結果
| 問題 | No.2101 [Cherry Alpha N] ずっとこの数列だったらいいのに |
| ユーザー |
|
| 提出日時 | 2022-10-15 00:13:47 |
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 701 ms / 6,000 ms |
| コード長 | 7,874 bytes |
| コンパイル時間 | 1,609 ms |
| コンパイル使用メモリ | 131,380 KB |
| 実行使用メモリ | 39,108 KB |
| 最終ジャッジ日時 | 2024-06-26 18:19:23 |
| 合計ジャッジ時間 | 28,519 ms |
|
ジャッジサーバーID （参考情報） |
judge1 / judge2 |
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| ファイルパターン | 結果 |
|---|---|
| other | AC * 42 |
ソースコード
#include <cstdio>
#include <cstdint>
#include <cmath>
#include <cstring>
#include <iostream>
#include <iomanip>
#include <vector>
#include <map>
#include <unordered_map>
#include <set>
#include <unordered_set>
#include <queue>
#include <algorithm>
#include <numeric>
#include <cassert>
using namespace std;
namespace atcoder{};using namespace atcoder;
using ull = uint64_t;
using ll = int64_t;
using vi = vector<int>;
using vll = vector<ll>;
using vs = vector<string>;
using ld = long double;
using P = pair<ll,ll>;
using G = vector<vector<int>>;
#ifdef MYDEBUG
template<class C> string join(const C& c){stringstream ss; for(auto it=c.begin(); it!=c.end();it++){ss << *it;if(it!=c.end())ss<<", ";}return ss.str();}
template<class C> ostream &operator<<(ostream &os, const vector<C>& c){for(auto it=c.begin(); it!=c.end();it++){os << *it;if(it!=c.end())os<<", ";}return os;}
#define LO(...) fprintf(stderr, __VA_ARGS__)
#define debug(x) cerr << "\033[33m(line:" << __LINE__ << ") " << #x << ": " << x << "\033[m" << endl
#else
#define LO(...) (void)0
#define debug(x) (void)0
#endif
#define reps(i,a,n) for(ll i##_len = (ll)(n), i = (a); i < i##_len; ++i)
#define rep(i,n) reps(i,0,n)
#define rrep(i,n) reps(i,1,n+1)
#define repd(i,n) for(ll i=n-1;i>=0;i--)
#define rrepd(i,n) for(ll i=n;i>=1;i--)
#define inp(i) ll i; cin >> i;
#define inps(s) string s; cin >> s;
#define inpp(p) cin >> (p).first >> (p).second
#define inpv(v,N) vll v(N);rep(i,N)cin>>v[i];
#define inpg(g,N,M) g.resize(N);rep(i,M){inp(a);inp(b);a--,b--;g[a].push_back(b);g[b].push_back(a);}
#define all(v) begin(v),end(v)
#define YESNO(b) cout<<(b?"YES\n":"NO\n")
#define yesno(b) cout<<(b?"yes\n":"no\n")
#define YesNo(b) cout<<(b?"Yes\n":"No\n")
#define YES cout<<"YES\n"
#define NO cout<<"NO\n"
#define yes cout<<"yes\n"
#define no cout<<"no\n"
#define Yes cout<<"Yes\n"
#define No cout<<"No\n"
#define SP cout << " "
#define ENDL cout << "\n"
#define ou(i) cout << (i)
#define ous(i) cout << (i) << " "
#define oul(i) cout << (i) << "\n"
#define setfp() cout << fixed << setprecision(16)
template<typename C> void ouv(const C &v){for(auto &&e:v){cout << e;if(&e != &v.back()) cout << ' ';}cout << "\n";}
template<typename C> void ouvadd(const C &v){for(auto &&e:v){cout << e+1;if(&e != &v.back()) cout << ' ';}cout << "\n";}
template<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
inline ll lg(ll __n) { return sizeof(ll) * __CHAR_BIT__ - 1 - __builtin_clzl(__n); }
int dx[8]={1,0,-1,0,1,-1,-1,1};
int dy[8]={0,1,0,-1,1,1,-1,-1};
constexpr ll INF = 1e18;
#ifndef ATCODER_SEGTREE_HPP
#define ATCODER_SEGTREE_HPP 1
#include <algorithm>
#include <cassert>
#include <vector>
#ifndef ATCODER_INTERNAL_BITOP_HPP
#define ATCODER_INTERNAL_BITOP_HPP 1
#ifdef _MSC_VER
#include <intrin.h>
#endif
namespace atcoder {
namespace internal {
// @param n `0 <= n`
// @return minimum non-negative `x` s.t. `n <= 2**x`
int ceil_pow2(int n) {
int x = 0;
while ((1U << x) < (unsigned int)(n)) x++;
return x;
}
// @param n `1 <= n`
// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`
constexpr int bsf_constexpr(unsigned int n) {
int x = 0;
while (!(n & (1 << x))) x++;
return x;
}
// @param n `1 <= n`
// @return minimum non-negative `x` s.t. `(n & (1 << x)) != 0`
int bsf(unsigned int n) {
#ifdef _MSC_VER
unsigned long index;
_BitScanForward(&index, n);
return index;
#else
return __builtin_ctz(n);
#endif
}
} // namespace internal
} // namespace atcoder
#endif // ATCODER_INTERNAL_BITOP_HPP
namespace atcoder {
template <class S, S (*op)(S, S), S (*e)()> struct segtree {
public:
segtree() : segtree(0) {}
explicit segtree(int n) : segtree(std::vector<S>(n, e())) {}
explicit segtree(const std::vector<S>& v) : _n(int(v.size())) {
log = internal::ceil_pow2(_n);
size = 1 << log;
d = std::vector<S>(2 * size, e());
for (int i = 0; i < _n; i++) d[size + i] = v[i];
for (int i = size - 1; i >= 1; i--) {
update(i);
}
}
void set(int p, S x) {
assert(0 <= p && p < _n);
p += size;
d[p] = x;
for (int i = 1; i <= log; i++) update(p >> i);
}
S get(int p) const {
assert(0 <= p && p < _n);
return d[p + size];
}
S prod(int l, int r) const {
assert(0 <= l && l <= r && r <= _n);
S sml = e(), smr = e();
l += size;
r += size;
while (l < r) {
if (l & 1) sml = op(sml, d[l++]);
if (r & 1) smr = op(d[--r], smr);
l >>= 1;
r >>= 1;
}
return op(sml, smr);
}
S all_prod() const { return d[1]; }
template <bool (*f)(S)> int max_right(int l) const {
return max_right(l, [](S x) { return f(x); });
}
template <class F> int max_right(int l, F f) const {
assert(0 <= l && l <= _n);
assert(f(e()));
if (l == _n) return _n;
l += size;
S sm = e();
do {
while (l % 2 == 0) l >>= 1;
if (!f(op(sm, d[l]))) {
while (l < size) {
l = (2 * l);
if (f(op(sm, d[l]))) {
sm = op(sm, d[l]);
l++;
}
}
return l - size;
}
sm = op(sm, d[l]);
l++;
} while ((l & -l) != l);
return _n;
}
template <bool (*f)(S)> int min_left(int r) const {
return min_left(r, [](S x) { return f(x); });
}
template <class F> int min_left(int r, F f) const {
assert(0 <= r && r <= _n);
assert(f(e()));
if (r == 0) return 0;
r += size;
S sm = e();
do {
r--;
while (r > 1 && (r % 2)) r >>= 1;
if (!f(op(d[r], sm))) {
while (r < size) {
r = (2 * r + 1);
if (f(op(d[r], sm))) {
sm = op(d[r], sm);
r--;
}
}
return r + 1 - size;
}
sm = op(d[r], sm);
} while ((r & -r) != r);
return 0;
}
private:
int _n, size, log;
std::vector<S> d;
void update(int k) { d[k] = op(d[2 * k], d[2 * k + 1]); }
};
} // namespace atcoder
#endif // ATCODER_SEGTREE_HPP
ll op(ll a, ll b){return a+b;}
ll e(){return 0;}
using SEG = atcoder::segtree<ll,op,e>;
int main(){
inp(N);
vll A(N),T(N);
rep(i,N)cin>>A[i]>>T[i];
inp(Q);
vector<pair<P,P>> q(Q+N*2);
rep(i,Q){
cin >> q[i].first.first >> q[i].second.first >> q[i].second.second;
q[i].second.first--;
q[i].first.second = i;
}
rep(i,N){
q[Q+i].first.first = T[i];
q[Q+i].first.second = -3;
q[Q+i].second.first = i;
q[Q+N+i].first.first = T[i] + A[i];
q[Q+N+i].first.second = -2;
q[Q+N+i].second.first = i;
}
sort(all(q));
SEG fi(N),se(N),ti(N);
rep(i,N){
fi.set(i,A[i]);
}
ll prev_time = 0;
vll ans(Q);
rep(i,N+N+Q){
auto [a,b] = q[i].first;
auto [c,d] = q[i].second;
if(b == -3){
se.set(c, 1);
ti.set(c, a);
}else if(b == -2){
se.set(c, 0);
ti.set(c, 0);
fi.set(c, 0);
}else{
ll tot = fi.prod(c, d);
ll count = se.prod(c, d);
ll timetot = ti.prod(c, d);
debug(a);
debug(tot);
debug(count);
debug(timetot);
ans[b] = tot + (timetot - count * (a+1));
}
}
rep(i,Q){
oul(ans[i]);
}
return 0;
}