結果
| 問題 | 
                            No.2011 Arbitrary Mod (Hidden)
                             | 
                    
| コンテスト | |
| ユーザー | 
                             AngrySadEight
                         | 
                    
| 提出日時 | 2022-07-15 23:12:30 | 
| 言語 | C++14  (gcc 13.3.0 + boost 1.87.0)  | 
                    
| 結果 | 
                             
                                AC
                                 
                             
                            
                         | 
                    
| 実行時間 | 2 ms / 2,000 ms | 
| コード長 | 3,640 bytes | 
| コンパイル時間 | 3,667 ms | 
| コンパイル使用メモリ | 229,344 KB | 
| 実行使用メモリ | 6,944 KB | 
| 最終ジャッジ日時 | 2024-06-27 20:31:01 | 
| 合計ジャッジ時間 | 6,763 ms | 
| 
                            ジャッジサーバーID (参考情報)  | 
                        judge4 / judge3 | 
(要ログイン)
| ファイルパターン | 結果 | 
|---|---|
| other | AC * 43 | 
ソースコード
#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
typedef long long ll;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define repr(i, n) for (int i = (int)(n) - 1; i >= 0; i--)
#define repk(i, k, n) for (int i = k; i < (int)(n); i++)
#define all(v) v.begin(), v.end()
#define mod1 1000000007
#define mod2 998244353
#define vi vector<int>
#define vs vector<string>
#define vc vector<char>
#define vl vector<ll>
#define vvi vector<vector<int>>
#define vvc vector<vector<char>>
#define vvl vector<vector<ll>>
#define vvvi vector<vector<vector<int>>>
#define vvvl vector<vector<vector<ll>>>
#define pii pair<int,int>
#define pil pair<int,ll>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define vpii vector<pair<int,int>>
#define vpll vector<pair<ll,ll>>
#define vvpii vector<vector<pair<int,int>>>
#define vvpll vector<vector<pair<ll,ll>>>
template<typename T> void debug(T e){
    cerr << e << endl;
}
template<typename T> void debug(vector<T> &v){
    rep(i, v.size()){
        cerr << v[i] << " ";
    }
    cerr << endl;
}
template<typename T> void debug(vector<vector<T>> &v){
    rep(i, v.size()){
        rep(j, v[i].size()){
            cerr << v[i][j] << " ";
        }
        cerr << endl;
    }
}
template<typename T> void debug(vector<pair<T, T>> &v){
    rep(i,v.size()){
        cerr << v[i].first << " " << v[i].second << endl;
    }
}
template<typename T> void debug(set<T> &st){
    for (auto itr = st.begin(); itr != st.end(); itr++){
        cerr << *itr << " ";
    }
    cerr << endl;
}
template<typename T> void debug(multiset<T> &ms){
    for (auto itr = ms.begin(); itr != ms.end(); itr++){
        cerr << *itr << " ";
    }
    cerr << endl;
}
template<typename T> void debug(map<T, T> &mp){
    for (auto itr = mp.begin(); itr != mp.end(); itr++){
        cerr << itr->first << " " << itr->second << endl;
    }
}
void debug_out(){
    cerr << endl;
}
template <typename Head, typename... Tail>
void debug_out(Head H, Tail... T){
    cerr << H << " ";
    debug_out(T...);
}
ll my_pow(ll x, ll n, ll mod){
    // 繰り返し二乗法.x^nをmodで割った余り.
    ll ret;
    if (n == 0){
        ret = 1;
    }
    else if (n % 2 == 1){
        ret = (x * my_pow((x * x) % mod, n / 2, mod)) % mod;
    }
    else{
        ret = my_pow((x * x) % mod, n / 2, mod);
    }
    return ret;
}
int main(){
    ll n;
    cin >> n;
    /*vector<bool> prime(1000005, true);
    prime[1] = false;
    repk(i, 1 ,1000005){
        if (prime[i]){
            for (ll j = 2; i * j <= 1000004; j++){
                prime[i * j] = false;
            }
        }
    }
    set<ll> st;
    for (ll i = 20; i <= 5000; i++){
        ll b = i * i - 398;
        for (ll j = 2; j * j <= b; j++){
            if (b % j == 0 && prime[j]){
                if (st.find(j) == st.end()){
                    st.insert(j);
                }
            }
        }
    }
    debug(st);
    ll num = 2LL;
    while(num <= 1048576){
        if (prime[num + 1] && st.find(num + 1) == st.end()){
            cout << num + 1 << endl;
        }
        num *= 2LL;
    }
    cout << 3 * 5 * 17 * 65537 << endl;
    /*ll num = 8LL;
    while(num <= 1048576){
        ll div = -1;
        for (ll i = 2; i * i <= num; i++){
        }
        if (div == -1){
            cout << num << endl;
            break;
        }
        else{
            cout << num << " " << div << endl;
        }
        num *= 2LL;
    }*/
    //ll M = 4294967297;
    //cout << M << endl;
    //cout << 1 << endl;
    ll M = 16711935;
    cout << M << endl;
    cout << 1 << endl;
}
            
            
            
        
            
AngrySadEight