結果
問題 | No.754 畳み込みの和 |
ユーザー |
|
提出日時 | 2022-09-20 18:38:19 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 26 ms / 5,000 ms |
コード長 | 3,070 bytes |
コンパイル時間 | 2,038 ms |
コンパイル使用メモリ | 198,548 KB |
最終ジャッジ日時 | 2025-02-07 13:06:15 |
ジャッジサーバーID (参考情報) |
judge3 / judge1 |
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ファイルパターン | 結果 |
---|---|
other | AC * 3 |
ソースコード
#include <bits/stdc++.h>#include <complex>#include <random>using namespace std;//#include <atcoder/all>//using namespace atcoder;using ll = long long;using vll = vector<ll>;using vvll = vector<vll>;using vvvll = vector<vvll>;using vvvvll = vector<vvvll>;using vvvvvll = vector<vvvvll>;using vvvvvvll = vector<vvvvvll>;using vb = vector<bool>;using vvb = vector<vb>;using vvvb = vector<vvb>;using vvvvb = vector<vvvb>;using vd = vector<double>;using vvd = vector<vd>;using vvvd = vector<vvd>;using vvvvd = vector<vvvd>;using vvvvvd = vector<vvvvd>;#define all(A) A.begin(),A.end()#define ALL(A) A.begin(),A.end()#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)using pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;#define tN(t) (t==1?XN:YN)#define tS(t) (t==1?XS:YS)#define tA(t) (t==1?XA:YA)template<class T>bool chmax(T& p, T q, bool C = 1) {if (C == 0 && p == q) {return 1;}if (p < q) {p = q;return 1;}else {return 0;}}template<class T>bool chmin(T& p, T q, bool C = 1) {if (C == 0 && p == q) {return 1;}if (p > q) {p = q;return 1;}else {return 0;}}ll gcd(ll(a), ll(b)) {if (b == 0)return a;ll c = a;while (a % b != 0) {c = a % b;a = b;b = c;}return b;}ll sqrtz(ll N) {ll L = 0;ll R = sqrt(N)+10000;while (abs(R - L) > 1) {ll mid = (R +L) / 2;if (mid * mid <= N)L = mid;else R = mid;}return L;}vector<ll> fact, factinv, inv;ll mod = 998244353;void prenCkModp(ll n) {fact.resize(n + 5);factinv.resize(n + 5);inv.resize(n + 5);fact.at(0) = fact.at(1) = 1;factinv.at(0) = factinv.at(1) = 1;inv.at(1) = 1;for (ll i = 2; i < n + 5; i++) {fact.at(i) = (fact.at(i - 1) * i) % mod;inv.at(i) = mod - (inv.at(mod % i) * (mod / i)) % mod;factinv.at(i) = (factinv.at(i - 1) * inv.at(i)) % mod;}}ll nCk(ll n, ll k) {if (n < k) return 0;return fact.at(n) * (factinv.at(k) * factinv.at(n - k) % mod) % mod;}/*ll modPow(long long a, long long n, long long p) {if (n == 0) return 1; // 0乗にも対応する場合if (n == 1) return a % p;if (n % 2 == 1) return (a * modPow(a, n - 1, p)) % p;long long t = modPow(a, n / 2, p);return (t * t) % p;}*/ll modPow(ll a, ll n, ll p) {ll res = 1;ll k = a;while (n > 0) {if (n % 2 == 1) {res *= k;if (res > p)res %= p;}k = k * k;if (k > p)k %= p;n /= 2;}return res;}int main() {cin.tie(nullptr);ios::sync_with_stdio(false);ll N,M=1e9+7;;cin>>N;vll A(N+1),B(N+1);rep(i,N+1)cin>>A[i];rep(i,N+1)cin>>B[i];//rep(i,N)A[i+1]+=A[i];rep(i,N)B[i+1]+=B[i];ll an=0;rep(i,N+1){an+=(A[i]%M)*(B[N-i]%M);an%=M;//21 14 22}cout<<an<<endl;}