結果
問題 | No.2065 Sum of Min |
ユーザー |
|
提出日時 | 2022-09-03 00:44:16 |
言語 | Rust (1.83.0 + proconio) |
結果 |
AC
|
実行時間 | 197 ms / 2,000 ms |
コード長 | 4,940 bytes |
コンパイル時間 | 23,328 ms |
コンパイル使用メモリ | 401,228 KB |
実行使用メモリ | 25,188 KB |
最終ジャッジ日時 | 2024-11-16 08:50:28 |
合計ジャッジ時間 | 18,496 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge2 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 2 |
other | AC * 20 |
ソースコード
use std::io::{Write, BufWriter};// https://qiita.com/tanakh/items/0ba42c7ca36cd29d0ac8macro_rules! input {($($r:tt)*) => {let stdin = std::io::stdin();let mut bytes = std::io::Read::bytes(std::io::BufReader::new(stdin.lock()));let mut next = move || -> String{bytes.by_ref().map(|r|r.unwrap() as char).skip_while(|c|c.is_whitespace()).take_while(|c|!c.is_whitespace()).collect()};input_inner!{next, $($r)*}};}macro_rules! input_inner {($next:expr) => {};($next:expr,) => {};($next:expr, $var:ident : $t:tt $($r:tt)*) => {let $var = read_value!($next, $t);input_inner!{$next $($r)*}};}macro_rules! read_value {($next:expr, ( $($t:tt),* )) => { ($(read_value!($next, $t)),*) };($next:expr, [ $t:tt ; $len:expr ]) => {(0..$len).map(|_| read_value!($next, $t)).collect::<Vec<_>>()};($next:expr, usize1) => (read_value!($next, usize) - 1);($next:expr, $t:ty) => ($next().parse::<$t>().expect("Parse error"));}/*** Segment Tree. This data structure is useful for fast folding on intervals of an array* whose elements are elements of monoid I. Note that constructing this tree requires the identity* element of I and the operation of I.* Verified by: yukicoder No. 259 (http://yukicoder.me/submissions/100581)* AGC015-E (http://agc015.contest.atcoder.jp/submissions/1461001)* yukicoder No. 833 (https://yukicoder.me/submissions/703521)*/struct SegTree<I, BiOp> {n: usize,orign: usize,dat: Vec<I>,op: BiOp,e: I,}impl<I, BiOp> SegTree<I, BiOp>where BiOp: Fn(I, I) -> I,I: Copy {pub fn new(n_: usize, op: BiOp, e: I) -> Self {let mut n = 1;while n < n_ { n *= 2; } // n is a power of 2SegTree {n: n, orign: n_, dat: vec![e; 2 * n - 1], op: op, e: e}}/* ary[k] <- v */pub fn update(&mut self, idx: usize, v: I) {debug_assert!(idx < self.orign);let mut k = idx + self.n - 1;self.dat[k] = v;while k > 0 {k = (k - 1) / 2;self.dat[k] = (self.op)(self.dat[2 * k + 1], self.dat[2 * k + 2]);}}/* [a, b) (note: half-inclusive)* http://proc-cpuinfo.fixstars.com/2017/07/optimize-segment-tree/ */#[allow(unused)]pub fn query(&self, mut a: usize, mut b: usize) -> I {debug_assert!(a <= b);debug_assert!(b <= self.orign);let mut left = self.e;let mut right = self.e;a += self.n - 1;b += self.n - 1;while a < b {if (a & 1) == 0 {left = (self.op)(left, self.dat[a]);}if (b & 1) == 0 {right = (self.op)(self.dat[b - 1], right);}a = a / 2;b = (b - 1) / 2;}(self.op)(left, right)}}trait Bisect<T> {fn lower_bound(&self, val: &T) -> usize;fn upper_bound(&self, val: &T) -> usize;}impl<T: Ord> Bisect<T> for [T] {fn lower_bound(&self, val: &T) -> usize {let mut pass = self.len() + 1;let mut fail = 0;while pass - fail > 1 {let mid = (pass + fail) / 2;if &self[mid - 1] >= val {pass = mid;} else {fail = mid;}}pass - 1}fn upper_bound(&self, val: &T) -> usize {let mut pass = self.len() + 1;let mut fail = 0;while pass - fail > 1 {let mid = (pass + fail) / 2;if &self[mid - 1] > val {pass = mid;} else {fail = mid;}}pass - 1}}fn main() {let out = std::io::stdout();let mut out = BufWriter::new(out.lock());macro_rules! puts {($($format:tt)*) => (let _ = write!(out,$($format)*););}input! {n: usize, q: usize,a: [i64; n],lrx: [(usize1, usize, i64); q],}let mut qs = vec![vec![]; n + 1];let mut ans = vec![0; q];for i in 0..q {let (l, r, x) = lrx[i];qs[l].push((x, i, -1));qs[r].push((x, i, 1));}let mut coo = a.clone();coo.sort(); coo.dedup();let m = coo.len();let mut st = SegTree::new(m, |x, y| x + y, 0i64);let mut sta = SegTree::new(m, |x, y| x + y, 0i64);for i in 1..n + 1 {let idx = coo.binary_search(&a[i - 1]).unwrap();st.update(idx, st.query(idx, idx + 1) + 1);sta.update(idx, sta.query(idx, idx + 1) + a[i - 1]);for &(x, aidx, coef) in &qs[i] {let xidx = coo.lower_bound(&x);let tmp = x * st.query(xidx, m) + sta.query(0, xidx);ans[aidx] += tmp * coef;}}for i in 0..q {puts!("{}\n", ans[i]);}}