結果

問題 No.2065 Sum of Min
ユーザー karinohito
提出日時 2022-09-02 21:35:06
言語 C++17
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 378 ms / 2,000 ms
コード長 5,467 bytes
コンパイル時間 2,761 ms
コンパイル使用メモリ 216,020 KB
最終ジャッジ日時 2025-02-07 00:50:56
ジャッジサーバーID
(参考情報)
judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 2
other AC * 20
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
#include <random>
using namespace std;
//#include <atcoder/all>
//using namespace atcoder;
using ll = long long;
using vll = vector<ll>;
using vvll = vector<vll>;
using vvvll = vector<vvll>;
using vvvvll = vector<vvvll>;
using vvvvvll = vector<vvvvll>;
using vvvvvvll = vector<vvvvvll>;
using vb = vector<bool>;
using vvb = vector<vb>;
using vvvb = vector<vvb>;
using vvvvb = vector<vvvb>;
using vd = vector<double>;
using vvd = vector<vd>;
using vvvd = vector<vvd>;
using vvvvd = vector<vvvd>;
using vvvvvd = vector<vvvvd>;
#define all(A) A.begin(),A.end()
#define ALL(A) A.begin(),A.end()
#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)
using pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;
template<class T>
bool chmax(T& p, T q, bool C = 1) {
if (C == 0 && p == q) {
return 1;
}
if (p < q) {
p = q;
return 1;
}
else {
return 0;
}
}
template<class T>
bool chmin(T& p, T q, bool C = 1) {
if (C == 0 && p == q) {
return 1;
}
if (p > q) {
p = q;
return 1;
}
else {
return 0;
}
}
ll gcd(ll(a), ll(b)) {
if (b == 0)return a;
ll c = a;
while (a % b != 0) {
c = a % b;
a = b;
b = c;
}
return b;
}
vector<ll> fact, factinv, inv;
ll mod = 1e9 + 7;
void prenCkModp(ll n) {
fact.resize(n + 5);
factinv.resize(n + 5);
inv.resize(n + 5);
fact.at(0) = fact.at(1) = 1;
factinv.at(0) = factinv.at(1) = 1;
inv.at(1) = 1;
for (ll i = 2; i < n + 5; i++) {
fact.at(i) = (fact.at(i - 1) * i) % mod;
inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;
factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;
}
}
ll nCk(ll n, ll k) {
if (n < k) return 0;
return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;
}
template <class S, S(*op)(S, S), S(*e)()> struct segtree {
public:
segtree() : segtree(0) {}
segtree(int n) : segtree(std::vector<S>(n, e())) {}
segtree(const std::vector<S>& v) : _n(int(v.size())) {
log = ceil_pow2(_n);
size = 1 << log;
d = std::vector<S>(2 * size, e());
for (int i = 0; i < _n; i++) d[size + i] = v[i];
for (int i = size - 1; i >= 1; i--) {
update(i);
}
}
int ceil_pow2(int n) {
int x = 0;
while ((1U << x) < (unsigned int)(n)) x++;
return x;
}
void set(int p, S x) {
p += size;
d[p] = x;
for (int i = 1; i <= log; i++) update(p >> i);
}
S get(int p) { return d[p + size]; }
S prod(int l, int r) {
S sml = e(), smr = e();
l += size;
r += size;
while (l < r) {
if (l & 1) sml = op(sml, d[l++]);
if (r & 1) smr = op(d[--r], smr);
l >>= 1;
r >>= 1;
}
return op(sml, smr);
}
S all_prod() { return d[1]; }
template <bool (*f)(S)> int max_right(int l) {
return max_right(l, [](S x) { return f(x); });
}
template <class F> int max_right(int l, F f) {
if (l == _n) return _n;
l += size;
S sm = e();
do {
while (l % 2 == 0) l >>= 1;
if (!f(op(sm, d[l]))) {
while (l < size) {
l = (2 * l);
if (f(op(sm, d[l]))) {
sm = op(sm, d[l]);
l++;
}
}
return l - size;
}
sm = op(sm, d[l]);
l++;
} while ((l & -l) != l);
return _n;
}
template <bool (*f)(S)> int min_left(int r) {
return min_left(r, [](S x) { return f(x); });
}
template <class F> int min_left(int r, F f) {
if (r == 0) return 0;
r += size;
S sm = e();
do {
r--;
while (r > 1 && (r % 2)) r >>= 1;
if (!f(op(d[r], sm))) {
while (r < size) {
r = (2 * r + 1);
if (f(op(d[r], sm))) {
sm = op(d[r], sm);
r--;
}
}
return r + 1 - size;
}
sm = op(d[r], sm);
} while ((r & -r) != r);
return 0;
}
private:
int _n, size, log;
std::vector<S> d;
void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};
ll op(ll a, ll b) { return a + b; }
ll e() { return 0; };
int main() {
ll N, Q;
cin >> N >> Q;
vector<pair<ll, ll>> A(N);
rep(i, N) {
cin >> A[i].first;
A[i].second = i;
}
sort(all(A));
A.push_back({ 1e18,-1 });
segtree<ll, op, e> seg(N);
segtree<ll, op, e> segn(N);
vector<tuple<ll, ll, ll, ll>> D(Q);
rep(q, Q) {
ll L, R, X;
cin >> L >> R >> X;
D[q] = { X,L,R,q };
}
sort(all(D));
vll AN(Q);
ll j = 0;
rep(q, Q) {
ll X = get<0>(D[q]);
ll L = get<1>(D[q]);
ll R = get<2>(D[q]);
ll i = get<3>(D[q]);
while (A[j].first < X) {
seg.set(A[j].second, A[j].first);
segn.set(A[j].second, 1);
j++;
}
ll d = seg.prod(L - 1, R);
ll n = segn.prod(L - 1, R);
AN[i] = d + (R - L + 1 - n) * X;
cout << "";
}
rep(i, Q)cout << AN[i] << endl;
}
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