結果

問題 No.1398 調和の魔法陣 (構築)
ユーザー 👑 obakyan
提出日時 2022-08-17 00:06:50
言語 Lua
(LuaJit 2.1.1734355927)
結果
WA  
実行時間 -
コード長 2,845 bytes
コンパイル時間 265 ms
コンパイル使用メモリ 6,944 KB
実行使用メモリ 6,820 KB
最終ジャッジ日時 2024-10-03 18:46:37
合計ジャッジ時間 26,867 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 26 WA * 2
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

local w, h, x = io.read("*n", "*n", "*n")
if x == 0 then
for i = 1, h do
print(string.rep("0", w))
end
os.exit()
end
if w == 1 then
if h == 1 then
if 9 < x then
print(-1)
else
print(x)
end
elseif h % 3 ~= 2 or 18 < x then
print(-1)
else
local t = {}
t[1] = math.min(x, 9)
t[2] = x - t[1]
for i = 1, h do
if i % 3 == 1 then
print(t[1])
elseif i % 3 == 2 then
print(t[2])
else
print(0)
end
end
end
os.exit()
end
if h == 1 then
if w % 3 ~= 2 or 18 < x then
print(-1)
else
local t = {}
t[1] = math.min(x, 9)
t[2] = x - t[1]
for j = 1, w do
if j % 3 == 1 then
io.write(t[1])
elseif j % 3 == 2 then
io.write(t[2])
else
io.write(0)
end
end
io.write("\n")
end
os.exit()
end
if 36 < x then
print(-1)
os.exit()
end
local rx = x
local t = {}
for i = 1, 4 do
t[i] = math.min(x, 9)
x = x - t[i]
end
x = rx
if 18 < x then
if w % 3 ~= 2 or h % 3 ~= 2 then
print(-1)
os.exit()
end
for i = 1, h do
for j = 1, w do
if i % 3 == 1 and j % 3 == 1 then
io.write(t[1])
elseif i % 3 == 1 and j % 3 == 2 then
io.write(t[2])
elseif i % 3 == 2 and j % 3 == 1 then
io.write(t[3])
elseif i % 3 == 2 and j % 3 == 2 then
io.write(t[4])
else
io.write(0)
end
end
io.write("\n")
end
os.exit()
end
if 9 < x then
if w % 3 ~= 2 and h % 3 ~= 2 then
print(-1)
os.exit()
end
if w % 3 == 2 then
if h % 3 == 0 then
t[1], t[3] = t[3], t[1]
t[2], t[4] = t[4], t[2]
end
else
if w % 3 == 0 then
t[1], t[2] = t[2], t[1]
t[3], t[4] = t[4], t[3]
end
end
for i = 1, h do
for j = 1, w do
if i % 3 == 1 and j % 3 == 1 then
io.write(t[1])
elseif i % 3 == 1 and j % 3 == 2 then
io.write(t[2])
elseif i % 3 == 2 and j % 3 == 1 then
io.write(t[3])
elseif i % 3 == 2 and j % 3 == 2 then
io.write(t[4])
else
io.write(0)
end
end
io.write("\n")
end
os.exit()
end
do
if w % 3 == 0 then
if h % 3 == 0 then
t[1], t[4] = t[4], t[1]
else
t[1], t[2] = t[2], t[1]
end
elseif w % 3 == 1 then
if h % 3 == 0 then
t[1], t[3] = t[3], t[1]
end
else
if h % 3 == 0 then
t[1], t[3] = t[3], t[1]
end
end
for i = 1, h do
for j = 1, w do
if i % 3 == 1 and j % 3 == 1 then
io.write(t[1])
elseif i % 3 == 1 and j % 3 == 2 then
io.write(t[2])
elseif i % 3 == 2 and j % 3 == 1 then
io.write(t[3])
elseif i % 3 == 2 and j % 3 == 2 then
io.write(t[4])
else
io.write(0)
end
end
io.write("\n")
end
os.exit()
end
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