結果
問題 |
No.2338 Range AtCoder Query
|
ユーザー |
![]() |
提出日時 | 2022-08-23 17:08:19 |
言語 | PyPy3 (7.3.15) |
結果 |
AC
|
実行時間 | 899 ms / 4,000 ms |
コード長 | 2,859 bytes |
コンパイル時間 | 154 ms |
コンパイル使用メモリ | 82,848 KB |
実行使用メモリ | 194,896 KB |
最終ジャッジ日時 | 2024-10-04 09:34:34 |
合計ジャッジ時間 | 22,739 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 34 |
ソースコード
# https://github.com/shakayami/ACL-for-python/blob/master/fenwicktree.py class fenwick_tree(): n=1 data=[0 for i in range(n)] def __init__(self,N): self.n=N self.data=[0 for i in range(N)] def add(self,p,x): assert 0<=p<self.n,"0<=p<n,p={0},n={1}".format(p,self.n) p+=1 while(p<=self.n): self.data[p-1]+=x p+=p& -p def sum(self,l,r): assert (0<=l and l<=r and r<=self.n),"0<=l<=r<=n,l={0},r={1},n={2}".format(l,r,self.n) return self.sum0(r)-self.sum0(l) def sum0(self,r): s=0 while(r>0): s+=self.data[r-1] r-=r&-r return s class OfflineRectangleAddPointGet: def __init__(self, n): self.n = n self.add = [[] for _ in range(n + 1)] self.sub = [[] for _ in range(n + 1)] self.q = 0 self.queries = [[] for _ in range(n)] def add_rect(self, xl, xr, yl, yr): self.add[xl].append((yl, yr)) self.sub[xr].append((yl, yr)) def add_query(self, x, y): self.queries[x].append((y, self.q)) self.q += 1 def solve(self): ret = [0 for _ in range(self.q)] fw = fenwick_tree(self.n + 1) for x in range(self.n): for (l, r) in self.add[x]: fw.add(l, 1) fw.add(r, -1) for (l, r) in self.sub[x]: fw.add(l, -1) fw.add(r, 1) for (y, qi) in self.queries[x]: ret[qi] = fw.sum(0, y + 1) return ret def main(): import sys input = sys.stdin.readline n, m, q = map(int, input().split()) p = [0 for _ in range(n)] is_ac = [False for _ in range(n)] for i in range(n): pi, si = input().split() p[i] = int(pi) - 1 is_ac[i] = si == "AC" l = [0 for _ in range(q)] r = [0 for _ in range(q)] for i in range(q): li, ri = map(int, input().split()) l[i] = li - 1 r[i] = ri prev_ac = [-1 for _ in range(n)] next_ac = [n for _ in range(n)] pv = [-1 for _ in range(m)] for i in range(n): prev_ac[i] = pv[p[i]] if is_ac[i]: pv[p[i]] = i nt = [n for _ in range(m)] for i in reversed(range(n)): next_ac[i] = nt[p[i]] if is_ac[i]: nt[p[i]] = i ac = OfflineRectangleAddPointGet(n + 1) pena = OfflineRectangleAddPointGet(n + 1) for i in range(n): if is_ac[i]: ac.add_rect(prev_ac[i] + 1, i + 1, i + 1, n + 1) else: pena.add_rect(prev_ac[i] + 1, i + 1, next_ac[i] + 1, n + 1) for i in range(q): ac.add_query(l[i], r[i]) pena.add_query(l[i], r[i]) acc = ac.solve() penac = pena.solve() for i in range(q): print(acc[i], penac[i]) main()