結果
問題 | No.2063 ±2^k operations (easy) |
ユーザー |
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提出日時 | 2022-09-02 21:35:05 |
言語 | C++14 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 4 ms / 2,000 ms |
コード長 | 2,215 bytes |
コンパイル時間 | 873 ms |
コンパイル使用メモリ | 103,364 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-11-16 02:34:53 |
合計ジャッジ時間 | 1,620 ms |
ジャッジサーバーID (参考情報) |
judge5 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 21 |
ソースコード
#include <iostream>#include <vector>#include <map>#include <algorithm>#include <cmath>#include <iomanip>#include <string>#include <list>#include <cassert>#include <numeric>#include <cstdint>#include <queue>#include <deque>#include <stack>#include <set>#include <random>#include <bitset>// #include <atcoder/all>using ll = long long;using ld = long double;using namespace std;// using namespace atcoder;using P = pair<ll, ll>;using Graph = vector<vector<int>>;using Priority = priority_queue<ll, vector<ll>, greater<ll>>;// 昇順using Priority_pair = priority_queue<P, vector<P>, greater<P>>;// using mint_17 = modint1000000007;// using mint = modint998244353;#define mod 1000000007#define MAX_WIDTH 60#define MAX_HEIGHT 60#define INF 1e18#define MOD 998244353#define PI 3.141592653589793#define rep(i, a, b) for(ll i=(a);i<(b);i++)#define rrep(i, a, b) for(ll i=(a);i>=(b);i--)#define fore(i, a) for(auto &i: a)#define all(v) (v).begin(), (v).end()#define YES(a) cout << ((a) ? "YES" : "NO") << endl#define Yes(a) cout << ((a) ? "Yes" : "No") << endl#define pb(a) push_back(a)#define vi vector<int>#define vll vector<ll>#define vs vector<string>#define vc vector<char>#define vp vector<pair<ll, ll>>#define mll map<ll, ll>#define msl map<string, ll>#define COUT(n) cout << (n) << endl#define isInGrid(a, b, h, w) (0 <= (a) && (a) < (h) && 0 <= (b) && (b) < (w))template<typename T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }template<typename T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }int vx[] = {1, 0, -1, 0}, vy[] = {0, 1, 0, -1};struct edge {ll to, cost;};string S;int main() {cin >> S;ll cnt = 0, block = 0, now = S[0];rep(i,0,S.size()) {if(S[i] == '1') cnt++;}if(now == '1') block++;rep(i,1,S.size()) {if(now != S[i]) {if(S[i] == '1') block++;now = S[i];}}bool ok = false;if(cnt >= 2) {if(cnt == 2 && block == 2) {ok = true;}if(block == 1) {ok = true;}}Yes(ok);return 0;}