p2 = rela[p];
        rela[p] = p1;
        p = p2;
    }
    return p1;
}
LL x[N], y[N], a[N], b[N];
int main() {
	int n;
	scanf("%d", &n);
	for(int i = 1; i <= n; i++) {
		scanf("%lld%lld", &x[i], &y[i]);
		a[i] = x[i] + y[i];
		b[i] = x[i] - y[i];
	}
	LL le = 0, ri = (LL)inf * 2;
	while(le != ri) {
		LL mid = (le + ri) / 2;
		LL mna = (LL)inf * 4;
		for(int i = 1; i <= n; i++) {
			mna = min(mna, a[i]);
		}
		LL mnb = (LL)inf * 4, mxb = inf * -4ll;
		for(int i = 1; i <= n; i++) {
			if(a[i] <= mna + mid * 2) {
				mnb = min(mnb, b[i]);
				mxb = max(mxb, b[i]);
			}
		}
		//cout << mid << ' ' << mna << ' ' << mnb << endl;
		LL mna2 = inf * 4ll, mnb2 = inf * 4ll;
		for(int i = 1; i <= n; i++) {
			if(a[i] <= mna + mid * 2 && b[i] <= mnb + mid * 2) {
			
			}else {
				mna2 = min(mna2, a[i]);
				mnb2 = min(mnb2, b[i]);
			}
		}
		bool flag = true;
		for(int i = 1; i <= n; i++) {
			if(a[i] <= mna + mid * 2 && b[i] <= mnb + mid * 2) {
			
			}else if(a[i] >= mna2 && a[i] <= mna2 + mid * 2 && b[i] >= mnb2 && b[i] <= mnb2 + mid * 2) {
			}else {
				flag = false;
			}
		}

		LL mna3 = inf * 4ll, mnb3 = inf * 4ll;
		for(int i = 1; i <= n; i++) {
			if(a[i] <= mna + mid * 2 && b[i] >= mxb - mid * 2) {
			
			}else {
				mna3 = min(mna3, a[i]);
				mnb3 = min(mnb3, b[i]);
			}
		}
		bool f1 = true;
		for(int i = 1; i <= n; i++) {
			if(a[i] <= mna + mid * 2 && b[i] >= mxb - mid * 2) {
			
			}else if(a[i] >= mna3 && a[i] <= mna3 + mid * 2 && b[i] >= mnb3 && b[i] <= mnb3 + mid * 2) {
			}else {
				f1 = false;
			}
		}
		if(flag == false && f1 == false) {
			le = mid + 1;
		}else ri = mid;
	}
	cout << le << endl;
}
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