結果
問題 | No.189 SUPER HAPPY DAY |
ユーザー |
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提出日時 | 2022-09-21 19:32:38 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 12 ms / 5,000 ms |
コード長 | 3,092 bytes |
コンパイル時間 | 5,511 ms |
コンパイル使用メモリ | 274,068 KB |
最終ジャッジ日時 | 2025-02-07 13:24:25 |
ジャッジサーバーID (参考情報) |
judge2 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 23 |
ソースコード
#include <bits/stdc++.h>#include <atcoder/all>#include <ext/pb_ds/assoc_container.hpp>#include <ext/pb_ds/tree_policy.hpp>using namespace std;using namespace __gnu_pbds;template <typename T>using ordered_set =tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;struct __INIT{__INIT(){cin.tie(0);ios::sync_with_stdio(false);cout<<fixed<<setprecision(15);}} __init;#define REP(i,n) for(ll i=0;i<ll(n);i++)#define REPD(i,n) for(ll i=n-1;i>=0;i--)#define FOR(i,a,b) for(ll i=a;i<=ll(b);i++)#define FORD(i,a,b) for(ll i=a;i>=ll(b);i--)#define overload4(_1,_2,_3,_4,name,...) name#define overload3(_1,_2,_3,name,...) name#define rep1(n) for(ll i=0;i<n;++i)#define rep2(i,n) for(ll i=0;i<n;++i)#define rep3(i,a,b) for(ll i=a;i<b;++i)#define rep4(i,a,b,c) for(ll i=a;i<b;i+=c)#define rep(...) overload4(__VA_ARGS__,rep4,rep3,rep2,rep1)(__VA_ARGS__)#define rrep1(n) for(ll i=n;i--;)#define rrep2(i,n) for(ll i=n;i--;)#define rrep3(i,a,b) for(ll i=b;i-->(a);)#define rrep4(i,a,b,c) for(ll i=(a)+((b)-(a)-1)/(c)*(c);i>=(a);i-=c)#define rrep(...) overload4(__VA_ARGS__,rrep4,rrep3,rrep2,rrep1)(__VA_ARGS__)#define ALL(v) v.begin(), v.end()#define endl "\n"#define fi first#define se second#define popcount(bit) __builtin_popcount(bit)#define popcountll(bit) __builtin_popcountll(bit)#define pb push_back#define eb emplace_back#define sz(x) ((ll)(x).size())using namespace atcoder;using P = pair<int, int>;using PL = pair<long long, long long>;using Graph = vector<vector<int>>;typedef long long ll;template<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }template<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }inline void Yes(bool b = true) { cout << (b ? "Yes" : "No") << '\n'; }inline void YES(bool b = true) { cout << (b ? "YES" : "NO") << '\n'; }inline void OKNG(bool b = true) { cout << (b ? "OK" : "NG") << '\n'; }const int dx[4] = {1, 0, -1, 0};const int dy[4] = {0, 1, 0, -1};const int fx[8] = {0, 1, 1, 1, 0, -1, -1, -1};const int fy[8] = {1, 1, 0, -1, -1, -1, 0, 1};template <typename T>const auto INF = numeric_limits<T>::max()/2;using mint = static_modint<1000000009>;mint dp1[203][1801][2];mint dp2[203][1801][2];int main() {string M, D;cin >> M >> D;int n = M.size();int m = D.size();dp1[0][0][0] = 1;dp2[0][0][0] = 1;rep(i, n)rep(j, 1801)rep(k, 2){if(dp1[i][j][k] == 0)continue;int nd = M[i] - '0';rep(d, 10){int nk = k;if(j + d > 1800)continue;if(k == 0){if(d < nd)nk = 1;if(d > nd)continue;}dp1[i+1][j + d][nk] += dp1[i][j][k];}}rep(i, m)rep(j, 1801)rep(k, 2){if(dp2[i][j][k] == 0)continue;int nd = D[i] - '0';rep(d, 10){int nk = k;if(k == 0){if(d < nd)nk = 1;if(d > nd)continue;}dp2[i+1][j + d][nk] += dp2[i][j][k];}}mint ans = 0;rep3(i, 1, 1801){ans += (dp1[n][i][0] + dp1[n][i][1]) * (dp2[m][i][0] + dp2[m][i][1]);}cout << ans.val() << endl;}