結果

問題 No.2101 [Cherry Alpha N] ずっとこの数列だったらいいのに
ユーザー aaaaaaaaaa2230
提出日時 2022-10-15 00:00:37
言語 PyPy3
(7.3.15)
結果
AC  
実行時間 3,796 ms / 6,000 ms
コード長 3,493 bytes
コンパイル時間 180 ms
コンパイル使用メモリ 82,476 KB
実行使用メモリ 210,108 KB
最終ジャッジ日時 2024-06-26 18:14:45
合計ジャッジ時間 110,560 ms
ジャッジサーバーID
（参考情報） 		judge4 / judge3
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ファイルパターン 結果
other AC * 42
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

class SegTree:
    """ define what you want to do with 0 index, ex) size = tree_size, func = min or max, sta = default_value """
    
    def __init__(self,size,func,sta):
        self.n = size
        self.size = 1 << size.bit_length()
        self.func = func
        self.sta = sta
        self.tree = [sta]*(2*self.size)
    def build(self, list):
        """ set list and update tree"""
        for i,x in enumerate(list,self.size):
            self.tree[i] = x
        for i in range(self.size-1,0,-1):
            self.tree[i] = self.func(self.tree[i<<1],self.tree[i<<1 | 1])
    def set(self,i,x):
        i += self.size
        self.tree[i] = x
        while i > 1:
            i >>= 1
            self.tree[i] = self.func(self.tree[i<<1],self.tree[i<<1 | 1])
    
    def get(self,l,r):
        """ take the value of [l r) with func (min or max)"""
        l += self.size
        r += self.size
        res = self.sta
        while l < r:
            if l & 1:
                res = self.func(self.tree[l],res)
                l += 1
            if r & 1:
                res = self.func(self.tree[r-1],res)
            l >>= 1
            r >>= 1
        return res
    def max_right(self, l, x):
        """[l,r) が ok であるような最大の r を返す"""
        if l == self.n:
            return l
        l += self.size
        res = self.sta
        check = True
        while check or (l & -l) != l:
            check = False
            while l%2 == 0:
                l >>= 1
            if not self.func(res,self.tree[l]) < x:
                while l < self.size:
                    l <<= 1
                    if self.func(res,self.tree[l]) < x:
                        res = self.func(res,self.tree[l])
                        l += 1
                return l - self.size
            res = self.func(res,self.tree[l])
            l += 1
        return self.n
    def min_left(self, r, x):
        """(r が ok であるような最小の r を返す probably wrong"""
        if r == 0:
            return 0
        r += self.size
        res = self.sta
        check = True
        while check and (r & -r) != r:
            check = False
            r -= 1
            while (r > 1 and r%2):
                r >>= 1
            if not self.func(res, self.tree[r]) < x:
                while r < self.size:
                    r = 2*r + 1
                    if self.func(res, self.tree[r]) < x:
                        res = self.func(res, self.tree[r])
                        r -= 1
                return r + 1 - self.size
            res = self.func(self.tree[r],res)
        return 0
def func(x,y):
    return x+y
n = int(input())
AT = [list(map(int,input().split())) for i in range(n)]
A = [a for a,t in AT]
q = int(input())
DLR = [list(map(int,input().split())) for i in range(q)]
ans = [0]*q
event = []
for i,(a,t) in enumerate(AT):
    if a == 0:
        continue
    event.append([t,-1,i,0])
    event.append([t+a,-2,i,0])
for i,(d,l,r) in enumerate(DLR):
    event.append([d,i,l,r])
seg1 = SegTree(n,func,0)
seg3 = SegTree(n,func,0)
seg4 = SegTree(n,func,0)
seg1.build([a for a,t in AT])
event.sort()
for day,ind,x,y in event:
    if ind == -1:
        seg3.set(x,1)
        seg4.set(x,day)
    elif ind == -2:
        seg1.set(x,0)
        seg3.set(x,0)
        seg4.set(x,0)
    else:
        l,r = x-1,y
        count = seg1.get(l,r) -seg3.get(l,r)*(day+1) + seg4.get(l,r)
        ans[ind] = count
for i in ans:
    print(i)    
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