結果

問題 No.1999 Lattice Teleportation
ユーザー xyz2606xyz2606
提出日時 2022-07-01 22:59:56
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 119 ms / 2,000 ms
コード長 4,792 bytes
コンパイル時間 1,407 ms
コンパイル使用メモリ 148,868 KB
実行使用メモリ 8,188 KB
最終ジャッジ日時 2024-11-26 06:39:03
合計ジャッジ時間 3,734 ms
ジャッジサーバーID
(参考情報)
judge4 / judge3
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
6,820 KB
testcase_01 AC 1 ms
6,816 KB
testcase_02 AC 2 ms
6,816 KB
testcase_03 AC 2 ms
6,820 KB
testcase_04 AC 2 ms
6,820 KB
testcase_05 AC 3 ms
6,820 KB
testcase_06 AC 3 ms
6,816 KB
testcase_07 AC 3 ms
6,816 KB
testcase_08 AC 3 ms
6,820 KB
testcase_09 AC 2 ms
6,820 KB
testcase_10 AC 2 ms
6,820 KB
testcase_11 AC 3 ms
6,816 KB
testcase_12 AC 57 ms
8,100 KB
testcase_13 AC 113 ms
7,656 KB
testcase_14 AC 2 ms
6,816 KB
testcase_15 AC 116 ms
6,816 KB
testcase_16 AC 44 ms
6,816 KB
testcase_17 AC 73 ms
7,760 KB
testcase_18 AC 66 ms
7,760 KB
testcase_19 AC 71 ms
6,816 KB
testcase_20 AC 119 ms
8,064 KB
testcase_21 AC 115 ms
7,760 KB
testcase_22 AC 117 ms
8,188 KB
testcase_23 AC 8 ms
6,816 KB
testcase_24 AC 29 ms
6,816 KB
testcase_25 AC 64 ms
6,820 KB
testcase_26 AC 54 ms
6,820 KB
testcase_27 AC 45 ms
6,820 KB
testcase_28 AC 77 ms
7,628 KB
testcase_29 AC 37 ms
6,820 KB
testcase_30 AC 17 ms
6,820 KB
testcase_31 AC 13 ms
6,820 KB
testcase_32 AC 48 ms
7,636 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include<vector>
#include<set>
#include<map>
#include<queue>
#include<string>
#include<algorithm>
#include<iostream>
#include<bitset>
#include<functional>
#include<chrono>
#include<numeric>
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cassert>
#include<cmath>
#include<iomanip>
#include<random>
#include<ctime>
#include<complex>
#include<type_traits>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
typedef long long LL;
typedef double D;
#define all(v) (v).begin(), (v).end()
mt19937 gene(chrono::system_clock::now().time_since_epoch().count());
typedef complex<double> Complex;
#define fi first
#define se second
#define ins insert
#define pb push_back
inline char GET_CHAR(){
    const int maxn = 131072;
    static char buf[maxn],*p1=buf,*p2=buf;
    return p1==p2&&(p2=(p1=buf)+fread(buf,1,maxn,stdin),p1==p2)?EOF:*p1++;
}
inline int getInt() {
    int res(0);
    char c = getchar();
    while(c < '0') c = getchar();
    while(c >= '0') {
        res = res * 10 + (c - '0');
        c = getchar();
    }
    return res;
}
inline LL fastpo(LL x, LL n, LL mod) {
    LL res(1);
    while(n) {
        if(n & 1) {
            res = res * (LL)x % mod;
        }
        x = x * (LL) x % mod;
        n /= 2;
    }
    return res;
}
template<LL mod> struct Num {
	LL a;
	Num operator + (const Num & b) { return Num{(a + b.a) % mod}; }
	Num operator - (const Num & b) { return Num{(a - b.a + mod) % mod}; }
	Num operator * (const Num & b) { return Num{a * b.a % mod}; }
	Num operator / (const Num & b) { return Num{a * fastpo(b.a, mod - 2, mod) % mod}; }
	void operator += (const Num & b) {if((a += b.a) >= mod) a -= mod;}
	void operator -= (const Num & b) {if((a -= b.a) < 0) a += mod;}
	void operator *= (const Num & b) { a = a * b.a % mod; }
	void operator /= (const Num & b) { a = a * fastpo(b.a, mod - 2, mod) % mod; }
	void operator = (const Num & b) { a = b.a; }
	void operator = (const LL & b) { a = b; }
};
template<LL mod> ostream & operator << (ostream & os, const Num<mod> & a) {
	os << a.a;
	return os;
}
LL gcd(LL a, LL b) { return b ? gcd(b, a % b) : a; }

inline string itoa(LL x, int width = 0) {
	string res;
	if(x == 0) res.push_back('0');
	while(x) {
		res.push_back('0' + x % 10);
		x /= 10;
	}
	while((int)res.size() < width) res.push_back('0');
	reverse(res.begin(), res.end());
	return res;
}
const int _B = 131072;
char buf[_B];
int _bl = 0;
inline void flush() {
	fwrite(buf, 1, _bl, stdout);
	_bl = 0;
}
__inline void _putchar(char c) {
	if(_bl == _B) flush();
	buf[_bl++] = c;
}
inline void print(LL x, char c) {
	static char tmp[20];
	int l = 0;
	if(!x) tmp[l++] = '0';
	else {
		while(x) {
			tmp[l++] = x % 10 + '0';
			x /= 10;
		}
	}
	for(int i = l - 1; i >= 0; i--) _putchar(tmp[i]);
	_putchar(c);
}
typedef LL C;
const int N = 300033;
const int mod = 1e9 + 7;
struct P {
	C x, y;
	void scan() {
		scanf("%lld%lld", &x, &y);
	}
	void print() {
		cout << '(' << x << ' ' << y << ')' << endl;
	}
	P operator + (const P & b) const { return P{x + b.x, y + b.y}; }
	P operator - (const P & b) const { return P{x - b.x, y - b.y}; }
	C operator * (const P & b) const { return x * b.y - y * b.x; }
	C operator % (const P & b) const { return ((LL)x % mod * (b.y % mod) - (LL)(y % mod) * (b.x % mod)) % mod; }
	int d() const { return (x < 0 || x == 0 && y < 0) ? 1 : 0; }
} a[N];
P operator * (const C & x, const P & b) { return P{x * b.x, x * b.y}; }
bool operator < (const P & a, const P & b) {
	if(a.d() != b.d()) {
		return a.d() < b.d();
	}else return a * b < 0;
}
const int LOG = 20;
const int inf = 1e9 + 7;
int n, m;
int dx[4] = {1, 0, -1, 0};
int dy[4] = {0, 1, 0, -1};
int rela[N];
int getr(int x) {
    int p = x;
    while(rela[p] != p) p = rela[p];
    int p1 = p; p = x;
    while(rela[p] != p) {
        int p2 = rela[p];
        rela[p] = p1;
        p = p2;
    }
    return p1;
}
int main() {
	int n;
	scanf("%d", &n);
	int np = 0;
	for(int i = 1; i <= n; i++) {
		P x;
		x.scan();
		if(x.x != 0 || x.y != 0) {
			a[++np] = x;
			a[++np] = -1 * x;
		}
	}
	n = np;
	sort(a + 1, a + 1 + n);
	LL ans = 0;
	for(int i = 1; i <= n; i++) {
		a[i] = a[i - 1] + a[i];
	}
	LL cnt = 0;
	for(int i = 0; i <= n; i++) {
		ans = ans + (a[i] % a[(i + 1) % (n + 1)]);
		ans = ans % mod;
		LL x = abs(a[i].x - a[(i + 1) %(n + 1)].x);
		LL y = abs(a[i].y - a[(i + 1) %(n + 1)].y);
		cnt += gcd(x, y) % mod;
		cnt %= mod;
	}
	//cout << ans << ' ' << cnt << endl;
	ans = (ans + mod) % mod;
	cnt = (cnt + mod) % mod;
	ans = (mod - ans) % mod;
	ans = ((LL)ans * (mod + 1) / 2) % mod;
	cnt = ((LL)cnt * (mod + 1) / 2) % mod;
	
	cout << (ans + 1ll + cnt) % mod << endl;
}





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