結果

問題 No.2095 High Rise
コンテスト
ユーザー SnowBeenDiding
提出日時 2022-10-07 22:12:50
言語 C++23
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 435 ms / 2,000 ms
コード長 6,505 bytes
コンパイル時間 5,973 ms
コンパイル使用メモリ 327,180 KB
実行使用メモリ 109,916 KB
最終ジャッジ日時 2024-06-12 18:52:29
合計ジャッジ時間 9,323 ms
ジャッジサーバーID
（参考情報） 		judge3 / judge5
このコードへのチャレンジ
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ファイルパターン 結果
sample AC * 3
other AC * 24
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include <atcoder/all>
using namespace atcoder;
// using mint = modint1000000007;
using mint = modint998244353;
// using mint = modint;//mint::set_mod(MOD);

// const long long MOD = 1000000007;
const long long MOD = 998244353;

#include <bits/stdc++.h>
#define rep(i, a, b) for (ll i = (ll)(a); i < (ll)(b); i++)
#define repeq(i, a, b) for (ll i = (ll)(a); i <= (ll)(b); i++)
#define repreq(i, a, b) for (ll i = (ll)(a); i >= (ll)(b); i--)
#define each(a, b) for (auto &(a) : (b))
#define endl '\n'  // fflush(stdout);
#define cYes cout << "Yes" << endl
#define cNo cout << "No" << endl
#define sortr(v) sort(v, greater<>())
#define pb push_back
#define mp make_pair
#define mt make_tuple
#define tget(a, b) get<b>(a)
#define FI first
#define SE second
#define ALL(v) (v).begin(), (v).end()
#define INFLL 3000000000000000100LL
#define INF 1000000100
#define PI acos(-1.0L)
#define TAU (PI * 2.0L)

using namespace std;

typedef long long ll;
typedef pair<ll, ll> Pll;
typedef tuple<ll, ll, ll> Tlll;
typedef vector<int> Vi;
typedef vector<Vi> VVi;
typedef vector<ll> Vl;
typedef vector<Vl> VVl;
typedef vector<VVl> VVVl;
typedef vector<Tlll> VTlll;
typedef vector<mint> Vm;
typedef vector<Vm> VVm;
typedef vector<string> Vs;
typedef vector<double> Vd;
typedef vector<char> Vc;
typedef vector<bool> Vb;
typedef vector<Pll> VPll;
typedef priority_queue<ll> PQl;
typedef priority_queue<ll, vector<ll>, greater<ll>> PQlr;

/* print */
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &V) {
    int N = V.size();
    if (N == 0) {
        os << endl;
        return os;
    }
    rep(i, 0, N - 1) { os << V[i] << ' '; }
    os << V[N - 1] << endl;
    return os;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<vector<T>> &V) {
    int N = V.size();
    rep(i, 0, N) os << V[i];
    return os;
}
template <typename T, typename S>
ostream &operator<<(ostream &os, pair<T, S> const &P) {
    os << P.FI << ' ' << P.SE;
    return os;
}
ostream &operator<<(ostream &os, mint const &M) {
    os << M.val();
    return os;
}

/* useful */
template <typename T>
void Vin(vector<T> &v) {
    int n = v.size();
    rep(i, 0, n) cin >> v[i];
}
template <typename T>
int SMALLER(vector<T> &a, T x) {
    return lower_bound(a.begin(), a.end(), x) - a.begin();
}
template <typename T>
int orSMALLER(vector<T> &a, T x) {
    return upper_bound(a.begin(), a.end(), x) - a.begin();
}
template <typename T>
int BIGGER(vector<T> &a, T x) {
    return a.size() - orSMALLER(a, x);
}
template <typename T>
int orBIGGER(vector<T> &a, T x) {
    return a.size() - SMALLER(a, x);
}
template <typename T>
int COUNT(vector<T> &a, T x) {
    return upper_bound(ALL(a), x) - lower_bound(ALL(a), x);
}
template <typename T, typename S>
bool chmax(T &a, S b) {
    if (a < b) {
        a = b;
        return 1;
    }
    return 0;
}
template <typename T, typename S>
bool chmin(T &a, S b) {
    if (a > b) {
        a = b;
        return 1;
    }
    return 0;
}
template <typename T>
void press(T &v) {
    v.erase(unique(ALL(v)), v.end());
}
template <typename T>
vector<int> zip(vector<T> b) {
    pair<T, int> p[b.size() + 10];
    int a = b.size();
    vector<int> l(a);
    for (int i = 0; i < a; i++) p[i] = mp(b[i], i);
    sort(p, p + a);
    int w = 0;
    for (int i = 0; i < a; i++) {
        if (i && p[i].first != p[i - 1].first) w++;
        l[p[i].second] = w;
    }
    return l;
}
template <typename T>
vector<T> vis(vector<T> &v) {
    vector<T> S(v.size() + 1);
    rep(i, 1, S.size()) S[i] += v[i - 1] + S[i - 1];
    return S;
}

ll dem(ll a, ll b) { return ((a + b - 1) / (b)); }
ll dtoll(double d, int g) { return round(d * pow(10, g)); }

const double EPS = 1e-10;

void init() {
    cin.tie(0);
    cout.tie(0);
    ios::sync_with_stdio(0);
    cout << fixed << setprecision(12);
}

// do {} while (next_permutation(ALL(vec)));
// for (auto p : se ) {}

/********************************** START **********************************/

template <typename T>
struct graph {
    struct edge {
        int to;
        T cost;
    };
    int N;
    vector<vector<edge>> G;
    vector<T> dist;
    vector<int> prever;

    graph(int n) { init(n); }
    T inf() {
        if (is_same_v<T, int>)
            return T(INF);
        else
            return T(INFLL);
    }
    T zero() { return T(0); }

    void init(int n) {
        N = n;
        G.resize(N);
        dist.resize(N, inf());
    }
    void add_edge(int s, int t, T cost) {
        edge e;
        e.to = t, e.cost = cost;
        G[s].push_back(e);
    }
    void dijkstra(int s) {
        rep(i, 0, N) dist[i] = inf();
        prever = vector<int>(N, -1);
        dist[s] = zero();
        priority_queue<pair<T, int>, vector<pair<T, int>>,
                       greater<pair<T, int>>>
            q;
        q.push(mp(zero(), s));
        while (!q.empty()) {
            int now;
            T nowdist;
            tie(nowdist, now) = q.top();
            q.pop();
            if (dist[now] < nowdist) continue;
            for (auto e : G[now]) {
                if (dist[e.to] > dist[now] + e.cost) {
                    prever[e.to] = now;
                    dist[e.to] = dist[now] + e.cost;
                    q.push(mp(dist[e.to], e.to));
                }
            }
        }
    }

    vector<int> get_path(int t) {  // tへの最短路構築
        if (dist[t] >= inf()) return {-1};
        vector<int> path;
        for (; t != -1; t = prever[t]) {
            path.push_back(t);
        }
        reverse(path.begin(), path.end());
        return path;
    }
};

void sol() {
    int h, w;
    cin >> h >> w;
    VVl a(h, Vl(w));
    rep(i, 0, h) rep(j, 0, w) cin >> a[i][j];
    if (h == 1) {
        cout << 0 << endl;
        return;
    }
    graph<ll> gr(h * w + 2010);
    int s = h * w + 2000;
    int t = h * w + 2001;
    rep(i, 0, w) {
        gr.add_edge(s, i, 0);
        // gr.add_edge(i + w * (h - 1), t, 0);
    }
    Vl yo(h);
    rep(i, 0, h) yo[i] = h * w + i;
    rep(i, 0, h) {
        rep(j, 0, w) {
            int nw = w * i + j;
            int ue = nw + w;
            if (ue < h * w) {
                gr.add_edge(nw, ue, a[i][j]);
            } else {
                gr.add_edge(nw, t, a[i][j]);
            }
            gr.add_edge(nw, yo[i], a[i][j]);
            gr.add_edge(yo[i], nw, 0);
        }
    }
    gr.dijkstra(s);
    cout << gr.dist[t] << endl;
}

int main() {
    init();
    int q = 1;
    // cin >> q;
    while (q--) sol();
    return 0;
}
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