結果

問題 No.2020 Sum of Common Prefix Length
ユーザー leaf_1415leaf_1415
提出日時 2022-10-27 06:18:47
言語 C++11
(gcc 11.4.0)
結果
WA  
実行時間 -
コード長 15,629 bytes
コンパイル時間 2,253 ms
コンパイル使用メモリ 152,768 KB
実行使用メモリ 125,996 KB
最終ジャッジ日時 2023-09-17 23:23:38
合計ジャッジ時間 18,620 ms
ジャッジサーバーID
(参考情報)
judge12 / judge13
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 WA -
testcase_01 WA -
testcase_02 WA -
testcase_03 RE -
testcase_04 RE -
testcase_05 RE -
testcase_06 RE -
testcase_07 RE -
testcase_08 WA -
testcase_09 RE -
testcase_10 WA -
testcase_11 RE -
testcase_12 RE -
testcase_13 RE -
testcase_14 RE -
testcase_15 WA -
testcase_16 WA -
testcase_17 RE -
testcase_18 RE -
testcase_19 RE -
testcase_20 RE -
testcase_21 RE -
testcase_22 RE -
testcase_23 RE -
testcase_24 RE -
testcase_25 RE -
testcase_26 RE -
testcase_27 AC 10 ms
27,168 KB
testcase_28 WA -
testcase_29 WA -
testcase_30 WA -
testcase_31 RE -
testcase_32 RE -
testcase_33 RE -
testcase_34 AC 262 ms
57,636 KB
testcase_35 WA -
testcase_36 RE -
testcase_37 WA -
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ソースコード

diff #

#include <iostream>
#include <iomanip>
#include <cstdio>
#include <cmath>
#include <ctime>
#include <cstdlib>
#include <cassert>
#include <vector>
#include <list>
#include <stack>
#include <queue>
#include <deque>
#include <map>
#include <set>
#include <bitset>
#include <string>
#include <algorithm>
#include <utility>
#include <complex>
#include <array>
#include <unordered_set>
#include <unordered_map>
#define rep(x, s, t) for(ll x = (s); (x) <= (t); (x)++)
#define per(x, s, t) for(ll x = (s); (x) >= (t); (x)--)
#define reps(x, s) for(ll x = 0; (x) < (ll)(s).size(); (x)++)
#define chmin(x, y) (x) = min((x), (y))
#define chmax(x, y) (x) = max((x), (y))
#define sz(x) ((ll)(x).size())
#define all(x) (x).begin(),(x).end()
#define rall(x) (x).rbegin(),(x).rend()
#define outl(...) dump_func(__VA_ARGS__)
#define outf(x) cout << fixed << setprecision(16) << (x) << endl
#define pb push_back
#define fi first
#define se second
#define inf 2e18
#define eps 1e-9
const double PI = 3.1415926535897932384626433;

using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> P;

struct edge{
	ll to, cost;
	edge(){}
	edge(ll a, ll b){ to = a, cost = b;}
};
const int dx[] = {1, 0, -1, 0}, dy[] = {0, -1, 0, 1};

const int mod = 1000000007;
//const int mod = 998244353;

struct mint{
	int x;
	mint(ll y = 0){if(y < 0 || y >= mod) y = (y%mod+mod)%mod; x = y;}
	mint(const mint &ope) {x = ope.x;}
	mint operator-(){return mint(-x);}
	mint operator+(const mint &ope){return mint(x) += ope;}
	mint operator-(const mint &ope){return mint(x) -= ope;}
	mint operator*(const mint &ope){return mint(x) *= ope;}
	mint operator/(const mint &ope){return mint(x) /= ope;}
	mint& operator+=(const mint &ope){x += ope.x; if(x >= mod) x -= mod; return *this;}
	mint& operator-=(const mint &ope){x += mod - ope.x; if(x >= mod) x -= mod; return *this;}
	mint& operator*=(const mint &ope){ll tmp = x; tmp *= ope.x, tmp %= mod; x = tmp; return *this;}
	mint& operator/=(const mint &ope){
		ll n = mod-2; mint mul = ope;
		while(n){if(n & 1) *this *= mul; mul *= mul; n >>= 1;}
		return *this;
	}
	mint inverse(){return mint(1) / *this;}
	bool operator ==(const mint &ope){return x == ope.x;}
	bool operator !=(const mint &ope){return x != ope.x;}
	bool operator <(const mint &ope)const{return x < ope.x;}
};
mint modpow(mint a, ll n){
	if(n == 0) return mint(1);
	if(n % 2) return a * modpow(a, n-1);
	else return modpow(a*a, n/2);
}
istream& operator >>(istream &is, mint &ope){ll t; is >> t, ope.x = t; return is;}
ostream& operator <<(ostream &os, mint &ope){return os << ope.x;}
ostream& operator <<(ostream &os, const mint &ope){return os << ope.x;}

ll modpow(ll a, ll n, ll mod){
	if(n == 0) return 1;
	if(n % 2) return ((a%mod) * (modpow(a, n-1, mod)%mod)) % mod;
	else return modpow((a*a)%mod, n/2, mod) % mod;
}

vector<mint> fact, fact_inv;
void make_fact(int n){
	fact.resize(n+1), fact_inv.resize(n+1);
	fact[0] = mint(1); rep(i, 1, n) fact[i] = fact[i-1] * mint(i);
	fact_inv[n] = fact[n].inverse(); per(i, n-1, 0) fact_inv[i] = fact_inv[i+1] * mint(i+1);
}
mint comb(int n, int k){ if(n < 0 || k < 0 || n < k) return mint(0); return fact[n] * fact_inv[k] * fact_inv[n-k];}
mint perm(int n, int k){ return comb(n, k) * fact[k]; }
template<typename T> T comb2(ll n, ll k){ T ret = 1; rep(i, 1, k) ret *= n-k+i, ret /= i; return ret;}

vector<int> prime, pvec, qrime;
void make_prime(int n){
	prime.resize(n+1);
	rep(i, 2, n){
		if(prime[i] == 0) pvec.push_back(i), prime[i] = i;
		for(auto p : pvec){ if(i*p > n || p > prime[i]) break; prime[i*p] = p;}
	}
}
void make_qrime(int n){
	qrime.resize(n+1);
	rep(i, 2, n){int ni = i / prime[i]; if(prime[i] == prime[ni]) qrime[i] = qrime[ni] * prime[i]; else qrime[i] = prime[i];}
}

bool exceed(ll x, ll y, ll m){return y > 0 && x >= m / y + 1;}
void mark(){ cout << "*" << endl; }
void yes(){ cout << "YES" << endl; }
void no(){ cout << "NO" << endl; }
ll floor(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return a/b; else return -((-a+b-1)/b); }
ll ceil(ll a, ll b){ if(b < 0) a *= -1, b *= -1; if(a >= 0) return (a+b-1)/b; else return -((-a)/b); }
ll modulo(ll a, ll b){ b = abs(b); return a - floor(a, b) * b;}
ll sgn(ll x){ if(x > 0) return 1; if(x < 0) return -1; return 0;}
ll gcd(ll a, ll b){if(b == 0) return a; return gcd(b, a%b);}
ll lcm(ll a, ll b){return a/gcd(a, b)*b;}
ll arith(ll x){return x*(x+1)/2;}
ll arith(ll l, ll r){return arith(r) - arith(l-1);}
ll digitnum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret++; return ret;}
ll digitsum(ll x, ll b = 10){ll ret = 0; for(; x; x /= b) ret += x % b; return ret;}
string lltos(ll x, ll b = 10){if(x == 0) return "0"; string ret; for(;x;x/=b) ret += x % b + '0'; reverse(all(ret)); return ret;}
ll stoll(string &s, ll b = 10){ll ret = 0; for(auto c : s) ret *= b, ret += c - '0'; return ret;}
template<typename T> void uniq(T &vec){sort(all(vec)); vec.erase(unique(all(vec)), vec.end());}
int popcount(ull x){
	x -= ((x>>1)&0x5555555555555555ULL), x = (x & 0x3333333333333333ULL) + ((x>>2) & 0x3333333333333333ULL);
	return (((x + (x>>4)) & 0x0F0F0F0F0F0F0F0FULL) * 0x0101010101010101ULL) >> 56;
}

template<class S, class T> pair<S, T>& operator+=(pair<S, T> &s, const pair<S, T> &t){s.first += t.first, s.second += t.second; return s;}
template<class S, class T> pair<S, T>& operator-=(pair<S, T> &s, const pair<S, T> &t){s.first -= t.first, s.second -= t.second; return s;}
template<class S, class T> pair<S, T> operator+(const pair<S, T> &s, const pair<S, T> &t){return pair<S,T>(s.first+t.first, s.second+t.second);}
template<class S, class T> pair<S, T> operator-(const pair<S, T> &s, const pair<S, T> &t){return pair<S,T>(s.first-t.first, s.second-t.second);}
template<class T> T dot(const pair<T, T> &s, const pair<T, T> &t){return s.first*t.first + s.second*t.second;}
template<class T> T cross(const pair<T, T> &s, const pair<T, T> &t){return s.first*t.second - s.second*t.first;}
template<class T> T mdist(pair<T, T> s, pair<T, T> t){return abs(s.first-t.first) + abs(s.second-t.second);}
template<class T> T cdist(pair<T, T> s, pair<T, T> t){return max(abs(s.first-t.first), abs(s.second-t.second));}
template<class T> T edist2(pair<T, T> s, pair<T, T> t){return (s.first-t.first)*(s.first-t.first) + (s.second-t.second)*(s.second-t.second);}

template<typename T> ostream& operator << (ostream& os, vector<T>& vec){reps(i, vec) os << vec[i] << " "; return os;}
template<typename T> ostream& operator << (ostream& os, const vector<T>& vec){reps(i, vec) os << vec[i] << " "; return os;}
template<typename T> ostream& operator << (ostream& os, list<T>& ls){for(auto x : ls) os << x << " "; return os;}
template<typename T> ostream& operator << (ostream& os, const list<T>& ls){for(auto x : ls) os << x << " "; return os;}
template<typename T> ostream& operator << (ostream& os, deque<T>& deq){reps(i,  deq) os << deq[i] << " "; return os;}
template<typename T, typename U> ostream& operator << (ostream& os, pair<T, U>& ope){ os << "(" << ope.first << ", " << ope.second << ")"; return os;}
template<typename T, typename U> ostream& operator << (ostream& os, const pair<T, U>& ope){ os << "(" << ope.first << ", " << ope.second << ")"; return os;}
template<typename T, typename U> ostream& operator << (ostream& os, map<T, U>& ope){ for(auto p : ope) os << "(" << p.first << ", " << p.second << "),";return os;}
template<typename T> ostream& operator << (ostream& os, set<T>& ope){for(auto x : ope) os << x << " "; return os;}
template<typename T> ostream& operator << (ostream& os, multiset<T>& ope){for(auto x : ope) os << x << " "; return os;}
template<typename T> void outa(T a[], ll s, ll t){rep(i, s, t){ cout << a[i]; if(i < t) cout << " ";} cout << endl;}
template<typename T, size_t N> ostream& operator << (ostream& os, array<T, N>& arr){reps(i, arr) os << arr[i] << " "; return os;}
template<typename T, size_t N> ostream& operator << (ostream& os, const array<T, N>& arr){reps(i, arr) os << arr[i] << " "; return os;}
void dump_func(){cout << endl;}
template <class Head, class... Tail>
void dump_func(Head &&head, Tail &&... tail){cout << head; if(sizeof...(Tail) > 0) cout << " "; dump_func(std::move(tail)...);}

struct Trie{
	struct TrieNode{
		int num, next[26];
		TrieNode(){
			num = 0;
			for(int i = 0; i < 26; i++) next[i] = -1;
		}
	};
	vector<TrieNode> vec;
	Trie(){
		init();
	}
	void init(){
		vec.clear();
		vec.push_back(TrieNode());
	}
	int seek(string &s)
	{
		int p = 0;
		for(int i = 0; i < s.size(); i++){
			int c = s[i]-'a';
			if(vec[p].next[c] == -1){
				vec.push_back(TrieNode());
				vec[p].next[c] = (int)vec.size()-1;
			}
			p = vec[p].next[c];
		}
		return p;
	}
	void insert(string &s, int x = 1)
	{
		int p = seek(s);
		vec[p].num += x;
	}
	void erase(string &s, int x = 1)
	{
		int p = seek(s);
		vec[p].num = max(0, vec[p].num - x);
	}
	int count(string &s)
	{
		int p = seek(s);
		return vec[p].num;
	}
};

struct HLD{
	int V, logV;
	vector<P> mp;
	map<P, int> mp2;
	vector<P> parent;
	
	//subtree of v is [pre_order[v], back_order[v]]
	vector<int> pre_order;
	vector<int> back_order;
	
	int order;
	int global_id, local_id;
	vector<int> size, depth;
	vector<vector<int> > prev;
	
	HLD(){}
	
	void predfs(vector<int> G[], int v, int p, int d)
	{
		size[v] = 1, depth[v] = d, prev[v][0] = p;
		for(int i = 0; i < G[v].size(); i++){
			if(G[v][i] == p) continue;
			predfs(G, G[v][i], v, d+1);
			size[v] += size[G[v][i]];
		}
	}
	void maindfs(vector<int> G[], int v, int p)
	{
		mp[v] = make_pair(global_id, local_id);
		mp2[make_pair(global_id, local_id)] = v;
		pre_order[v] = ++order;
		
		if(G[v].size() == 1 && G[v][0] == p){
			back_order[v] = order;
			return;
		}
		
		vector<P> vec;
		for(int i = 0; i < G[v].size(); i++){
			if(G[v][i] == p) continue;
			vec.push_back(make_pair(size[G[v][i]], G[v][i]));
		}
		sort(vec.rbegin(), vec.rend());
		
		local_id++;
		if(vec.size() >= 1) maindfs(G, vec[0].second, v);
			
		for(int i = 1; i < vec.size(); i++){
			parent.push_back(mp[v]);
			global_id++, local_id = 0;
			maindfs(G, vec[i].second, v);
		}
		back_order[v] = order;
	}
	int getLCA(int u, int v){
		int x = u, y = v;
		if(depth[y] > depth[x]) swap(x, y);
		
		for(int i = logV-1; i >= 0; i--){
			if(depth[x] - (1<<i) >= depth[y]) x = prev[x][i];
		}
		if(x == y) return x;
		for(int i = logV-1; i >= 0; i--){
			if(prev[x][i] != prev[y][i]){
				x = prev[x][i];
				y = prev[y][i];
			}
		}
		x = prev[x][0];
		return x;
	}
	void pathcalc(int v, int lca, vector<pair<int, P> > &dest)
	{
		int gid = mp[v].first, lid = mp[v].second;
		int Gid = mp[lca].first, Lid = mp[lca].second;
		
		while(Gid != gid){
			dest.push_back(make_pair(gid, make_pair(0, lid)));
			int ngid = parent[gid].first, nlid = parent[gid].second;
			gid = ngid, lid = nlid;
		}
		dest.push_back(make_pair(gid, make_pair(Lid, lid)));
	}
	
	void init(vector<int> G[], int V) // The tree must be undirected and 1-indexed.
	{
		this->V = V, logV = 0;
		for(int t = V; t; t/=2) logV++;
		prev.resize(V+1);
		for(int i = 0; i <= V; i++) prev[i].resize(logV);
		
		size.resize(V+1), depth.resize(V+1);
		predfs(G, 1, 0, 0);
		
		prev[0][0] = 0;
		for(int i = 1; i < logV; i++){
			for(int j = 1; j <= V; j++){
				prev[j][i] = prev[prev[j][i-1]][i-1];
			}
		}
		
		mp.resize(V+1), mp2.clear();
		parent.clear(), parent.push_back(make_pair(-1, -1));
		pre_order.resize(V+1), back_order.resize(V+1);
		global_id = local_id = 0, order = 0;
		
		maindfs(G, 1, 0);
	}
	
	void path(int u, int v, vector<pair<int, P> > &dest)
	{
		dest.clear();
		int lca = getLCA(u, v);
		pathcalc(u, lca, dest);
		pathcalc(v, lca, dest);
		
		pair<int, P> p = make_pair(mp[lca].first, make_pair(mp[lca].second, mp[lca].second));
		for(int i = 0; i < dest.size(); i++){
			if(dest[i] == p){
				dest.erase(dest.begin()+i);
				return ;
			}
		}
	}
	
	void getPath(int u, int v, vector<P> &dest) //transform an u-v path into intervals[l, r] on segtree.
	{
		vector<pair<int, P> > src;
		path(u, v, src);
		
		dest.clear();
		for(int i = 0; i < src.size(); i++){
			int u = mp2[make_pair(src[i].first, src[i].second.first)], v = mp2[make_pair(src[i].first, src[i].second.second)];
			dest.push_back(make_pair(pre_order[u], pre_order[v]));
		}
	}
};


struct LazySegTree{
	typedef ll SEG;
	typedef ll DELAY;
	
	int size;
	vector<SEG> seg;
	vector<DELAY> delay;
	
	LazySegTree(){}
	LazySegTree(int size){
		this->size = size;
		seg.resize(1<<(size+1));
		delay.resize(1<<(size+1));
	}
	
	SEG Ident(){ //
		return 0;
	}
	SEG ope(SEG a, SEG b){ //
		return a + b;
	}
	DELAY NoDelay(){ //
		return 0;
	}
	DELAY merge(DELAY a, DELAY b){ //
		return a + b;
	}
	SEG act(SEG a, DELAY d, int l, int r){ //総和クエリのときは区間幅を乗じる必要がある
		return a + d*(r-l+1);
	}
	
	void init(){
		for(int i = 0; i < (1<<(size+1)); i++){
			seg[i] = Ident();
			delay[i] = NoDelay();
		}
	}
	void set(int i, SEG x){
		seg[i+(1<<size)] = x;
	}
	void setup(){
		for(int i = (1<<size)-1; i >= 1; i--) seg[i] = ope(seg[i*2], seg[i*2+1]);
	}
	
	void eval(int l, int r, int k){
		if(delay[k] != NoDelay()){
			seg[k] = act(seg[k], delay[k], l, r);
			if(l < r){
				delay[k*2] = merge(delay[k*2], delay[k]);
				delay[k*2+1] = merge(delay[k*2+1], delay[k]);
			}
			delay[k] = NoDelay();
		}
	}
	
	void update(int i, SEG val){
		int l = 0, r = (1<<size)-1, k = 1;
		
		eval(l, r, k);
		for(int j = size-1; j >= 0; j--){
			k <<= 1;
			if(i & (1<<j)){
				k++;
				l = (l+r)/2+1;
			}
			else r = (l+r)/2;
			eval(l, r, k);
		}
		
		seg[i+(1<<size)] = val;
		
		l = i, r = i, k = i+(1<<size);
		for(int j = 0; j < size; j++){
			k /= 2, l &= ~(1<<j), r |= 1<<j;
			eval(l, (l+r)/2, k*2), eval((l+r)/2+1, r, k*2+1);
			seg[k] = ope(seg[k*2], seg[k*2+1]);
		}
	}
	
	void add(int a, int b, int k, int l, int r, DELAY val){
		eval(l, r, k);
		if(b < l || r < a) return;
		if(a <= l && r <= b){
			delay[k] = merge(delay[k], val); 
			eval(l, r, k);
			return;
		}
		add(a, b, k*2, l, (l+r)/2, val);
		add(a, b, k*2+1, (l+r)/2+1, r, val);
		seg[k] = ope(seg[k*2], seg[k*2+1]);
	}
	void add(int a, int b, DELAY val){
		if(a > b) return;
		add(a, b, 1, 0, (1<<size)-1, val);
	}
 
	SEG query(int a, int b, int k, int l, int r){
		eval(l, r, k);
		if(b < l || r < a) return Ident();
		if(a <= l && r <= b) return seg[k];
		SEG lval = query(a, b, k*2, l, (l+r)/2);
		SEG rval = query(a, b, k*2+1, (l+r)/2+1, r);
		return ope(lval, rval);
	}
	SEG query(int a, int b){
		if(a > b) return Ident();
		return query(a, b, 1, 0, (1<<size)-1);
	}
};

ll n, Q;
string s[200005];
ll t[200005], x[200005];
char c[200005];

Trie trie;
HLD hld;
LazySegTree seg;
vector<int> G[600005];
ll v[200005];

void dfs(int v){
	rep(i, 0, 25){
		ll u = trie.vec[v].next[i];
		if(u == -1) continue;
		G[v+1].pb(u+1), dfs(u);
	}
}

void add(int u, int v, int x)
{
	vector<P> res;
	hld.getPath(u+1, v+1, res);
	for(auto p : res) seg.add(p.fi, p.se, x);
}
ll query(int u, int v)
{
	vector<P> res;
	hld.getPath(u+1, v+1, res);
	ll ret = 0;
	for(auto p : res) ret += seg.query(p.fi, p.se);
	return ret;
}

int main(void)
{
	ios::sync_with_stdio(0);
	cin.tie(0);
	
	cin >> n;
	rep(i, 1, n) cin >> s[i], trie.insert(s[i]);
	rep(i, 1, n) v[i] = trie.seek(s[i]);
	
	cin >> Q;
	rep(i, 1, Q){
		cin >> t[i] >> x[i];
		if(t[i] == 1){
			cin >> c[i];
			s[x[i]] += c[i];
		}
	}
	dfs(0);
	
	ll m = sz(trie.vec);
	seg = LazySegTree(digitnum(m+5, 2));
	hld.init(G, m), seg.init();
	
	rep(i, 1, n) add(0, v[i], 1);
	rep(i, 1, Q){
		if(t[i] == 1){
			add(0, v[x[i]], -1);
			v[x[i]] = trie.vec[v[x[i]]].next[c[i]-'a'];
			add(0, v[x[i]], 1);
		}
		if(t[i] == 2) cout << query(0, v[x[i]])-n << "\n";
	}
	
	
	return 0;
}
0