結果
問題 | No.2058 Binary String |
ユーザー | cureskol |
提出日時 | 2022-09-07 16:33:10 |
言語 | C++17 (gcc 12.3.0 + boost 1.83.0) |
結果 |
CE
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 4,184 bytes |
コンパイル時間 | 2,644 ms |
コンパイル使用メモリ | 217,652 KB |
最終ジャッジ日時 | 2024-11-15 02:42:39 |
合計ジャッジ時間 | 3,047 ms |
ジャッジサーバーID (参考情報) |
judge3 / judge4 |
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コンパイルエラー時のメッセージ・ソースコードは、提出者また管理者しか表示できないようにしております。(リジャッジ後のコンパイルエラーは公開されます)
ただし、clay言語の場合は開発者のデバッグのため、公開されます。
ただし、clay言語の場合は開発者のデバッグのため、公開されます。
コンパイルメッセージ
main.cpp: In instantiation of 'void fin(T) [with T = atcoder::static_modint<998244353>]': main.cpp:135:6: required from here main.cpp:93:27: error: no match for 'operator<<' (operand types are 'std::ostream' {aka 'std::basic_ostream<char>'} and 'atcoder::static_modint<998244353>') 93 | TYPE(T) void fin(T a){cout<<a<<endl;exit(0);} | ~~~~^~~ In file included from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/istream:39, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/sstream:38, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/complex:45, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ccomplex:39, from /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/x86_64-pc-linux-gnu/bits/stdc++.h:54, from main.cpp:3: /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:108:7: note: candidate: 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(__ostream_type& (*)(__ostream_type&)) [with _CharT = char; _Traits = std::char_traits<char>; __ostream_type = std::basic_ostream<char>]' 108 | operator<<(__ostream_type& (*__pf)(__ostream_type&)) | ^~~~~~~~ /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:108:36: note: no known conversion for argument 1 from 'atcoder::static_modint<998244353>' to 'std::basic_ostream<char>::__ostream_type& (*)(std::basic_ostream<char>::__ostream_type&)' {aka 'std::basic_ostream<char>& (*)(std::basic_ostream<char>&)'} 108 | operator<<(__ostream_type& (*__pf)(__ostream_type&)) | ~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~ /home/linuxbrew/.linuxbrew/Cellar/gcc@12/12.3.0/include/c++/12/ostream:117:7: note: candidate: 'std::basic_ostream<_CharT, _Traits>::__ostream_type& std::basic_ostream<_CharT, _Traits>::operator<<(__
ソースコード
#pragma region template #pragma GCC optimize("Ofast") #include <bits/stdc++.h> using namespace std; #ifdef __LOCAL #include <debug> #else #define debug(...) void(0) #endif using ll=long long; using ld=long double; using vi=vector<int>; using vll=vector<ll>; using pi=pair<int,int>; using pll=pair<ll,ll>; #define overload2(a,b,c,...) c #define overload3(a,b,c,d,...) d #define overload4(a,b,c,d,e,...) e #define overload5(a,b,c,d,e,f,...) f #define TYPE1(T) template<typename T> #define TYPE2(T,U) template<typename T,typename U> #define TYPE(...) overload2(__VA_ARGS__,TYPE2,TYPE1)(__VA_ARGS__) #define TYPES1(T) template<typename... T> #define TYPES2(H,T) template<typename H,typename... T> #define TYPES(...) overload2(__VA_ARGS__,TYPES2,TYPES1)(__VA_ARGS__) #define REP4(i,s,n,d) for(int i=(s);i<(n);i+=(d)) #define REP3(i,s,n) REP4(i,s,n,1) #define REP2(i,n) REP3(i,0,n) #define REP1(n) REP2(tomato,n) #define REP(...) overload4(__VA_ARGS__,REP4,REP3,REP2,REP1)(__VA_ARGS__) #define RREP4(i,s,n,d) for(int i=(n)-1;i>=s;i-=d) #define RREP3(i,s,n) RREP4(i,s,n,1) #define RREP2(i,n) RREP3(i,0,n) #define RREP1(n) RREP2(tomato,n) #define RREP(...) overload4(__VA_ARGS__,RREP4,RREP3,RREP2,RREP1)(__VA_ARGS__) #define ALL(v) v.begin(),v.end() #define RALL(v) v.rbegin(),v.rend() #define SORT(v) sort(ALL(v)) #define RSORT(v) sort(RALL(v)) #define REVERSE(v) reverse(ALL(v)) #define UNIQUE(v) SORT(v),v.erase(unique(ALL(v)),v.end()) TYPES(T) void input(T&... a){ (cin>>...>>a); } #define DECLARE(T,...) T __VA_ARGS__;input(__VA_ARGS__); #define INT(...) DECLARE(int,__VA_ARGS__) #define STR(...) DECLARE(string,__VA_ARGS__) #define LL(...) DECLARE(long long,__VA_ARGS__) #define CHR(...) DECLARE(char,__VA_ARGS__) #define DBL(...) DECLARE(double,__VA_ARGS__) #define VI(n,v) vi v(n);cin>>v; #define VLL(n,v) vll v(n);cin>>v; TYPE(T) istream&operator>>(istream&is,vector<T>&v){ for(auto&a:v)cin>>a; return is; } TYPE(T) ostream&operator<<(ostream&os,const vector<T>&v){ if(&os==&cerr)os<<"["; REP(i,v.size()){ os<<v[i]; if(i+1<v.size())os<<(&os==&cerr?",":" "); } if(&os==&cerr)os<<"]"; return os; } TYPE(T,S) istream&operator>>(istream&is,pair<T,S>&p){ cin>>p.first>>p.second; return is; } TYPE(T) using pq=priority_queue<T>; TYPE(T) using pqg=priority_queue<T,vector<T>,greater<T>>; TYPE(T) T pick(queue<T>& que){assert(que.size()); T a=que.front();que.pop();return a;} TYPE(T) T pick(pq<T>& que){assert(que.size()); T a=que.top();que.pop();return a;} TYPE(T) T pick(pqg<T>& que){assert(que.size()); T a=que.top();que.pop();return a;} TYPE(T) T pick(stack<T>& sta){assert(sta.size()); T a=sta.top();sta.pop();return a;} string YES(bool f=true){return (f?"YES":"NO");} string Yes(bool f=true){return (f?"Yes":"No");} string yes(bool f=true){return (f?"yes":"no");} constexpr int INF=1e9+7; constexpr ll LINF=ll(1e18)+7; constexpr ld EPS=1e-10; vi iota(int n){vi a(n);iota(ALL(a),0);return a;} TYPE(T) void fin(T a){cout<<a<<endl;exit(0);} TYPE(T) bool chmax(T &a,T b){return (a<b&&(a=b,true));} TYPE(T) bool chmin(T &a,T b){return (a>b&&(a=b,true));} TYPES(T,Ns) auto make_vector(T x,int n,Ns ...ns){ if constexpr(sizeof...(ns)==0)return vector<T>(n,x); else return vector(n,make_vector<T>(x,ns...)); } bool in(const ll S,const int a){return (S>>a)&1;} int popcount(const ll S){return __builtin_popcountll(S);} #pragma endregion template #include <atcoder/modint> #include <atcoder/convolution> using namespace atcoder; using mint=modint998244353; ostream& operator<<(ostream &os,mint a){os<<a.val();return os;} istream& operator>>(istream &is,mint &a){ long long b;is>>b;a=b; return is; } constexpr int SIZE=5000000; mint Factorial[SIZE],Finverse[SIZE]; void Cinit(){ Factorial[0]=mint(1); for(int i=1;i<SIZE;i++)Factorial[i]=Factorial[i-1]*mint(i); Finverse[SIZE-1]=Factorial[SIZE-1].inv(); for(int i=SIZE-2;i>=0;i--)Finverse[i]=mint(i+1)*Finverse[i+1]; } mint nCk(int n,int k){ if(Factorial[0]==0)Cinit(); if(n<k)return 0; return Factorial[n]*Finverse[n-k]*Finverse[k]; } int main(){ ios::sync_with_stdio(false); cin.tie(nullptr); INT(n,k); mint ans=0; REP(x,1,n)ans+=nCk(n-1,x)*mint(x).pow(k); fin(ans); }