結果
| 問題 | No.3066 エリスリトール |
| ユーザー |
 ecottea
|
| 提出日時 | 2022-09-22 05:50:13 |
| 言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
| 結果 |
WA
|
| 実行時間 | - |
| コード長 | 64,344 bytes |
| コンパイル時間 | 4,864 ms |
| コンパイル使用メモリ | 255,568 KB |
| 実行使用メモリ | 10,696 KB |
| 最終ジャッジ日時 | 2024-06-01 17:47:44 |
| 合計ジャッジ時間 | 8,276 ms |
|
ジャッジサーバーID （参考情報） |
judge4 / judge3 |
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テストケース
テストケース表示| 入力 | 結果 | 実行時間 実行使用メモリ |
|---|---|---|
| testcase_00 | AC | 4 ms
5,248 KB |
| testcase_01 | AC | 4 ms
5,248 KB |
| testcase_02 | AC | 4 ms
5,248 KB |
| testcase_03 | AC | 4 ms
5,376 KB |
| testcase_04 | AC | 4 ms
5,376 KB |
| testcase_05 | AC | 4 ms
5,376 KB |
| testcase_06 | AC | 41 ms
8,992 KB |
| testcase_07 | WA | - |
| testcase_08 | WA | - |
| testcase_09 | AC | 41 ms
9,092 KB |
| testcase_10 | WA | - |
| testcase_11 | WA | - |
| testcase_12 | AC | 40 ms
9,104 KB |
| testcase_13 | AC | 41 ms
9,100 KB |
| testcase_14 | WA | - |
| testcase_15 | AC | 40 ms
8,992 KB |
| testcase_16 | AC | 42 ms
8,988 KB |
| testcase_17 | AC | 41 ms
8,992 KB |
| testcase_18 | AC | 41 ms
9,120 KB |
| testcase_19 | AC | 41 ms
9,192 KB |
| testcase_20 | WA | - |
| testcase_21 | AC | 41 ms
8,992 KB |
| testcase_22 | AC | 41 ms
8,992 KB |
| testcase_23 | AC | 41 ms
9,116 KB |
| testcase_24 | AC | 41 ms
9,116 KB |
| testcase_25 | AC | 40 ms
8,988 KB |
| testcase_26 | AC | 41 ms
9,120 KB |
| testcase_27 | WA | - |
| testcase_28 | WA | - |
| testcase_29 | AC | 40 ms
9,120 KB |
| testcase_30 | AC | 41 ms
8,992 KB |
| testcase_31 | AC | 41 ms
9,124 KB |
| testcase_32 | WA | - |
| testcase_33 | AC | 4 ms
5,376 KB |
| testcase_34 | AC | 4 ms
5,376 KB |
| testcase_35 | AC | 4 ms
5,376 KB |
ソースコード
#ifndef HIDDEN_IN_VS // 折りたたみ用
// 警告の抑制
#define _CRT_SECURE_NO_WARNINGS
// ライブラリの読み込み
#include <bits/stdc++.h>
using namespace std;
// 型名の短縮
using ll = long long; // -2^63 ～ 2^63 = 9 * 10^18（int は -2^31 ～ 2^31 = 2 * 10^9）
using pii = pair<int, int>; using pll = pair<ll, ll>; using pil = pair<int, ll>; using pli = pair<ll, int>;
using vi = vector<int>; using vvi = vector<vi>; using vvvi = vector<vvi>;
using vl = vector<ll>; using vvl = vector<vl>; using vvvl = vector<vvl>;
using vb = vector<bool>; using vvb = vector<vb>; using vvvb = vector<vvb>;
using vc = vector<char>; using vvc = vector<vc>; using vvvc = vector<vvc>;
using vd = vector<double>; using vvd = vector<vd>; using vvvd = vector<vvd>;
template <class T> using priority_queue_rev = priority_queue<T, vector<T>, greater<T>>;
using Graph = vvi;
// 定数の定義
const double PI = acos(-1);
const vi DX = { 1, 0, -1, 0 }; // 4 近傍（下，右，上，左）
const vi DY = { 0, 1, 0, -1 };
int INF = 1001001001; ll INFL = 4004004004004004004LL;
double EPS = 1e-12;
// 入出力高速化
struct fast_io { fast_io() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << fixed << setprecision(18); } } fastIOtmp;
// 汎用マクロの定義
#define all(a) (a).begin(), (a).end()
#define sz(x) ((int)(x).size())
#define lbpos(a, x) (int)distance((a).begin(), std::lower_bound(all(a), x))
#define ubpos(a, x) (int)distance((a).begin(), std::upper_bound(all(a), x))
#define Yes(b) {cout << ((b) ? "Yes\n" : "No\n");}
#define rep(i, n) for(int i = 0, i##_len = int(n); i < i##_len; ++i) // 0 から n-1 まで昇順
#define repi(i, s, t) for(int i = int(s), i##_end = int(t); i <= i##_end; ++i) // s から t まで昇順
#define repir(i, s, t) for(int i = int(s), i##_end = int(t); i >= i##_end; --i) // s から t まで降順
#define repe(v, a) for(const auto& v : (a)) // a の全要素（変更不可能）
#define repea(v, a) for(auto& v : (a)) // a の全要素（変更可能）
#define repb(set, d) for(int set = 0; set < (1 << int(d)); ++set) // d ビット全探索（昇順）
#define repp(a) sort(all(a)); for(bool a##_perm = true; a##_perm; a##_perm = next_permutation(all(a))) // a の順列全て（昇順）
#define smod(n, m) ((((n) % (m)) + (m)) % (m)) // 非負mod
#define uniq(a) {sort(all(a)); (a).erase(unique(all(a)), (a).end());} // 重複除去
#define EXIT(a) {cout << (a) << endl; exit(0);} // 強制終了
// 汎用関数の定義
template <class T> inline ll pow(T n, int k) { ll v = 1; rep(i, k) v *= n; return v; }
template <class T> inline bool chmax(T& M, const T& x) { if (M < x) { M = x; return true; } return false; } // 最大値を更新（更新されたら true を返す）
template <class T> inline bool chmin(T& m, const T& x) { if (m > x) { m = x; return true; } return false; } // 最小値を更新（更新されたら true を返す）
// 演算子オーバーロード
template <class T, class U> inline istream& operator>>(istream& is, pair<T, U>& p) { is >> p.first >> p.second; return is; }
template <class T> inline istream& operator>>(istream& is, vector<T>& v) { repea(x, v) is >> x; return is; }
template <class T> inline vector<T>& operator--(vector<T>& v) { repea(x, v) --x; return v; }
template <class T> inline vector<T>& operator++(vector<T>& v) { repea(x, v) ++x; return v; }
// 手元環境（Visual Studio）
#ifdef _MSC_VER
#include "local.hpp"
// 提出用（gcc）
#else
inline int popcount(int n) { return __builtin_popcount(n); }
inline int popcount(ll n) { return __builtin_popcountll(n); }
inline int lsb(int n) { return n != 0 ? __builtin_ctz(n) : -1; }
inline int lsb(ll n) { return n != 0 ? __builtin_ctzll(n) : -1; }
inline int msb(int n) { return n != 0 ? (31 - __builtin_clz(n)) : -1; }
inline int msb(ll n) { return n != 0 ? (63 - __builtin_clzll(n)) : -1; }
#define gcd __gcd
#define dump(...)
#define dumpel(v)
#define dump_list(v)
#define input_from_file(f)
#define output_to_file(f)
#define Assert(b) { if (!(b)) while (1) cout << "OLE"; }
#endif
#endif // 折りたたみ用
//--------------AtCoder 専用--------------
#include <atcoder/all>
using namespace atcoder;
using mint = modint1000000007;
//using mint = modint998244353;
//using mint = modint; // mint::set_mod(m);
istream& operator>>(istream& is, mint& x) { ll x_; is >> x_; x = x_; return is; }
ostream& operator<<(ostream& os, const mint& x) { os << x.val(); return os; }
using vm = vector<mint>; using vvm = vector<vm>; using vvvm = vector<vvm>;
//----------------------------------------
//【局面のニム値】O(?)（遅いので実験用）
/*
* 初期局面 p から遷移可能な局面とそのニム値のリストを nim に格納する．
* nxt(p, nps) を呼ぶと，p から遷移可能な局面のリストを nps に格納するものとする．
*/
template <class T>
void calc_nimber(const T& p, function<void(const T&, vector<T>&)>& nxt, map<T, int>& nim) {
nim.clear();
function<int(const T&)> calc_nimber = [&](const T& p) {
if (nim.count(p)) return nim[p];
vector<T> nps;
nxt(p, nps);
vi next_nimbers;
repe(np, nps) {
next_nimbers.push_back(calc_nimber(np));
}
uniq(next_nimbers);
int i = 0;
while (i < sz(next_nimbers) && next_nimbers[i] == i) i++;
nim[p] = i;
return nim[p];
};
calc_nimber(p);
}
void zikken() {
using T = vi;
function<void(const T&, vector<T>&)> nxt = [&](const T& p, vector<T>& nps) {
rep(i, sz(p)) {
if (p[i] == 1) continue;
if ((i == 0 || p[i - 1] == 1) && (i == sz(p) - 1 || p[i + 1] == 1)) {
T np(p);
np[i] = 1;
nps.push_back(np);
}
}
repi(i, 1, sz(p) - 2) {
if (p[i - 1] == 1 || p[i] == 1 || p[i + 1] == 1) continue;
T np1(p);
np1[i] = np1[i - 1] = 1;
nps.push_back(np1);
T np2(p);
np2[i] = np2[i + 1] = 1;
nps.push_back(np2);
}
};
repi(n, 0, 25) {
T p(n + 1);
p[0] = 1;
map<T, int> nim;
calc_nimber(p, nxt, nim);
dump(n, nim[p]);
}
exit(0);
repi(n, 0, 25) {
T p(n + 2);
p[0] = p[n + 1] = 1;
map<T, int> nim;
calc_nimber(p, nxt, nim);
dump(n, nim[p]);
}
exit(0);
}
/*
片側の開いた長さ i の '0' の連
0 0
1 1
2 0
3 0
4 1
5 2
6 2
7 1
8 4
9 0
10 1
11 4
12 2
13 1
14 4
15 0
16 1
17 4
18 2
19 1
20 4
21 2
22 1
23 0
24 2
25 1
両側とも閉じた長さ i の '0' の連
0 0
1 1
2 0
3 0
4 1
5 2
6 2
7 1
8 4
9 0
10 1
11 4
12 2
13 1
14 4
15 0
16 1
17 4
18 2
19 1
20 4
21 2
22 1
23 0
24 2
25 1
http://oeis.org/A071430
Sprague-Grundy values for octal game .16
山から 1 つの石を取り除く場合，残る山の数を 0 にすることができる．
山から 2 つの石を取り除く場合，残る山の数を 1 または 2 にすることができる．
Sequence is eventually periodic with period 149459. The last exception is at n=105350.
*/
string TLE(int n, ll k, vl a) {
a.insert(a.begin(), 0);
a.push_back(k + 1);
chmax(k, 10LL);
vi dp(k + 1);
dp[0] = 0;
dp[1] = 1;
dp[2] = 0;
repi(i, 3, k) {
int set = 0;
repi(j, 0, (i - 2) / 2) {
set |= 1 << (dp[j] ^ dp[i - j - 2]);
}
dp[i] = lsb(~set);
}
dump(dp);
int res = 0;
rep(i, n + 1) {
ll w = a[i + 1] - a[i] - 1;
dump(w);
res ^= dp[w];
}
return res ? "Yes" : "No";
}
//【ランレングス符号】O(n)
/*
* a[0..n) をランレングス符号化し，結果を cls に格納する．
* cls[i] = {c, l} は前から i 番目の列が l 個の文字 c からなることを表す．
*/
template <class T>
void run_length_encodeing(const vector<T>& a, vector<pair<T, int>>& cls) {
// verify : https://atcoder.jp/contests/arc024/tasks/arc024_2
int n = sz(a);
cls.clear();
if (n == 0) return;
cls.push_back({ a[0], 1 });
// 今読んでいる文字の種類を記憶する．
T c = a[0];
repi(i, 1, n - 1) {
// 記憶している文字と同じ文字の場合
if (c == a[i]) {
// 列の長さを増やす．
cls.rbegin()->second++;
}
// 記憶している文字と異なる文字の場合
else {
// 新しい文字を記憶しておく．
c = a[i];
// 新たな列を追加する．
cls.push_back({ c, 1 });
}
}
}
void umekomi() {
auto start = chrono::system_clock::now();
int k = 149459 + 105350 + 10;
k = k / 3 * 3;
// k = 1002; // デバッグ用
vi dp(k);
dp[0] = 0;
dp[1] = 1;
dp[2] = 0;
repi(i, 3, k - 1) {
int set = 0;
repi(j, 0, (i - 2) / 2) {
set |= 1 << (dp[j] ^ dp[i - j - 2]);
}
dp[i] = lsb(~set);
}
// dump(dp);
rep(i, k) {
if (14 <= dp[i] && dp[i] <= 17) dp[i] -= 4;
else if (22 <= dp[i] && dp[i] <= 23) dp[i] -= 8;
}
vi dp3(k / 3);
rep(i, k / 3) dp3[i] = ((dp[3 * i] * 16) + dp[3 * i + 1]) * 16 + dp[3 * i + 2];
// dump(dp3);
vector<pii> cls;
run_length_encodeing(dp3, cls);
// dump(cls);
cout << "string s = R\"(";
repe(cl, cls) {
int c, l;
tie(c, l) = cl;
char c1 = ':' + c / 64;
char c2 = ':' + c % 64;
cout << c1 << c2;
if (l >= 2) cout << l;
}
cout << "~)\";" << endl;
auto now = chrono::system_clock::now();
auto msec = chrono::duration_cast<std::chrono::milliseconds>(now - start).count();
dump(msec);
exit(0);
}
/*
24859 (25秒で終わった)
*/
const char* s = 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string solve(int n, ll k, vl a) {
vi dp;
int i = 0;
while (s[i] != '~') {
int c1 = s[i++] - ':';
int c2 = s[i++] - ':';
int c = c1 * 64 + c2;
int l = 0;
while (s[i] <= '9') l = l * 10 + s[i++] - '0';
if (l == 0) l = 1;
int d0 = c / 16 / 16;
int d1 = c / 16 % 16;
int d2 = c % 16;
rep(hoge, l) {
dp.emplace_back(d0);
dp.emplace_back(d1);
dp.emplace_back(d2);
}
}
dump(dp);
rep(i, sz(dp)) {
if (14 - 4 <= dp[i] && dp[i] <= 17 - 4) dp[i] += 4;
else if (22 - 8 <= dp[i] && dp[i] <= 23 - 8) dp[i] += 8;
}
dump(dp);
a.insert(a.begin(), 0);
a.push_back(k + 1);
int res = 0;
rep(i, n + 1) {
ll w = a[i + 1] - a[i] - 1;
dump(w);
if (w >= sz(dp)) {
w = (w - 105350) % 149459 + 105350;
}
res ^= dp[w];
}
return res ? "Yes" : "No";
}
int main() {
// input_from_file("input.txt");
// output_to_file("output.txt");
// umekomi();
int n; ll k;
cin >> n >> k;
vl a(n);
cin >> a;
cout << solve(n, k, a) << endl;
}