結果

問題 No.2012 Largest Triangle
ユーザー chineristAC
提出日時 2022-07-15 22:41:52
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 1,200 ms / 2,500 ms
コード長 1,887 bytes
コンパイル時間 204 ms
コンパイル使用メモリ 82,048 KB
実行使用メモリ 97,664 KB
最終ジャッジ日時 2024-06-27 21:22:16
合計ジャッジ時間 25,183 ms
ジャッジサーバーID
(参考情報)
judge2 / judge4
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 1
other AC * 41
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ソースコード

diff #
プレゼンテーションモードにする

import sys,random,bisect
from collections import deque,defaultdict
from heapq import heapify,heappop,heappush
from itertools import permutations
from math import log,gcd
input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())
local = False
N = int(input())
if not local:
xy = [tuple(mi()) for i in range(N)]
else:
xy = [(random.randint(-100,100),random.randint(-100,100)) for i in range(N)]
xy.sort()
def cross3(a, b, c):
return (b[0]-a[0])*(c[1]-a[1]) - (b[1]-a[1])*(c[0]-a[0])
# ps = [(x, y), ...]: list
def convex_hull(ps):
qs = []
N = len(ps)
for p in ps:
# 2 ">="
while len(qs) > 1 and cross3(qs[-1], qs[-2], p) > 0:
qs.pop()
qs.append(p)
t = len(qs)
for i in range(N-2, -1, -1):
p = ps[i]
while len(qs) > t and cross3(qs[-1], qs[-2], p) > 0:
qs.pop()
qs.append(p)
return qs
totu = convex_hull(xy)
totu.pop()
n = len(totu)
def f(i,a,b):
i %= n
x,y = totu[i]
return a*y-b*x
res = 0
for x,y in xy:
l,m,r = 0,n,2*n
while r-l >= 3:
nl = (l+m)//2
nr = (m+r+1)//2
if f(nl,x,y) < f(m,x,y):
l,m,r = l,nl,m
elif f(m,x,y) > f(nr,x,y):
l,m,r = m,nr,r
else:
l,m,r = nl,m,nr
res = max(res,abs(f(m,x,y)))
l,m,r = 0,n,2*n
while r-l >= 3:
nl = (l+m)//2
nr = (m+r+1)//2
if -f(nl,x,y) < -f(m,x,y):
l,m,r = l,nl,m
elif -f(m,x,y) > -f(nr,x,y):
l,m,r = m,nr,r
else:
l,m,r = nl,m,nr
res = max(res,abs(f(m,x,y)))
print(res)
if local:
check = 0
for x,y in xy:
for p,q in xy:
check = max(check,abs(x*q-y*p))
print(check)
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