結果

問題 No.2030 Googol Strings
ユーザー first_vil
提出日時 2022-08-05 22:00:53
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 229 ms / 2,000 ms
コード長 5,071 bytes
コンパイル時間 2,130 ms
コンパイル使用メモリ 203,872 KB
最終ジャッジ日時 2025-01-30 18:11:05
ジャッジサーバーID
（参考情報） 		judge3 / judge2
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ファイルパターン 結果
sample AC * 1
other AC * 16
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ソースコード

diff #
プレゼンテーションモードにする

// clang-format off
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using ld = long double;
template<class T> using V = vector<T>;
using VI = V<int>;
using VL = V<ll>;
using VS = V<string>;
template<class T> using PQ = priority_queue<T, V<T>, greater<T>>;
using G = V<VI>;
template<class T> using WG = V<V<pair<int, T>>>;
#define overload4(_1,_2,_3,_4,name,...) name
#define rep1(n) for(ll i=0;i<(n);++i)
#define rep2(i,n) for(ll i=0;i<(n);++i)
#define rep3(i,a,b) for(ll i=(a);i<(b);++i)
#define rep4(i,a,b,c) for(ll i=(a);i<(b);i+=(c))
#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)
#define rrep1(n) for(ll i=n;i>0;--i)
#define rrep2(i,n) for(ll i=n;i>0;--i)
#define rrep3(i,a,b) for(ll i=b;i>a;--i)
#define rrep4(i,a,b,c) for(ll i=(a)+((b)-(a)-1)/(c)*(c);i>=(a);i-=c)
#define rrep(...) overload4(__VA_ARGS__,rrep4,rrep3,rrep2,rrep1)(__VA_ARGS__)
#define all(a) a.begin(),a.end()
#define rall(a) a.rbegin(),a.rend()
#define inside(h,w,y,x) (unsigned(y)<h&&unsigned(x)<w)
#ifdef _DEBUG
#define line cout << "-----------------------------\n"
#define debug(...) print(__VA_ARGS__)
#else
#define line
#define debug
#endif
constexpr ll INF = 1000000000;
constexpr ll LLINF = 1LL << 61;
constexpr ll mod = 1000000007;
constexpr ll MOD = 998244353;
constexpr ld eps = 1e-10;
constexpr int dy[]{ -1,0,1,0 }, dx[]{ 0,1,0,-1 };
template<class T> inline bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; }return false; }
template<class T> inline bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; }return false; }
inline void init() { cin.tie(nullptr); cout.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(15); }
template<class T> inline istream& operator>>(istream& is, V<T>& v) { for (auto& a : v)is >> a; return is; }
template<class T, class U> inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }
template<class T> inline V<T> vec(size_t a) { return V<T>(a); }
template<class T> inline V<T> defvec(T def, size_t a) { return V<T>(a, def); }
template<class T, class... Ts> inline auto vec(size_t a, Ts... ts) { return V<decltype(vec<T>(ts...))>(a, vec<T>(ts...)); }
template<class T, class... Ts> inline auto defvec(T def, size_t a, Ts... ts) { return V<decltype(defvec<T>(def, ts...))>(a, defvec<T>(def, ts...)); }
template<class T> inline void print(const T& a) { cout << a << "\n"; }
template<class T, class... Ts> inline void print(const T& a, const Ts&... ts) { cout << a << " "; print(ts...); }
template<class T> inline void print(const V<T>& v) { for (int i = 0; i < v.size(); ++i)cout << v[i] << (i == v.size() - 1 ? "\n" : " "); }
template<class T> inline void print(const V<V<T>>& v) { for (auto& a : v)print(a); }
template<class T> inline constexpr const T cum(const V<T>& a, int l, int r) { return 0 <= l && l <= r && r < a.size() ? a[r] - (l == 0 ? 0 : a[l - 1]
    ) : 0; }//[l,r]
template<class T> inline constexpr const auto min(const T& v) { return *min_element(all(v)); }
template<class T> inline constexpr const auto max(const T& v) { return *max_element(all(v)); }
template<class T> inline V<T>& operator++(V<T>& v) { for (T& a : v)++a; return v; }
template<class T> inline V<T>& operator--(V<T>& v) { for (T& a : v)--a; return v; }
// clang-format on
class RollingHash {
    ll base1 = 1007, base2 = 2009;
    ll mod1 = 1000000007, mod2 = 998244353;
    VL hash1, hash2, power1, power2;
public:
    RollingHash(const string& s) {
        int n = s.size();
        hash1.resize(n + 1);
        hash2.resize(n + 1);
        power1.resize(n + 1, 1);
        power2.resize(n + 1, 1);
        rep(i, n) {
            hash1[i + 1] = (hash1[i] * base1 + s[i]) % mod1;
            hash2[i + 1] = (hash2[i] * base2 + s[i]) % mod2;
            power1[i + 1] = (power1[i] * base1) % mod1;
            power2[i + 1] = (power2[i] * base2) % mod2;
        }
    }
    inline pair<ll, ll> hash(int l, int r) const {
        ll res1 = hash1[r] - hash1[l] * power1[r - l] % mod1;
        if (res1 < 0) res1 += mod1;
        ll res2 = hash2[r] - hash2[l] * power2[r - l] % mod2;
        if (res2 < 0) res2 += mod2;
        return {res1, res2};
    }
};
int main() {
    init();
    int t;
    cin >> t;
    rep(_, t) {
        string x, y;
        cin >> x >> y;
        string ansX = "X", ansY = "Y";
        if (x.size() > y.size()) {
            swap(ansX, ansY);
            swap(x, y);
        }
        RollingHash X(x), Y(y + y);
        int cnt = 0;
        V<bool> seen(y.size());
        bool f = true;
        int i = 0;
        while (true) {
            seen[i] = true;
            if (X.hash(0, x.size()) == Y.hash(i, i + x.size())) {
                ++cnt;
                i = (i + (int)x.size()) % int(y.size());
                if (seen[i]) {
                    break;
                }
            }
            else {
                f = false;
                break;
            }
        }
        if (f) print(ansY);
        else print(x > (y + y).substr(i, i + x.size()) ? ansX : ansY);
    }
    return 0;
}
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