結果
問題 | No.922 東北きりきざむたん |
ユーザー | terasa |
提出日時 | 2022-11-03 23:10:33 |
言語 | PyPy3 (7.3.15) |
結果 |
TLE
|
実行時間 | - |
コード長 | 6,826 bytes |
コンパイル時間 | 168 ms |
コンパイル使用メモリ | 82,520 KB |
実行使用メモリ | 269,440 KB |
最終ジャッジ日時 | 2024-07-18 05:18:42 |
合計ジャッジ時間 | 5,898 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge5 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 64 ms
76,812 KB |
testcase_01 | AC | 64 ms
70,532 KB |
testcase_02 | AC | 69 ms
69,756 KB |
testcase_03 | AC | 64 ms
70,040 KB |
testcase_04 | AC | 92 ms
78,264 KB |
testcase_05 | AC | 72 ms
74,164 KB |
testcase_06 | AC | 117 ms
78,984 KB |
testcase_07 | AC | 102 ms
78,180 KB |
testcase_08 | AC | 112 ms
78,720 KB |
testcase_09 | TLE | - |
testcase_10 | -- | - |
testcase_11 | -- | - |
testcase_12 | -- | - |
testcase_13 | -- | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
testcase_17 | -- | - |
testcase_18 | -- | - |
testcase_19 | -- | - |
testcase_20 | -- | - |
testcase_21 | -- | - |
testcase_22 | -- | - |
testcase_23 | -- | - |
testcase_24 | -- | - |
testcase_25 | -- | - |
testcase_26 | -- | - |
testcase_27 | -- | - |
testcase_28 | -- | - |
testcase_29 | -- | - |
ソースコード
from typing import List, Tuple, Callable, TypeVar from typing import List, Tuple, Optional import sys import itertools import heapq import bisect from collections import deque, defaultdict from functools import lru_cache, cmp_to_key input = sys.stdin.readline # for AtCoder Easy test if __file__ != 'prog.py': sys.setrecursionlimit(10 ** 6) def readints(): return map(int, input().split()) def readlist(): return list(readints()) def readstr(): return input().rstrip() T = TypeVar('T') class Rerooting: # reference: https://null-mn.hatenablog.com/entry/2020/04/14/124151 # 適当な頂点vを根とする部分木に対して計算される値dp_vが、vの子c1, c2, ... ckを用いて # 下記のように表すことができる # dp_v = g(merge(f(dp_c1,c1), f(dp_c2,c2), ..., f(dp_ck,ck)), v) def __init__(self, N: int, E: List[Tuple[int, int]], f: Callable[[T, int, int, int], T], g: Callable[[T, int], T], merge: Callable[[T, T], T], e: T): self.N = N self.E = E self.f = f self.g = g self.merge = merge self.e = e self.dp = [[self.e for _ in range(len(self.E[v]))] for v in range(self.N)] def _dfs1(self, root): stack = [(root, -1)] ret = [self.e] * self.N while stack: v, p = stack.pop() if v < 0: v = ~v acc = self.e for i, (c, d) in enumerate(self.E[v]): if d == p: continue self.dp[v][i] = ret[d] acc = self.merge(acc, self.f(ret[d], v, d, c)) ret[v] = self.g(acc, v) continue stack.append((~v, p)) for i, (c, d) in enumerate(self.E[v]): if d == p: continue stack.append((d, v)) def _dfs2(self, root): stack = [(root, -1, self.e)] while stack: v, p, from_par = stack.pop() for i, (c, d) in enumerate(self.E[v]): if d == p: self.dp[v][i] = from_par break ch = len(self.E[v]) Sr = [self.e] * (ch + 1) for i in range(ch, 0, -1): c, d = self.E[v][i - 1] Sr[i - 1] = self.merge(Sr[i], self.f(self.dp[v][i - 1], v, d, c)) Sl = self.e for i, (c, d) in enumerate(self.E[v]): if d != p: val = self.merge(Sl, Sr[i + 1]) stack.append((d, v, self.g(val, v))) Sl = self.merge(Sl, self.f(self.dp[v][i], v, d, c)) def calculate(self, root=0): self._dfs1(root) self._dfs2(root) def solve(self, v): ans = self.e for i, (c, d) in enumerate(self.E[v]): ans = self.merge(ans, self.f(self.dp[v][i], v, d, c)) return self.g(ans, v) class UnionFind: def __init__(self, N): self.N = N self.par = [-1] * N def find(self, x): if self.par[x] < 0: return x else: self.par[x] = self.find(self.par[x]) return self.par[x] def unite(self, x, y): x = self.find(x) y = self.find(y) if x == y: return False if self.par[x] > self.par[y]: x, y = y, x self.par[x] += self.par[y] self.par[y] = x return True def same(self, x, y): return self.find(x) == self.find(y) def size(self, x): return -self.par[self.find(x)] def roots(self): return [i for i in range(self.N) if self.par[i] < 0] class LCA: def __init__(self, N, E): self.N = N self.E = E self.K = N.bit_length() self.par = [[-1 for _ in range(N)] for _ in range(self.K)] self.depth = [None] * N def _dfs(self, root): self.depth[root] = 0 stack = [(root, -1)] while stack: v, p = stack.pop() if not p < 0: self.par[0][v] = p self.depth[v] = self.depth[p] + 1 for _, dest in self.E[v]: if dest == p: continue stack.append((dest, v)) def calculate(self): for k in range(self.K - 1): for i in range(self.N): if self.par[k][i] < 0: continue self.par[k + 1][i] = self.par[k][self.par[k][i]] def la(self, v, x): for k in range(self.K): if x & (1 << k): v = self.par[k][v] return v def lca(self, u, v): if self.depth[u] > self.depth[v]: u, v = v, u d = self.depth[v] - self.depth[u] v = self.la(v, d) if u == v: return u for k in range(self.K)[::-1]: if self.par[k][u] != self.par[k][v]: u = self.par[k][u] v = self.par[k][v] return self.par[0][v] def dist(self, u, v): return self.depth[u] + self.depth[v] - 2 * self.depth[self.lca(u, v)] def jump(self, u, v, x): lca = self.lca(u, v) d1 = self.depth[u] - self.depth[lca] d2 = self.depth[v] - self.depth[lca] if d1 + d2 < x: return -1 if x <= d1: return self.la(u, x) return self.la(v, d1 + d2 - x) N, M, Q = readints() E = [[] for _ in range(N)] uf = UnionFind(N) D = N for _ in range(M): u, v = readints() u -= 1 v -= 1 E[u].append((1, v)) E[v].append((1, u)) if uf.unite(u, v) is True: D -= 1 query = [] cnt = [0] * N for _ in range(Q): a, b = readints() a -= 1 b -= 1 if uf.same(a, b) is False: cnt[a] += 1 cnt[b] += 1 query.append((a, b)) def f(a, v, ch, cost): return (a[0] + a[1], a[1]) def g(a, v): return (a[0], a[1] + cnt[v]) def merge(a, b): return (a[0] + b[0], a[1] + b[1]) gidx = {} for i, v in enumerate(uf.roots()): gidx[v] = i V = [[] for _ in range(D)] for i in range(N): V[gidx[uf.find(i)]].append(i) solver = Rerooting(N, E, f, g, merge, (0, 0)) lca = LCA(N, E) airports = [None] * D cost = [None] * N for i in range(D): solver.calculate(root=V[i][0]) lca._dfs(V[i][0]) for v in V[i]: cost[v] = solver.solve(v)[0] if airports[i] is None: airports[i] = v elif cost[airports[i]] > cost[v]: airports[i] = v A = [None] * N for i in range(D): for v in V[i]: A[v] = airports[i] ans = 0 lca.calculate() for s, t in query: sa, ta = A[s], A[t] if A[s] == A[t]: ans += lca.dist(s, t) else: ans += lca.dist(s, sa) + lca.dist(ta, t) print(ans)