結果

問題 No.1073 無限すごろく
ユーザー tenten
提出日時 2022-08-30 16:16:18
言語 Java
(openjdk 23)
結果
AC  
実行時間 57 ms / 2,000 ms
コード長 2,362 bytes
コンパイル時間 3,239 ms
コンパイル使用メモリ 77,624 KB
実行使用メモリ 37,364 KB
最終ジャッジ日時 2024-11-07 10:42:55
合計ジャッジ時間 5,252 ms
ジャッジサーバーID
(参考情報)
judge2 / judge1
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 30
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

import java.io.*;
import java.util.*;
public class Main {
static final int MOD = 1000000007;
public static void main(String[] args) throws Exception {
Scanner sc = new Scanner();
long n = sc.nextLong();
long[][][] matrix = new long[60][6][6];
long tmp = pow(6, MOD - 2);
matrix[0] = new long[][]{{tmp, tmp, tmp, tmp, tmp, tmp}, {1, 0, 0, 0, 0, 0}, {0, 1, 0, 0, 0, 0}, {0, 0, 1, 0, 0, 0}, {0, 0, 0, 1, 0, 0}, {0, 0
            , 0, 0, 1, 0}};
for (int i = 1; i < 60; i++) {
for (int a = 0; a < 6; a++) {
for (int b = 0; b < 6; b++) {
for (int c = 0; c < 6; c++) {
matrix[i][a][c] += matrix[i - 1][a][b] * matrix[i - 1][b][c];
matrix[i][a][c] %= MOD;
}
}
}
}
long[] ans = new long[]{1, 0, 0, 0, 0, 0};
for (int i = 59; i >= 0; i--) {
if (n < (1L << i)) {
continue;
}
n -= (1L << i);
long[] nexts = new long[6];
for (int a = 0; a < 6; a++) {
for (int b = 0; b < 6; b++) {
nexts[a] += matrix[i][a][b] * ans[b] % MOD;
nexts[a] %= MOD;
}
}
ans = nexts;
}
System.out.println(ans[0]);
}
static long pow(long x, int p) {
if (p == 0) {
return 1;
} else if (p % 2 == 0) {
return pow(x * x % MOD, p / 2);
} else {
return pow(x, p - 1) * x % MOD;
}
}
}
class Scanner {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
StringTokenizer st = new StringTokenizer("");
StringBuilder sb = new StringBuilder();
public Scanner() throws Exception {
}
public int nextInt() throws Exception {
return Integer.parseInt(next());
}
public long nextLong() throws Exception {
return Long.parseLong(next());
}
public double nextDouble() throws Exception {
return Double.parseDouble(next());
}
public String next() throws Exception {
while (!st.hasMoreTokens()) {
st = new StringTokenizer(br.readLine());
}
return st.nextToken();
}
}
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