結果
| 問題 |
No.2074 Product is Square ?
|
| コンテスト | |
| ユーザー |
taiga0629kyopro
|
| 提出日時 | 2022-09-16 22:06:59 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
TLE
|
| 実行時間 | - |
| コード長 | 2,576 bytes |
| コンパイル時間 | 334 ms |
| コンパイル使用メモリ | 82,048 KB |
| 実行使用メモリ | 155,776 KB |
| 最終ジャッジ日時 | 2024-12-21 20:53:57 |
| 合計ジャッジ時間 | 32,571 ms |
|
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 28 TLE * 5 |
ソースコード
# https://old.yosupo.jp/submission/90839
from random import randrange
def gcd(a, b):
while a:
a, b = b%a, a
return b
def is_prime(n):
if n == 2:
return 1
if n == 1 or n%2 == 0:
return 0
m = n - 1
lsb = m & -m
s = lsb.bit_length()-1
d = m // lsb
if n < 4759123141:
test_numbers = [2, 7, 61]
elif n < 341550071728321:
test_numbers = [2, 3, 5, 7, 11, 13, 17]
elif n < 3825123056546413051:
test_numbers = [2, 3, 5, 7, 11, 13, 17, 19, 23]
else:
test_numbers = [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37]
for a in test_numbers:
if a == n:
continue
x = pow(a,d,n)
r = 0
if x == 1:
continue
while x != m:
x = pow(x,2,n)
r += 1
if x == 1 or r == s:
return 0
return 1
def find_prime_factor(n):
m = max(1,int(n**0.125))
while True:
c = randrange(n)
y = k = 0
g = q = r = 1
while g == 1:
x = y
mr = 3*r//4
while k < mr:
y = (pow(y,2,n)+c)%n
k += 1
while k < r and g == 1:
ys = y
for _ in range(min(m, r-k)):
y = (pow(y,2,n)+c)%n
q = q*abs(x-y)%n
g = gcd(q,n)
k += m
k = r
r <<= 1
if g == n:
g = 1
y = ys
while g == 1:
y = (pow(y,2,n)+c)%n
g = gcd(abs(x-y),n)
if g == n:
continue
if is_prime(g):
return g
elif is_prime(n//g):
return n//g
else:
return find_prime_factor(g)
def factorize(n):
res = {}
for p in range(2,1000):
if p*p > n:
break
if n%p:
continue
s = 0
while n%p == 0:
n //= p
s += 1
res[p] = s
while not is_prime(n) and n > 1:
p = find_prime_factor(n)
s = 0
while n%p == 0:
n //= p
s += 1
res[p] = s
if n > 1:
res[n] = 1
return res
T=int(input())
from collections import defaultdict
for iii in range(T):
n=int(input())
a=list(map(int,input().split()))
ans=defaultdict(int)
for x in a:
pri=factorize(x)
for p in pri:ans[p]+=pri[p]
flag=1
for p in ans:
if ans[p]%2==1:flag=0
print("Yes" if flag else "No")
taiga0629kyopro