結果
問題 | No.847 Divisors of Power |
ユーザー | h-izu |
提出日時 | 2022-07-23 01:07:53 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 7 ms / 2,000 ms |
コード長 | 5,693 bytes |
コンパイル時間 | 4,675 ms |
コンパイル使用メモリ | 280,784 KB |
実行使用メモリ | 6,948 KB |
最終ジャッジ日時 | 2024-07-04 10:07:51 |
合計ジャッジ時間 | 5,736 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 1 ms
6,944 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 2 ms
6,940 KB |
testcase_04 | AC | 1 ms
6,944 KB |
testcase_05 | AC | 2 ms
6,940 KB |
testcase_06 | AC | 2 ms
6,940 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 2 ms
6,944 KB |
testcase_09 | AC | 2 ms
6,944 KB |
testcase_10 | AC | 2 ms
6,940 KB |
testcase_11 | AC | 2 ms
6,940 KB |
testcase_12 | AC | 2 ms
6,944 KB |
testcase_13 | AC | 2 ms
6,944 KB |
testcase_14 | AC | 2 ms
6,940 KB |
testcase_15 | AC | 7 ms
6,940 KB |
testcase_16 | AC | 2 ms
6,948 KB |
testcase_17 | AC | 2 ms
6,944 KB |
testcase_18 | AC | 2 ms
6,940 KB |
testcase_19 | AC | 2 ms
6,944 KB |
testcase_20 | AC | 2 ms
6,940 KB |
testcase_21 | AC | 3 ms
6,940 KB |
testcase_22 | AC | 2 ms
6,940 KB |
testcase_23 | AC | 2 ms
6,940 KB |
testcase_24 | AC | 6 ms
6,944 KB |
testcase_25 | AC | 2 ms
6,944 KB |
testcase_26 | AC | 2 ms
6,944 KB |
testcase_27 | AC | 2 ms
6,940 KB |
testcase_28 | AC | 2 ms
6,940 KB |
testcase_29 | AC | 2 ms
6,940 KB |
ソースコード
#ifdef __LOCAL #define _GLIBCXX_DEBUG #endif #include <bits/stdc++.h> #include <atcoder/all> using namespace std; using namespace atcoder; typedef unsigned long long ull; typedef long long ll; const double PI = 3.14159265358979323846; #define rep(i, n) for (ll i = 0; i < (ll)(n); i++) // a^p // 2^3 = 2 * 2^2 // 2^2 = 2 * (2^1) // 2^1 = 2 ll modpow(ll a, ll p, ll mod) { if (p == 0) return 1; a %= mod; if (p % 2 == 0) { ll half = modpow(a, p / 2, mod) % mod; return half * half % mod; } else { return a * modpow(a, p - 1, mod) % mod; } } // a^p ll powpow(ll a, ll p) { if (p == 0) return 1; if (p % 2 == 0) { ll half = pow(a, p / 2); return half * half; } else { return a * pow(a, p - 1); } } // a/b // https://qiita.com/drken/items/3b4fdf0a78e7a138cd9a ll moddiv(ll a, ll b, ll mod) { return a * modpow(b, mod - 2, mod); } // nCa を求める ll modCombination(ll n, ll a, ll mod) { if (n < 0 || a < 0 || n < a) return 0; if (n - a < a) { return modCombination(n, n - a, mod); } ll denominator = 1; // 分母 ll numerator = 1; // 分子 for (ll i = 0; i < a; i++) { denominator *= a - i; numerator *= n - i; denominator %= mod; numerator %= mod; } return numerator * modpow(denominator, mod - 2, mod) % mod; } vector<vector<ll>> combination(ll n) { vector<vector<ll>> C(n + 1, vector<ll>(n + 1)); C[0][0] = 1; rep(i, n) rep(j, i + 1) { C[i + 1][j + 1] += C[i][j]; C[i + 1][j] += C[i][j]; } return C; } // ref. https://drken1215.hatenablog.com/entry/2018/06/08/210000 class ModCombinationTable { private: ll n; ll mod; vector<ll> fac, finv, inv; public: ModCombinationTable(ll n, ll mod) : n(n), mod(mod) { fac.resize(n + 1); finv.resize(n + 1); inv.resize(n + 1); fac[0] = fac[1] = 1; finv[0] = finv[1] = 1; inv[1] = 1; for (ll i = 2; i <= n; i++) { fac[i] = fac[i - 1] * i % mod; inv[i] = mod - inv[mod % i] * (mod / i) % mod; finv[i] = finv[i - 1] * inv[i] % mod; } } ll operator()(ll n, ll k) { if (n < k) return 0; if (n < 0 || k < 0) return 0; return fac[n] * (finv[k] * finv[n - k] % mod) % mod; } }; // cf. https://qiita.com/drken/items/a14e9af0ca2d857dad23 vector<ll> enum_divisors(ll n) { vector<ll> res; // sqrt(n)まで試し割り for (ll i = 1; i * i <= n; i++) { if (n % i == 0) { res.push_back(i); // 重複しないならばiの相方であるn/iも約数 // e.g. n=25のときのi=5は重複 if (n / i != i) res.push_back(n / i); } } sort(res.begin(), res.end()); return res; } // cf. https://qiita.com/drken/items/a14e9af0ca2d857dad23 map<ll, ll> prime_factors(ll n) { map<ll, ll> res; // sqrt(n)まで試し割り for (ll a = 2; a * a <= n; a++) { if (n % a != 0) continue; // nで割れる限り割る while (n % a == 0) { res[a]++; n /= a; } } if (n != 1) res[n]++; return res; } ll gcd(ll a, ll b) { if (b == 0) return a; else return gcd(b, a % b); } ll lcm(ll a, ll b) { return (a / gcd(a, b)) * b; } // p/q struct fraction { ll p, q; fraction(ll _p = 0, ll _q = 1) : p(_p), q(_q) { if (q == 0) { p = 1; return; } if (q < 0) { p = -p; q = -q; } ll g = gcd(p, q); p /= g; q /= g; } bool operator<(const fraction &other) const { return p * other.q < q * other.p; } bool operator<=(const fraction &other) const { return p * other.q <= q * other.p; } bool operator==(const fraction &other) const { return p == other.p && q == other.q; } }; // res[i][c] := i 文字目以降で最初に文字 c が登場する index (存在しないときは n) vector<vector<ll>> calcNext(const string &S) { ll n = (ll)S.size(); vector<vector<ll>> res(n + 1, vector<ll>(26, n)); for (ll i = n - 1; i >= 0; --i) { for (ll j = 0; j < 26; ++j) res[i][j] = res[i + 1][j]; res[i][S[i] - 'a'] = i; } return res; } // ref. https://algo-logic.info/bridge-lowlink/ struct LowLink { vector<vector<ll>> G; vector<ll> ord, low; vector<bool> visited; vector<pair<ll, ll>> bridges; LowLink(const vector<vector<ll>> &G) : G(G) { visited.resize(G.size(), false); ord.resize(G.size(), 0); low.resize(G.size(), 0); ll k = 0; rep(i, (ll)G.size()) { if (visited[i]) continue; k = dfs(i, k); } } ll dfs(ll node, ll k, ll parent = -1) { visited[node] = true; ord[node] = k; low[node] = k; k++; for (auto g : G[node]) { if (!visited[g]) { k = dfs(g, k, node); low[node] = min(low[node], low[g]); if (ord[node] < low[g]) { bridges.emplace_back(node, g); } } else if (g != parent) { low[node] = min(low[node], ord[g]); } } return k; } }; int main() { cin.tie(nullptr); ios_base::sync_with_stdio(false); cout << fixed << setprecision(15); ll N, K, M; cin >> N >> K >> M; auto factors = prime_factors(N); vector<pair<ll, ll>> F(factors.size()); ll i = 0; for (auto [p, e] : factors) { F[i] = make_pair(p, e * K); i++; } ll L = F.size(); // rep(i, L) { cout << F[i].first << " " << F[i].second << endl; } ll ans = 0; auto dfs = [&](auto f, ll n, ll product) -> void { if (n == L) { if (product <= M) { // cout << product << endl; ans++; } return; } ll mul = 1; ll p = F[n].first; rep(i, F[n].second + 1) { if (product > M / mul) break; f(f, n + 1, product * mul); mul *= p; } }; dfs(dfs, 0, 1); cout << ans << endl; return 0; }