結果
問題 | No.2080 Simple Nim Query |
ユーザー | woodywoody |
提出日時 | 2022-09-25 21:26:45 |
言語 | C++14 (gcc 12.3.0 + boost 1.83.0) |
結果 |
AC
|
実行時間 | 402 ms / 3,000 ms |
コード長 | 4,272 bytes |
コンパイル時間 | 4,567 ms |
コンパイル使用メモリ | 236,508 KB |
実行使用メモリ | 14,720 KB |
最終ジャッジ日時 | 2024-06-12 07:22:10 |
合計ジャッジ時間 | 6,985 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,376 KB |
testcase_02 | AC | 2 ms
5,376 KB |
testcase_03 | AC | 114 ms
5,376 KB |
testcase_04 | AC | 127 ms
5,376 KB |
testcase_05 | AC | 402 ms
14,720 KB |
testcase_06 | AC | 241 ms
7,168 KB |
testcase_07 | AC | 240 ms
7,168 KB |
testcase_08 | AC | 328 ms
12,800 KB |
testcase_09 | AC | 327 ms
12,800 KB |
testcase_10 | AC | 163 ms
5,376 KB |
ソースコード
// #define _GLIBCXX_DEBUG #include<bits/stdc++.h> #include<atcoder/all> #define rep(i,b) for(int i=0;i<b;i++) #define rrep(i,b) for(int i=b-1;i>=0;i--) #define rep1(i,b) for(int i=1;i<b;i++) #define repx(i,x,b) for(int i=x;i<b;i++) #define rrepx(i,x,b) for(int i=b-1;i>=x;i--) #define fore(i,a) for(auto i:a) #define fore1(i,a) for(auto &i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>; template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; } template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; } template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return 1;} else {cout << "No" << endl; return 0;}} #define dame { cout << "No" << endl; return 0;} #define dame1 { cout << -1 << endl; return 0;} #define test(x) cout << "test" << x << endl; #define deb(x,y) cout << x << " " << y << endl; #define debp(p) cout << p.fi << " " << p.se << endl; #define deb3(x,y,z) cout << x << " " << y << " " << z << endl; #define deb4(x,y,z,x2) cout << x << " " << y << " " << z << " " << x2 << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define show(x) cerr<<#x<<" = "<<x<<endl; #define showdeb(x,y) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<endl; #define showv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define showv2(v) fore(vy , v) cout << vy << "\n"; #define showvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define showvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>; using tp = tuple<int ,int ,int>; using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>; using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>; using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>; using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>; using mint = modint998244353; using vm = vector<mint>; using vvm = vector<vector<mint>>; vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<<endl;} #define yesr { cout <<"Yes"<<endl; return 0;} #define no {cout <<"No"<<endl;} #define nor { cout <<"No"<<endl; return 0;} const double eps = 1e-10; const ll LINF = 1001002003004005006ll; const int INF = 1001001001; void solve(){ int n,q; cin>>n>>q; vector<char> ans; vl a(n); rep(i,n) cin>>a[i]; set<int> se; rep(i,n) if (a[i] >= 2) se.insert(i); rep(i,q){ int t,x,y; cin>>t>>x>>y; x--; if (t == 1){ if (a[x] == 1){ if (y == 1) continue; else{ se.insert(x); a[x] = y; } }else{ if (y == 1){ se.erase(x); a[x] = y; }else continue; } }else{ y--; auto it = se.upper_bound(y); int k; if (it == se.begin()){ k = y - x + 1; }else{ it--; int l = *it; chmax(l , x); k = y - l + 1; } if (k%2 == 0){ ans.pb('S'); }else{ ans.pb('F'); } } } outv; return; } int main(){ solve(); return 0; }