結果

問題 No.1058 素敵な数
ユーザー McGregorshMcGregorsh
提出日時 2022-07-08 14:20:37
言語 PyPy3
(7.3.15)
結果
WA  
実行時間 -
コード長 3,380 bytes
コンパイル時間 324 ms
コンパイル使用メモリ 87,060 KB
実行使用メモリ 93,592 KB
最終ジャッジ日時 2023-08-27 07:38:53
合計ジャッジ時間 3,493 ms
ジャッジサーバーID
(参考情報)
judge13 / judge12
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 234 ms
93,484 KB
testcase_01 AC 230 ms
93,592 KB
testcase_02 AC 229 ms
93,336 KB
testcase_03 WA -
testcase_04 WA -
testcase_05 WA -
testcase_06 WA -
testcase_07 WA -
testcase_08 WA -
testcase_09 WA -
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ソースコード

diff #

###N以上K以下の素数列挙###

import math

def segment_sieve(a, b):
	  sqrt_b = math.ceil(math.sqrt(b))
	  prime_small = [True for i in range(sqrt_b)]
	  prime = [True for i in range(b-a+1)]
	  
	  for i in range(2, sqrt_b):
	  	  if prime_small[i]:
	  	  	  for j in range(2*i, sqrt_b, i):
	  	  	  	  prime_small[j] = False
	  	  	  for j in range((a+i-1)//i*i, b+1, i):
	  	  	  	  #print('j: ', j)
	  	  	  	  prime[j-a] = False
	  return prime


###n進数から10進数変換###

def base_10(num_n,n):
	  num_10 = 0
	  for s in str(num_n):
	  	  num_10 *= n
	  	  num_10 += int(s)
	  return num_10


###10進数からn進数変換###

def base_n(num_10,n):
	  str_n = ''
	  while num_10:
	  	  if num_10%n>=10:
	  	  	  return -1
	  	  str_n += str(num_10%n)
	  	  num_10 //= n
	  return int(str_n[::-1])


###複数の数の最大公約数、最小公倍数###

from functools import reduce

# 最大公約数
def gcd_list(num_list: list) -> int:
	  return reduce(gcd, num_list)

# 最小公倍数
def lcm_base(x: int, y: int) -> int:
	  return (x * y) // gcd(x, y)
def lcm_list(num_list: list):
	  return reduce(lcm_base, num_list, 1)


###約数列挙###

def make_divisors(n):
	  lower_divisors, upper_divisors = [], []
	  i = 1
	  while i * i <= n:
	  	  if n % i == 0:
	  	  	  lower_divisors.append(i)
	  	  	  if i != n // i:
	  	  	  	  upper_divisors.append(n//i)
	  	  i += 1
	  return lower_divisors + upper_divisors[::-1]


###順列###

def nPr(n, r):
	  npr = 1
	  for i in range(n, n-r, -1):
	  	  npr *= i
	  return npr


###組合せ###

def nCr(n, r):
	  factr = 1
	  r = min(r, n - r)
	  for i in range(r, 1, -1):
	  	  factr *= i
	  return nPr(n, r)/factr



import sys, re
from math import ceil, floor, sqrt, pi, factorial, gcd
from copy import deepcopy
from collections import Counter, deque, defaultdict
from heapq import heapify, heappop, heappush
from itertools import accumulate, product, combinations, combinations_with_replacement, permutations
from bisect import bisect, bisect_left, bisect_right
from functools import reduce
from decimal import Decimal, getcontext
def i_input(): return int(input())
def i_map(): return map(int, input().split())
def i_list(): return list(i_map())
def i_row(N): return [i_input() for _ in range(N)]
def i_row_list(N): return [i_list() for _ in range(N)]
def s_input(): return input()
def s_map(): return input().split()
def s_list(): return list(s_map())
def s_row(N): return [s_input for _ in range(N)]
def s_row_str(N): return [s_list() for _ in range(N)]
def s_row_list(N): return [list(s_input()) for _ in range(N)]
def lcm(a, b): return a * b // gcd(a, b)
def get_distance(x1, y1, x2, y2):
	  d = sqrt((x2 - x1) ** 2 + (y2 - y1) ** 2)
	  return d
def rotate(table):
   	  n_fild = []
   	  for x in zip(*table[::-1]):
   	  	  n_fild.append(x)
   	  return n_fild
sys.setrecursionlimit(10 ** 7)
INF = float('inf')
MOD = 10 ** 9 + 7
MOD2 = 998244353


###関数コピーしたか?###
def main():
   
   n = int(input())
   
   nums = []
   bilion = segment_sieve(10**5, 10**5+5000)
   for i in range(len(bilion)):
   	  if bilion[i]:
   	  	  nums.append(i+10**5)
   	  if len(nums) == 100:
   	  	  break
   
   ans = [1]
   for i in range(100):
   	  for j in range(100):
   	  	  ans.append(nums[i] * nums[j])
   ans.sort()
   
   print(ans[n-1])
   
   
if __name__ == '__main__':
    main()

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