結果

問題 No.1641 Tree Xor Query
ユーザー momoyuu
提出日時 2022-08-03 02:47:48
言語 PyPy3
(7.3.15)
結果
RE  
実行時間 -
コード長 1,994 bytes
コンパイル時間 403 ms
コンパイル使用メモリ 82,136 KB
実行使用メモリ 583,192 KB
最終ジャッジ日時 2024-07-23 20:52:32
合計ジャッジ時間 7,926 ms
ジャッジサーバーID
(参考情報)
judge1 / judge2
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 1 RE * 9 MLE * 1 -- * 7
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

def main():
import sys
sys.setrecursionlimit(10**8)
input = sys.stdin.readline
N,Q = map(int,input().split())
C = list(map(int,input().split()))
def f(n):
return int(n) - 1
ab = [list(map(f,input().split())) for _ in range(N-1)]
# txy = [list(map(int,input().split())) for _ in range(Q)]
e = [[] for _ in range(N)]
for i in range(N-1):
a,b = ab[i]
e[a].append(b)
e[b].append(a)
sum = [0 for _ in range(N)]
d = [[0,0] for _ in range(N)]
l = [0 for _ in range(N)]
def euler(n,k):
d[n][0] = k
l[n] = 1
now = k
for i in e[n]:
if l[i] == 1:
continue
qqq = euler(i,now+1)
now = qqq
d[n][1] = now + 1
return (now + 1)
euler(0,0)
import math
def dfs(n):
l[n] = 1
sum[n] = C[n]
for i in e[n]:
if l[i]:
continue
s = dfs(i)
sum[n] ^= s
return sum[n]
q = math.floor(math.sqrt(Q))
nowq = 0
while True:
for i in range(N):
l[i] = 0
dfs(0)
p = 1
txy = []
for i in range(q):
nq = q * nowq + i
if nq >= Q:
p = 0
break
txy.append(list(map(int,input().split())))
if txy[i][0] == 1:
continue
s = sum[txy[i][1]-1]
for j in range(i):
# nnq = q * nowq + j
# nt,nx,ny = txy[j]
if txy[j][0] == 2:
continue
nx -= 1
if d[txy[i][1]-1][0] <= d[txy[j][1]-1][0] <= d[txy[i][1]-1][1]:
s ^= txy[j][2]
print(s)
if not p:
break
for i in range(q):
if txy[i][0] == 2:
continue
C[txy[i][1]-1] ^= txy[i][2]
nowq += 1
if __name__ == '__main__':
main()
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