結果
| 問題 |
No.5007 Steiner Space Travel
|
| コンテスト | |
| ユーザー |
rosso01
|
| 提出日時 | 2022-08-01 07:11:16 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 896 ms / 1,000 ms |
| コード長 | 4,285 bytes |
| コンパイル時間 | 815 ms |
| 実行使用メモリ | 88,560 KB |
| スコア | 7,063,140 |
| 最終ジャッジ日時 | 2022-08-01 07:11:46 |
| 合計ジャッジ時間 | 29,946 ms |
|
ジャッジサーバーID (参考情報) |
judge12 / judge14 |
| 純コード判定しない問題か言語 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 30 |
ソースコード
"""
最後に各ステーションを重心に移動して微調整するパートを加えた
①、②にかける時間を戻した
①ランダムにステーションを配置して各惑星から最も近いステーションまでのコストの和が最小になる解を山登りで見つける
②次に2点swapでコストの和が最小になる道順を時間いっぱいまで山登りで探索
"""
from random import randint,shuffle,sample
from time import time
# ダイクストラ(惑星専用)
def dijkstra(start = 0, INF=10**20):
from heapq import heappop, heappush
d = [INF for i in range(len(G))]
prev = [-1]*len(G)
d[start] = 0
que = []
heappush(que, (0, start))
while que:
d_, v = heappop(que)
if d[v] < d_: continue
for u, c in G[v].items():
if d[u] > d[v] + c:
d[u] = d[v] + c
prev[u] = v
heappush(que, (d[u], u))
return d,prev
# sからtまでの最短経路を復元
def recover_path(s,t):
prev = PREV[s]
path = [t]
while prev[t] != -1:
t = prev[t]
path.append(t)
return path[::-1]
# 道順を与えられたときに距離を返す
def calc_score(path):
assert len(path) == N+1, "The length of path should be N+1"
score = 0
for i in range(N):
score += D[path[i]][path[i+1]]
return score
stime = time()
N,M = map(int,input().split())
AB = [tuple(map(int,input().split())) for _ in range(N)]
AB2 = {}
for a,b in AB:
if a not in AB2:
AB2[a] = set()
AB2[a].add(b)
alpha = 5
res2 = 10**30
argmin = []
for itr in range(10000):
CD = []
for i in range(M):
c,d = randint(0,999),randint(0,999)
while c in AB2 and d in AB2[c]:
c,d = randint(0,999),randint(0,999)
CD.append((c,d))
res = 0
for a,b in AB:
MIN = 10**20
for c,d in CD:
MIN = min(MIN,(c-a)**2+(d-b)**2)
res += MIN
if res < res2:
res2 = res
argmin = CD
CD = argmin
G = [{} for _ in range(N+M)]
for i in range(N+M-1):
if i < N:
x1,y1 = AB[i]
else:
x1,y1 = CD[i-N]
for j in range(i+1,N+M):
if j < N:
x2,y2 = AB[j]
else:
x2,y2 = CD[j-N]
dist = (x2-x1)**2 + (y2-y1)**2
if i<N and j<N:
dist *= alpha**2
elif i<N or j<N:
dist *= alpha
G[i][j] = G[j][i] = dist
D = [[0]*(N+M) for _ in range(N+M)]
PREV = [[-1]*(N+M) for _ in range(N+M)]
for i in range(N+M):
D[i],PREV[i] = dijkstra(i)
ans = list(range(1,N))
score = calc_score([0]+ans+[0])
# 初期解
for i in range(100):
ans2 = ans[:]
shuffle(ans2)
score2 = calc_score([0]+ans2+[0])
if score2 < score:
score = score2
ans = ans2
#print(score)
# 2点swapで山登り
for itr in range(10**7):
if time() - stime > 0.8:
break
i,j = sample(range(N-1),2)
ans[i],ans[j] = ans[j],ans[i]
score2 = calc_score([0]+ans+[0])
if score2 < score:
score = score2
else:
ans[i],ans[j] = ans[j],ans[i]
ans = [0]+ans+[0]
all_path = [ans[0]]
for i in range(N):
s,t = ans[i],ans[i+1]
path = recover_path(s,t)
for j in range(len(path)-1):
all_path.append(path[j+1])
# 一度も訪問しないステーションが発生した場合は一番近いステーションから往復する
unvisited = set(i for i in range(N+M)) - set(all_path)
#unvisited = set([N])
if unvisited:
for x in unvisited:
MIN = 10**20
argmin = -1
for y in range(N,N+M):
if x == y:
continue
if D[x][y] < MIN:
MIN = D[x][y]
argmin = y
idx = all_path.index(y)
all_path.insert(idx+1,y)
all_path.insert(idx+1,x)
# 各ステーションを重心に移動させる
data = {i:set() for i in range(M)}
for i in range(len(all_path)-1):
a,b = all_path[i],all_path[i+1]
if a<N and b<N:
continue
if a>=N and b>=N:
continue
if a > b:
a,b = b,a
data[b-N].add(a)
#print(data)
for i in range(M):
X = []
Y = []
for j in data[i]:
X.append(AB[j][0])
Y.append(AB[j][1])
#assert X
if X:
CD[i] = sum(X)//len(X),sum(Y)//len(Y)
#print(score)
#print(all_path)
for c,d in CD:
print(c,d)
print(len(all_path))
for idx in all_path:
if idx < N:
t = 1
else:
t = 2
idx -= N
print(t,idx+1)
rosso01