結果
| 問題 |
No.263 Common Palindromes Extra
|
| コンテスト | |
| ユーザー |
SSRS
|
| 提出日時 | 2022-08-31 03:34:27 |
| 言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 6,950 bytes |
| コンパイル時間 | 2,294 ms |
| コンパイル使用メモリ | 192,620 KB |
| 実行使用メモリ | 103,852 KB |
| 最終ジャッジ日時 | 2024-11-07 20:10:55 |
| 合計ジャッジ時間 | 9,853 ms |
|
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 10 TLE * 2 |
ソースコード
#include <bits/stdc++.h>
using namespace std;
const long long BASE = 123456789;
const long long M30 = ((long long) 1 << 30) - 1;
const long long M31 = ((long long) 1 << 31) - 1;
const long long MOD = ((long long) 1 << 61) - 1;
unsigned long long modulo(unsigned long long x){
unsigned long long xu = x >> 61;
unsigned long long xd = x & MOD;
unsigned long long res = xu + xd;
if (res >= MOD){
res -= MOD;
}
return res;
}
unsigned long long mul(unsigned long long a, unsigned long long b){
unsigned long long au = a >> 31;
unsigned long long ad = a & M31;
unsigned long long bu = b >> 31;
unsigned long long bd = b & M31;
unsigned long long mid = au * bd + ad * bu;
unsigned long long midu = mid >> 30;
unsigned long long midd = mid & M30;
return modulo(au * bu * 2 + midu + (midd << 31) + ad * bd);
}
struct rolling_hash{
vector<long long> POW, S;
rolling_hash(string s){
int N = s.size();
POW.resize(N + 1);
POW[0] = 1;
for (int i = 0; i < N; i++){
POW[i + 1] = mul(POW[i], BASE);
}
S.resize(N + 1);
S[N] = 0;
for (int i = N - 1; i >= 0; i--){
S[i] = modulo(mul(S[i + 1], BASE) + s[i]);
}
}
long long get(int L, int R){
return modulo(S[L] + MOD - mul(S[R], POW[R - L]));
}
};
vector<int> manacher(string &S){
int N = S.size();
vector<int> ans(N, 0);
int i = 0, j = 0;
while (i < N){
while (i >= j && i + j < N && S[i - j] == S[i + j]){
j++;
}
ans[i] = j;
int k = 1;
while (i >= k && i + k < N && k + ans[i - k] < j){
ans[i + k] = ans[i - k];
k++;
}
i += k;
j -= k;
}
return ans;
}
vector<int> suffix_array(const vector<int> &A, int mx){
int N = A.size();
vector<int> sum(mx + 1, 0);
for (int i = 0; i < N; i++){
sum[A[i] + 1]++;
}
for (int i = 0; i < mx; i++){
sum[i + 1] += sum[i];
}
vector<bool> is_s(N);
is_s[N - 1] = false;
for (int i = N - 2; i >= 0; i--){
is_s[i] = A[i] < A[i + 1] || A[i] == A[i + 1] && is_s[i + 1];
}
vector<int> id(N, -1);
vector<int> pos;
int M = 0;
for (int i = 1; i < N; i++){
if (is_s[i] && !is_s[i - 1]){
id[i] = M;
pos.push_back(i);
M++;
}
}
vector<int> sa(N);
auto induce = [&](vector<int>& lms){
sa = vector<int>(N, -1);
vector<bool> used(N, false);
vector<int> p(mx);
vector<int> p2(mx);
for (int i = 0; i < mx; i++){
p[i] = sum[i + 1] - 1;
p2[i] = sum[i];
}
for (int i = M - 1; i >= 0; i--){
sa[p[A[lms[i]]]] = lms[i];
p[A[lms[i]]]--;
used[lms[i]] = true;
}
sa[p2[A[N - 1]]] = N - 1;
p2[A[N - 1]]++;
used[N - 1] = true;
for (int i = 0; i < N; i++){
if (sa[i] > 0){
if (!is_s[sa[i] - 1] && !used[sa[i] - 1]){
sa[p2[A[sa[i] - 1]]] = sa[i] - 1;
p2[A[sa[i] - 1]]++;
used[sa[i] - 1] = true;
}
}
}
for (int i = 0; i < N; i++){
if (sa[i] != -1){
if (id[sa[i]] != -1){
used[sa[i]] = false;
sa[i] = -1;
}
}
}
for (int i = 0; i < mx; i++){
p[i] = sum[i + 1] - 1;
}
for (int i = N - 1; i >= 0; i--){
if (sa[i] > 0){
if (is_s[sa[i] - 1] && !used[sa[i] - 1]){
sa[p[A[sa[i] - 1]]] = sa[i] - 1;
p[A[sa[i] - 1]]--;
used[sa[i] - 1] = true;
}
}
}
};
induce(pos);
if (M == 0){
return sa;
}
vector<int> lms;
for (int i = 0; i < N; i++){
if (id[sa[i]] != -1){
lms.push_back(sa[i]);
}
}
vector<int> c(M);
c[0] = 0;
for (int i = 0; i < M - 1; i++){
c[i + 1] = c[i];
int x = lms[i];
int y = lms[i + 1];
bool ok = true;
while (x < N && y < N){
if (A[x] != A[y]){
ok = false;
break;
}
x++;
y++;
if (id[x] != -1){
if (id[y] == -1){
ok = false;
}
break;
}
}
if (x == N || y == N){
ok = false;
}
if (!ok){
c[i + 1]++;
}
}
vector<int> rec(M);
for (int i = 0; i < M; i++){
rec[id[lms[i]]] = c[i];
}
vector<int> sa2 = suffix_array(rec, c[M - 1] + 1);
vector<int> pos2(M);
for (int i = 0; i < M; i++){
pos2[i] = pos[sa2[i]];
}
induce(pos2);
return sa;
}
vector<int> suffix_array(const string &S){
int N = S.size();
vector<int> A(N);
for (int i = 0; i < N; i++){
A[i] = S[i];
}
return suffix_array(A, 256);
}
vector<int> lcp_array(string &S, vector<int> &SA){
int N = S.size();
vector<int> rank(N);
for (int i = 0; i < N; i++){
rank[SA[i]] = i;
}
vector<int> lcp(N - 1, 0);
int h = 0;
for (int i = 0; i < N; i++){
if (rank[i] > 0){
int prev = SA[rank[i] - 1];
if (h > 0){
h--;
}
while (i + h < N && prev + h < N){
if (S[i + h] != S[prev + h]){
break;
}
h++;
}
lcp[rank[i] - 1] = h;
}
}
return lcp;
}
template <typename T>
struct sparse_table{
vector<vector<T>> ST;
sparse_table(vector<T> &A){
int N = A.size();
int LOG = 32 - __builtin_clz(N);
ST = vector<vector<T>>(LOG, vector<T>(N));
for (int i = 0; i < N; i++){
ST[0][i] = A[i];
}
for (int i = 0; i < LOG - 1; i++){
for (int j = 0; j < N - (1 << i); j++){
ST[i + 1][j] = min(ST[i][j], ST[i][j + (1 << i)]);
}
}
}
T range_min(int L, int R){
int d = 31 - __builtin_clz(R - L);
return min(ST[d][L], ST[d][R - (1 << d)]);
}
};
unordered_map<unsigned long long, int> solve(string S){
int N = S.size();
string T = "$";
for (int i = 0; i < N; i++){
T += S[i];
T += '$';
}
vector<int> A = manacher(T);
vector<int> SA = suffix_array(S);
vector<int> LCP = lcp_array(S, SA);
sparse_table<int> ST(LCP);
rolling_hash RH(S);
vector<int> rank(N);
for (int i = 0; i < N; i++){
rank[SA[i]] = i;
}
unordered_map<unsigned long long, int> mp;
for (int i = 1; i < N * 2; i++){
int l = (i - A[i] + 2) / 2, r = (i + A[i] - 1) / 2;
while (l < r){
unsigned long long hash = RH.get(l, r);
if (mp.count(hash) == 1){
break;
}
int tv1 = rank[l], fv1 = N;
while (fv1 - tv1 > 1){
int mid = (tv1 + fv1) / 2;
if (ST.range_min(rank[l], mid) >= r - l){
tv1 = mid;
} else {
fv1 = mid;
}
}
int tv2 = rank[l], fv2 = -1;
while (tv2 - fv2 > 1){
int mid = (tv2 + fv2) / 2;
if (ST.range_min(mid, rank[l]) >= r - l){
tv2 = mid;
} else {
fv2 = mid;
}
}
mp[hash] = tv1 - tv2 + 1;
l++;
r--;
}
}
return mp;
}
int main(){
string S;
cin >> S;
string T;
cin >> T;
unordered_map<unsigned long long, int> A = solve(S);
unordered_map<unsigned long long, int> B = solve(T);
long long ans = 0;
for (auto P : A){
if (B.count(P.first) == 1){
ans += (long long) P.second * B[P.first];
}
}
cout << ans << endl;
}
SSRS