結果
問題 | No.1035 Color Box |
ユーザー |
|
提出日時 | 2022-07-11 11:35:33 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 58 ms / 2,000 ms |
コード長 | 2,518 bytes |
コンパイル時間 | 1,966 ms |
コンパイル使用メモリ | 197,648 KB |
最終ジャッジ日時 | 2025-01-30 06:23:59 |
ジャッジサーバーID (参考情報) |
judge4 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 36 |
ソースコード
#include <bits/stdc++.h>using namespace std;using ll = long long;using vll = vector<ll>;using vvll = vector<vll>;using vvvll = vector<vvll>;using vvvvll = vector<vvvll>;using vb = vector<bool>;using vvb = vector<vb>;using vvvb = vector<vvb>;using vvvvb = vector<vvvb>;using vd = vector<double>;using vvd = vector<vd>;using vvvd = vector<vvd>;#define all(A) A.begin(),A.end()#define ALL(A) A.begin(),A.end()#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)using pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;template<class T>bool chmax(T& p, T q, bool C = 1) {if (C == 0 && p == q) {return 1;}if (p < q) {p = q;return 1;}else {return 0;}}template<class T>bool chmin(T& p, T q, bool C = 1) {if (C == 0 && p == q) {return 1;}if (p > q) {p = q;return 1;}else {return 0;}}ll gcd(ll(a), ll(b)) {if (b == 0)return a;ll c = a;while (a % b != 0) {c = a % b;a = b;b = c;}return b;}ll modPow(long long a, long long n, long long p = 1e9 + 7) {if (n == 0) return 1; // 0乗にも対応する場合if (n == 1) return a % p;if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;long long t = modPow(a, n / 2, p);return (t * t) % p;}vector<ll> fact, factinv, inv;ll mod = 1e9 + 7;void prenCkModp(ll n) {fact.resize(n + 5);factinv.resize(n + 5);inv.resize(n + 5);fact.at(0) = fact.at(1) = 1;factinv.at(0) = factinv.at(1) = 1;inv.at(1) = 1;for (ll i = 2; i < n + 5; i++) {fact.at(i) = (fact.at(i - 1) * i) % mod;inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;}}ll nCk(ll n, ll k) {if (n < k) return 0;return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;}int main() {cin.tie(nullptr);ios::sync_with_stdio(false);ll N, M;cin >> N >> M;prenCkModp(100000);ll an = 0;for (ll m = M; m > 0; m--) {ll p = 1;if ((M - m) % 2 != 0)p *= -1;ll q = modPow(m, N);ll r = nCk(M, m);//cout << p << " " << q << " " << r << endl;an += p * (q * r) % mod;an %= mod;an += mod;//cout << an % mod << endl;}//cout<<inv[3]<<endl;//cout << nCk(4, 4) << endl;cout << an % mod << endl;}