結果
問題 | No.2040 010-1 Deletion |
ユーザー | miscalc |
提出日時 | 2022-08-13 00:25:22 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
MLE
|
実行時間 | - |
コード長 | 3,285 bytes |
コンパイル時間 | 4,529 ms |
コンパイル使用メモリ | 272,364 KB |
実行使用メモリ | 814,976 KB |
最終ジャッジ日時 | 2024-09-23 04:56:59 |
合計ジャッジ時間 | 7,170 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
6,812 KB |
testcase_01 | AC | 2 ms
6,940 KB |
testcase_02 | AC | 2 ms
6,940 KB |
testcase_03 | AC | 4 ms
6,940 KB |
testcase_04 | AC | 2 ms
6,944 KB |
testcase_05 | AC | 2 ms
6,944 KB |
testcase_06 | AC | 2 ms
6,940 KB |
testcase_07 | AC | 2 ms
6,940 KB |
testcase_08 | AC | 2 ms
6,944 KB |
testcase_09 | AC | 2 ms
6,944 KB |
testcase_10 | AC | 2 ms
6,940 KB |
testcase_11 | MLE | - |
testcase_12 | -- | - |
testcase_13 | -- | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
testcase_17 | -- | - |
testcase_18 | -- | - |
testcase_19 | -- | - |
testcase_20 | -- | - |
testcase_21 | -- | - |
testcase_22 | -- | - |
testcase_23 | -- | - |
testcase_24 | -- | - |
testcase_25 | -- | - |
testcase_26 | -- | - |
testcase_27 | -- | - |
testcase_28 | -- | - |
testcase_29 | -- | - |
testcase_30 | -- | - |
testcase_31 | -- | - |
testcase_32 | -- | - |
testcase_33 | -- | - |
testcase_34 | -- | - |
testcase_35 | -- | - |
testcase_36 | -- | - |
ソースコード
#include <bits/stdc++.h> using namespace std; using ll = long long; using ld = long double; using pll = pair<ll, ll>; using tlll = tuple<ll, ll, ll>; constexpr ll INF = 1LL << 60; template<class T> bool chmin(T& a, T b) {if (a > b) {a = b; return true;} return false;} template<class T> bool chmax(T& a, T b) {if (a < b) {a = b; return true;} return false;} ll safemod(ll A, ll M) {ll res = A % M; if (res < 0) res += M; return res;} ll divfloor(ll A, ll B) {if (B < 0) {return divfloor(-A, -B);} return (A - safemod(A, B)) / B;} ll divceil(ll A, ll B) {if (B < 0) {return divceil(-A, -B);} return divfloor(A + B - 1, B);} ll pow_ll(ll A, ll B) {if (A == 0 || A == 1) {return A;} if (A == -1) {return B & 1 ? -1 : 1;} ll res = 1; for (int i = 0; i < B; i++) {res *= A;} return res;} ll logfloor(ll A, ll B) {assert(A >= 2); ll res = 0; for (ll tmp = 1; tmp <= B / A; tmp *= A) {res++;} return res;} ll logceil(ll A, ll B) {assert(A >= 2); ll res = 0; for (ll tmp = 1; tmp < B; tmp *= A) {res++;} return res;} ll arisum_ll(ll a, ll d, ll n) { return n * a + (n & 1 ? ((n - 1) >> 1) * n : (n >> 1) * (n - 1)) * d; } ll arisum2_ll(ll a, ll l, ll n) { return n & 1 ? ((a + l) >> 1) * n : (n >> 1) * (a + l); } ll arisum3_ll(ll a, ll l, ll d) { assert((l - a) % d == 0); return arisum2_ll(a, l, (l - a) / d + 1); } template<class T> void unique(vector<T> &V) {V.erase(unique(V.begin(), V.end()), V.end());} template<class T> void sortunique(vector<T> &V) {sort(V.begin(), V.end()); V.erase(unique(V.begin(), V.end()), V.end());} #define FINALANS(A) do {cout << (A) << '\n'; exit(0);} while (false) template<class T> void printvec(const vector<T> &V) {int _n = V.size(); for (int i = 0; i < _n; i++) cout << V[i] << (i == _n - 1 ? "" : " ");cout << '\n';} template<class T> void printvect(const vector<T> &V) {for (auto v : V) cout << v << '\n';} template<class T> void printvec2(const vector<vector<T>> &V) {for (auto &v : V) printvec(v);} //* #include <atcoder/all> using namespace atcoder; using mint = modint998244353; //using mint = modint1000000007; //using mint = modint; //*/ int main() { ll N; cin >> N; string S; cin >> S; vector dp(N + 1, vector(6 * N, vector(2, vector(2, mint(0))))); dp.at(0).at(3 * N).at(1).at(0) = 1; for (ll i = 0; i < N; i++) { for (ll j = 0; j < 6 * N; j++) { for (ll k = 0; k < 2; k++) { for (ll l = 0; l < 2; l++) { if (S.at(i) == '?' || S.at(i) == '0') { ll nj = j + 1; ll nl = (l + 1) % 2; if (0 <= nj && nj < 6 * N) dp.at(i + 1).at(nj).at(0).at(nl) += dp.at(i).at(j).at(k).at(l); } if (S.at(i) == '?' || S.at(i) == '1') { ll nj = (k == 0 ? j - 2 : j); if (0 <= nj && nj < 6 * N) dp.at(i + 1).at(nj).at(1).at(l) += dp.at(i).at(j).at(k).at(l); } } } } } mint ans = 0; for (ll j = 0; j <= 3 * N; j++) { for (ll k = 0; k < 2; k++) { mint tmp = dp.at(N).at(j).at(k).at(0); ll j2 = (k == 1 ? j + 2 : j); if (j2 <= 3 * N) { //if (tmp != 0) cerr << j2 - 3 * N << endl; ans += tmp; } } } if (count(S.begin(), S.end(), '0') == 0) ans++; cout << ans.val() << endl; }