結果
| 問題 | No.1094 木登り / Climbing tree |
| ユーザー |
|
| 提出日時 | 2022-11-04 00:04:17 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 1,710 ms / 2,000 ms |
| コード長 | 1,225 bytes |
| 記録 | |
| コンパイル時間 | 172 ms |
| コンパイル使用メモリ | 82,304 KB |
| 実行使用メモリ | 147,336 KB |
| 最終ジャッジ日時 | 2024-07-18 05:49:29 |
| 合計ジャッジ時間 | 34,705 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 26 |
ソースコード
from collections import deque
n = int(input())
g = [[] for _ in range(n)]
for _ in range(n - 1):
a, b, c = map(int, input().split())
a -= 1
b -= 1
g[a].append((b, c))
g[b].append((a, c))
k = n.bit_length()
src = 0
doub = [[src for _ in range(n)] for _ in range(k)]
depth = [None for _ in range(n)]
depth[src] = 0
cost = [0 for _ in range(n)]
dq = deque()
dq.appendleft(src)
while len(dq) > 0:
cur = dq.pop()
for nxt, c in g[cur]:
if not depth[nxt] is None:
continue
depth[nxt] = depth[cur] + 1
cost[nxt] = cost[cur] + c
doub[0][nxt] = cur
dq.appendleft(nxt)
for i in range(1, k):
for v in range(n):
doub[i][v] = doub[i - 1][doub[i - 1][v]]
def lca(u, v):
ut = u
vt = v
if depth[ut] > depth[vt]:
ut, vt = vt, ut
diff = depth[vt] - depth[ut]
for i in range(k):
if (diff >> i) & 1 != 0:
vt = doub[i][vt]
if ut != vt:
for i in range(k - 1, -1, -1):
if doub[i][ut] != doub[i][vt]:
ut = doub[i][ut]
vt = doub[i][vt]
if ut != vt:
ut = doub[0][ut]
return ut
q = int(input())
for _ in range(q):
s, t = map(int, input().split())
s -= 1
t -= 1
l = lca(s, t)
print(cost[s] + cost[t] - 2 * cost[l])