結果

問題 No.738 平らな農地
ユーザー fumofumofuni
提出日時 2022-07-13 00:30:01
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 290 ms / 2,000 ms
コード長 6,112 bytes
コンパイル時間 2,347 ms
コンパイル使用メモリ 212,736 KB
最終ジャッジ日時 2025-01-30 06:49:03
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 5
other AC * 87
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include<bits/stdc++.h>
using namespace std;
#define rep(i,n) for(ll i=0;i<n;i++)
#define repl(i,l,r) for(ll i=(l);i<(r);i++)
#define per(i,n) for(ll i=(n)-1;i>=0;i--)
#define perl(i,r,l) for(ll i=r-1;i>=l;i--)
#define fi first
#define se second
#define pb push_back
#define ins insert
#define pqueue(x) priority_queue<x,vector<x>,greater<x>>
#define all(x) (x).begin(),(x).end()
#define CST(x) cout<<fixed<<setprecision(x)
#define vtpl(x,y,z) vector<tuple<x,y,z>>
#define rev(x) reverse(x);
using ll=long long;
using vl=vector<ll>;
using vvl=vector<vector<ll>>;
using pl=pair<ll,ll>;
using vpl=vector<pl>;
using vvpl=vector<vpl>;
const ll MOD=1000000007;
const ll MOD9=998244353;
const int inf=1e9+10;
const ll INF=4e18;
const ll dy[9]={0,-1,0,1,1,1,-1,-1,0};
const ll dx[9]={-1,0,1,0,1,-1,1,-1,0};
template<class T> inline bool chmin(T& a, T b) {
if (a > b) {
a = b;
return true;
}
return false;
}
template<class T> inline bool chmax(T& a, T b) {
if (a < b) {
a = b;
return true;
}
return false;
}
template<typename U = unsigned, int B = 32>
class binary_trie {
struct node {
int cnt;
node *ch[2];
node() : cnt(0), ch{ nullptr, nullptr } {}
};
node* add(node* t, U val, int b = B - 1) {
if (!t) t = new node;
t->cnt += 1;
if (b < 0) return t;
bool f = (val >> (U)b) & (U)1;
t->ch[f] = add(t->ch[f], val, b - 1);
return t;
}
node* sub(node* t, U val, int b = B - 1) {
assert(t);
t->cnt -= 1;
if (t->cnt == 0) return nullptr;
if (b < 0) return t;
bool f = (val >> (U)b) & (U)1;
t->ch[f] = sub(t->ch[f], val, b - 1);
return t;
}
U get_min(node* t, U val, int b = B - 1) const {
assert(t);
if (b < 0) return 0;
bool f = (val >> (U)b) & (U)1; f ^= !t->ch[f];
return get_min(t->ch[f], val, b - 1) | ((U)f << (U)b);
}
U get(node* t, int k, int b = B - 1) const {
if (b < 0) return 0;
int m = t->ch[0] ? t->ch[0]->cnt : 0;
return k < m ? get(t->ch[0], k, b - 1) : get(t->ch[1], k - m, b - 1) | ((U)1 << (U)b);
}
int count_lower(node* t, U val, int b = B - 1) {
if (!t || b < 0) return 0;
bool f = (val >> (U)b) & (U)1;
return (f && t->ch[0] ? t->ch[0]->cnt : 0) + count_lower(t->ch[f], val, b - 1);
}
node *root;
public:
binary_trie() : root(nullptr) {}
int size() const {
return root ? root->cnt : 0;
}
bool empty() const {
return !root;
}
void insert(U val) {
root = add(root, val);
}
void erase(U val) {
root = sub(root, val);
}
U max_element(U bias = 0) const {
return get_min(root, ~bias);
}
U min_element(U bias = 0) const {
return get_min(root, bias);
}
int lower_bound(U val) { // return id
return count_lower(root, val);
}
int upper_bound(U val) { // return id
return count_lower(root, val + 1);
}
U operator[](int k) const {
assert(0 <= k && k < size());
return get(root, k);
}
int count(U val) const {
if (!root) return 0;
node *t = root;
for (int i = B - 1; i >= 0; i--) {
t = t->ch[(val >> (U)i) & (U)1];
if (!t) return 0;
}
return t->cnt;
}
};
//0-indexed,2
template <class T>
struct SegTree {
private:
int n;//
vector<T> data;// vector
T def; //
function<T(T, T)> operation; // 使
function<T(T, T)> change;// 使
T find(int a, int b) {
T val_left = def, val_right = def;
for (a += (n - 1), b += (n - 1); a < b; a >>= 1, b >>= 1)
{
if ((a & 1) == 0){
val_left = operation(val_left, data[a]);
}
if ((b & 1) == 0){
val_right = operation(data[--b],val_right);
}
}
return operation(val_left, val_right);
}
public:
// _n:, _def:, _operation:,
// _change:
SegTree(size_t _n, T _def, function<T(T, T)> _operation,
function<T(T, T)> _change=[](T a,T b){return b;})
: def(_def), operation(_operation), change(_change) {
n = 1;
while (n < _n) {
n *= 2;
}
data = vector<T>(2 * n - 1, def);
}
void set(int i, T x) { data[i + n - 1] = x; }
void build() {
for (int k=n-2;k>=0;k--) data[k] = operation(data[2*k+1],data[2*k+2]);
}
// i(0-indexed)x
void update(int i, T x) {
i += n - 1;
data[i] = change(data[i], x);
while (i > 0) {
i = (i - 1) / 2;
data[i] = operation(data[i * 2 + 1], data[i * 2 + 2]);
}
}
T all_prod(){
return data[0];
}
// [a, b)
T query(int a, int b) {
//return _query(a, b, 0, 0, n);
return find(a,b);
}
//
T operator[](int i) {
return data[i + n - 1];
}
};
int main(){
ll n,k;cin >> n >> k;
vl v(n);rep(i,n)cin >> v[i];
vl pls=v;sort(all(pls));pls.erase(unique(all(pls)),pls.end());
rep(i,n)v[i]=lower_bound(all(pls),v[i])-pls.begin();
binary_trie<ll> bt;
ll m=pls.size();
SegTree<pl> st(m,{0,0},[](pl a,pl b){return make_pair(a.first+b.first,a.second+b.second);},[](pl a,pl b){return make_pair(a.first+b.first,a.second
      +b.second);});
rep(i,k){
bt.insert(v[i]);
st.update(v[i],{pls[v[i]],1});
}
ll ans=INF;
rep(i,n-k+1){
ll mid=bt[k/2];
auto f=st.query(mid,m);
ll ret=f.first-pls[mid]*f.second;
auto g=st.query(0,mid);
ret+=pls[mid]*g.second-g.first;
chmin(ans,ret);
if(i==n-k)break;
bt.erase(v[i]);
st.update(v[i],{-pls[v[i]],-1});
bt.insert(v[k+i]);
st.update(v[k+i],{pls[v[k+i]],1});
}
cout << ans << endl;
}
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