結果

問題 No.2032 Let's Write Multiples!!
ユーザー 👑 hitonanodehitonanode
提出日時 2022-08-06 19:02:00
言語 C++23(draft)
(gcc 11.2.0 + boost 1.78.0)
結果
AC  
実行時間 271 ms / 3,000 ms
コード長 7,158 Byte
コンパイル時間 1,454 ms
使用メモリ 3,556 KB
最終ジャッジ日時 2022-08-06 19:02:10
合計ジャッジ時間 6,250 ms
ジャッジサーバーID
(参考情報)
judge15 / judge11
このコードへのチャレンジ(β)

テストケース

テストケース表示
入力 結果 実行時間
使用メモリ
testcase_00 AC 1 ms
3,384 KB
testcase_01 AC 71 ms
3,396 KB
testcase_02 AC 48 ms
3,544 KB
testcase_03 AC 37 ms
3,400 KB
testcase_04 AC 101 ms
3,448 KB
testcase_05 AC 265 ms
3,392 KB
testcase_06 AC 220 ms
3,444 KB
testcase_07 AC 74 ms
3,448 KB
testcase_08 AC 154 ms
3,536 KB
testcase_09 AC 265 ms
3,544 KB
testcase_10 AC 162 ms
3,396 KB
testcase_11 AC 162 ms
3,468 KB
testcase_12 AC 140 ms
3,548 KB
testcase_13 AC 143 ms
3,400 KB
testcase_14 AC 126 ms
3,544 KB
testcase_15 AC 97 ms
3,448 KB
testcase_16 AC 100 ms
3,552 KB
testcase_17 AC 108 ms
3,536 KB
testcase_18 AC 271 ms
3,552 KB
testcase_19 AC 97 ms
3,556 KB
testcase_20 AC 56 ms
3,548 KB
testcase_21 AC 72 ms
3,392 KB
testcase_22 AC 64 ms
3,556 KB
testcase_23 AC 65 ms
3,556 KB
testcase_24 AC 67 ms
3,496 KB
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <deque>
#include <forward_list>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iostream>
#include <limits>
#include <list>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <type_traits>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>
using namespace std;
using lint = long long;
using pint = pair<int, int>;
using plint = pair<lint, lint>;
struct fast_ios { fast_ios(){ cin.tie(nullptr), ios::sync_with_stdio(false), cout << fixed << setprecision(20); }; } fast_ios_;
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, begin, end) for(int i=(begin),i##_end_=(end);i<i##_end_;i++)
#define IFOR(i, begin, end) for(int i=(end)-1,i##_begin_=(begin);i>=i##_begin_;i--)
#define REP(i, n) FOR(i,0,n)
#define IREP(i, n) IFOR(i,0,n)
template <typename T, typename V>
void ndarray(vector<T>& vec, const V& val, int len) { vec.assign(len, val); }
template <typename T, typename V, typename... Args> void ndarray(vector<T>& vec, const V& val, int len, Args... args) { vec.resize(len), for_each(begin(vec), end(vec), [&](T& v) { ndarray(v, val, args...); }); }
template <typename T> bool chmax(T &m, const T q) { return m < q ? (m = q, true) : false; }
template <typename T> bool chmin(T &m, const T q) { return m > q ? (m = q, true) : false; }
int floor_lg(long long x) { return x <= 0 ? -1 : 63 - __builtin_clzll(x); }
template <typename T1, typename T2> pair<T1, T2> operator+(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first + r.first, l.second + r.second); }
template <typename T1, typename T2> pair<T1, T2> operator-(const pair<T1, T2> &l, const pair<T1, T2> &r) { return make_pair(l.first - r.first, l.second - r.second); }
template <typename T> vector<T> sort_unique(vector<T> vec) { sort(vec.begin(), vec.end()), vec.erase(unique(vec.begin(), vec.end()), vec.end()); return vec; }
template <typename T> int arglb(const std::vector<T> &v, const T &x) { return std::distance(v.begin(), std::lower_bound(v.begin(), v.end(), x)); }
template <typename T> int argub(const std::vector<T> &v, const T &x) { return std::distance(v.begin(), std::upper_bound(v.begin(), v.end(), x)); }
template <typename T> istream &operator>>(istream &is, vector<T> &vec) { for (auto &v : vec) is >> v; return is; }
template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec) { os << '['; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T, size_t sz> ostream &operator<<(ostream &os, const array<T, sz> &arr) { os << '['; for (auto v : arr) os << v << ','; os << ']'; return os; }
#if __cplusplus >= 201703L
template <typename... T> istream &operator>>(istream &is, tuple<T...> &tpl) { std::apply([&is](auto &&... args) { ((is >> args), ...);}, tpl); return is; }
template <typename... T> ostream &operator<<(ostream &os, const tuple<T...> &tpl) { os << '('; std::apply([&os](auto &&... args) { ((os << args << ','), ...);}, tpl); return os << ')'; }
#endif
template <typename T> ostream &operator<<(ostream &os, const deque<T> &vec) { os << "deq["; for (auto v : vec) os << v << ','; os << ']'; return os; }
template <typename T> ostream &operator<<(ostream &os, const set<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T, typename TH> ostream &operator<<(ostream &os, const unordered_set<T, TH> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T> &vec) { os << '{'; for (auto v : vec) os << v << ','; os << '}'; return os; }
template <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &pa) { os << '(' << pa.first << ',' << pa.second << ')'; return os; }
template <typename TK, typename TV> ostream &operator<<(ostream &os, const map<TK, TV> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
template <typename TK, typename TV, typename TH> ostream &operator<<(ostream &os, const unordered_map<TK, TV, TH> &mp) { os << '{'; for (auto v : mp) os << v.first << "=>" << v.second << ','; os << '}'; return os; }
#ifdef HITONANODE_LOCAL
const string COLOR_RESET = "\033[0m", BRIGHT_GREEN = "\033[1;32m", BRIGHT_RED = "\033[1;31m", BRIGHT_CYAN = "\033[1;36m", NORMAL_CROSSED = "\033[0;9;37m", RED_BACKGROUND = "\033[1;41m", NORMAL_FAINT = "\033[0;2m";
#define dbg(x) cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << endl
#define dbgif(cond, x) ((cond) ? cerr << BRIGHT_CYAN << #x << COLOR_RESET << " = " << (x) << NORMAL_FAINT << " (L" << __LINE__ << ") " << __FILE__ << COLOR_RESET << endl : cerr)
#else
#define dbg(x) 0
#define dbgif(cond, x) 0
#endif

// \sum_{i=0}^{n-1} floor((ai + b) / m)
// 0 <= n < 2e32
// 1 <= m < 2e32
// 0 <= a, b < m
// Complexity: O(lg(m))
long long floor_sum(long long n, long long m, long long a, long long b) {
    auto safe_mod = [](long long x, long long m) -> long long {
        x %= m;
        if (x < 0) x += m;
        return x;
    };
    auto floor_sum_unsigned = [](unsigned long long n, unsigned long long m, unsigned long long a,
                                 unsigned long long b) -> unsigned long long {
        unsigned long long ans = 0;
        while (true) {
            if (a >= m) {
                ans += n * (n - 1) / 2 * (a / m);
                a %= m;
            }
            if (b >= m) {
                ans += n * (b / m);
                b %= m;
            }

            unsigned long long y_max = a * n + b;
            if (y_max < m) break;
            // y_max < m * (n + 1)
            // floor(y_max / m) <= n
            n = (unsigned long long)(y_max / m);
            b = (unsigned long long)(y_max % m);
            std::swap(m, a);
        }
        return ans;
    };

    unsigned long long ans = 0;
    if (a < 0) {
        unsigned long long a2 = safe_mod(a, m);
        ans -= 1ULL * n * (n - 1) / 2 * ((a2 - a) / m);
        a = a2;
    }
    if (b < 0) {
        unsigned long long b2 = safe_mod(b, m);
        ans -= 1ULL * n * ((b2 - b) / m);
        b = b2;
    }
    return ans + floor_sum_unsigned(n, m, a, b);
}

// 1, 2, ..., X, K の倍数、数字 C の回数
lint solve(lint X, lint K, lint C) {
    lint len = X / K + 1;
    lint ret = 0;

    for (lint m = 10; m <= 1000000000; m *= 10) {
        ret += floor_sum(len, m, K, m / 10 * (10 - C));
        ret -= floor_sum(len, m, K, m / 10 * (10 - (C + 1)));
    }
    return ret;
}

int main() {
    int T;
    cin >> T;
    while (T--) {
        lint L, R, K, C;
        cin >> L >> R >> K >> C;
        cout << solve(R, K, C) - solve(L - 1, K, C) << '\n';
    }
}
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