結果
問題 | No.1996 <>< |
ユーザー | au7777 |
提出日時 | 2022-09-22 17:53:32 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 521 ms / 2,000 ms |
コード長 | 3,294 bytes |
コンパイル時間 | 4,339 ms |
コンパイル使用メモリ | 246,724 KB |
実行使用メモリ | 36,480 KB |
最終ジャッジ日時 | 2024-06-01 17:59:43 |
合計ジャッジ時間 | 11,191 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 38 ms
36,224 KB |
testcase_01 | AC | 37 ms
36,224 KB |
testcase_02 | AC | 37 ms
36,096 KB |
testcase_03 | AC | 37 ms
36,224 KB |
testcase_04 | AC | 37 ms
36,224 KB |
testcase_05 | AC | 38 ms
36,096 KB |
testcase_06 | AC | 37 ms
36,224 KB |
testcase_07 | AC | 37 ms
36,352 KB |
testcase_08 | AC | 37 ms
36,224 KB |
testcase_09 | AC | 36 ms
36,224 KB |
testcase_10 | AC | 37 ms
36,352 KB |
testcase_11 | AC | 178 ms
36,352 KB |
testcase_12 | AC | 411 ms
36,352 KB |
testcase_13 | AC | 521 ms
36,224 KB |
testcase_14 | AC | 493 ms
36,480 KB |
testcase_15 | AC | 432 ms
36,480 KB |
testcase_16 | AC | 366 ms
36,352 KB |
testcase_17 | AC | 452 ms
36,224 KB |
testcase_18 | AC | 222 ms
36,096 KB |
testcase_19 | AC | 271 ms
36,352 KB |
testcase_20 | AC | 260 ms
36,224 KB |
testcase_21 | AC | 365 ms
36,480 KB |
testcase_22 | AC | 438 ms
36,352 KB |
testcase_23 | AC | 45 ms
36,224 KB |
testcase_24 | AC | 221 ms
36,224 KB |
testcase_25 | AC | 106 ms
36,224 KB |
testcase_26 | AC | 168 ms
36,096 KB |
testcase_27 | AC | 51 ms
36,096 KB |
testcase_28 | AC | 37 ms
36,224 KB |
testcase_29 | AC | 99 ms
36,096 KB |
testcase_30 | AC | 39 ms
36,352 KB |
testcase_31 | AC | 53 ms
36,224 KB |
testcase_32 | AC | 38 ms
36,224 KB |
ソースコード
#include <bits/stdc++.h> #include <atcoder/all> typedef long long int ll; using namespace std; using namespace atcoder; typedef pair<ll, ll> P; #define loop(i,n) for(int i=0;i<n;i++) template<typename T> using min_priority_queue = priority_queue<T, vector<T>, greater<T>>; // const ll MOD = 998244353; // using mint = modint998244353; const ll MOD = 1000000007; using mint = modint1000000007; const int MAX = 2000005; long long fac[MAX], finv[MAX], inv[MAX]; void COMinit() { fac[0] = fac[1] = 1; finv[0] = finv[1] = 1; inv[1] = 1; for (int i = 2; i < MAX; i++){ fac[i] = fac[i - 1] * i % MOD; inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD; finv[i] = finv[i - 1] * inv[i] % MOD; } } long long COM(int n, int k){ if (n < k) return 0; if (n < 0 || k < 0) return 0; return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD; } ll gcd(ll x, ll y) { if (y == 0) return x; else if (y > x) { return gcd (y, x); } else return gcd(x % y, y); } ll lcm(ll x, ll y) { return x / gcd(x, y) * y; } ll my_sqrt(ll x) { ll m = 0; ll M = 3000000001; while (M - m > 1) { ll now = (M + m) / 2; if (now * now <= x) { m = now; } else { M = now; } } return m; } ll keta(ll n, ll hou) { ll ret = 0; while (n) { n /= hou; ret++; } return ret; } ll ceil(ll n, ll m) { // n > 0, m > 0 ll ret = n / m; if (n % m) ret++; return ret; } ll pow_ll(ll x, ll n) { if (n == 0) return 1; if (n % 2) { return pow_ll(x, n - 1) * x; } else { ll tmp = pow_ll(x, n / 2); return tmp * tmp; } } vector<ll> compress(vector<ll>& v) { // [3 5 5 6 1 1 10 1] -> [1 2 2 3 0 0 4 0] vector<ll> u = v; sort(u.begin(), u.end()); u.erase(unique(u.begin(),u.end()),u.end()); map<ll, ll> mp; for (int i = 0; i < u.size(); i++) { mp[u[i]] = i; } for (int i = 0; i < v.size(); i++) { v[i] = mp[v[i]]; } return v; } mint op(mint a, mint b) { return a + b; } mint e() { return 0; } mint dp[1501][1501]; int main() { for (int i = 0; i <=1500; i++) { for (int j = 0; j <= 1500; j++) { dp[i][j] = false; } } ll n, k; cin >> n >> k; vector<ll> a(n); for (int i = 0; i < n; i++) cin >> a[i]; compress(a); string s; cin >> s; using tree = segtree<mint, op, e>; tree forest[1501]; for (int i = 0; i <= 1500; i++) { tree treei(1501); forest[i] = treei; } for (int i = 0; i < n; i++) { // j = 0 に追加 dp[i][0] = 1; forest[0].set(a[i], forest[0].get(a[i]) + 1); for (int j = 1; j <= k; j++) { if (s[j - 1] == '<') { // a[i]未満の合計 dp[i][j] = forest[j - 1].prod(0, a[i]); } else { dp[i][j] = forest[j - 1].prod(a[i] + 1, 1501); } forest[j].set(a[i], forest[j].get(a[i]) + dp[i][j]); // cout << i << ' ' << j << ' ' << dp[i][j].val() << endl; } } mint ans = 0; for (int i = 0; i < n; i++) { ans += dp[i][k]; } cout << ans.val() << endl; return 0; }