結果

問題 No.2115 Making Forest Easy
ユーザー woodywoodywoodywoody
提出日時 2022-11-06 23:02:25
言語 C++14
(gcc 12.3.0 + boost 1.83.0)
結果
AC  
実行時間 368 ms / 2,000 ms
コード長 5,360 bytes
コンパイル時間 3,751 ms
コンパイル使用メモリ 235,820 KB
実行使用メモリ 44,840 KB
最終ジャッジ日時 2023-09-27 15:46:24
合計ジャッジ時間 19,608 ms
ジャッジサーバーID
（参考情報） 		judge15 / judge14
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 2 ms
4,376 KB
testcase_01 AC 1 ms
4,376 KB
testcase_02 AC 325 ms
44,816 KB
testcase_03 AC 350 ms
42,916 KB
testcase_04 AC 335 ms
44,224 KB
testcase_05 AC 283 ms
37,992 KB
testcase_06 AC 321 ms
44,728 KB
testcase_07 AC 362 ms
42,988 KB
testcase_08 AC 324 ms
44,796 KB
testcase_09 AC 351 ms
43,056 KB
testcase_10 AC 328 ms
44,836 KB
testcase_11 AC 367 ms
42,936 KB
testcase_12 AC 356 ms
42,884 KB
testcase_13 AC 308 ms
38,768 KB
testcase_14 AC 361 ms
42,636 KB
testcase_15 AC 358 ms
43,100 KB
testcase_16 AC 361 ms
43,000 KB
testcase_17 AC 27 ms
6,796 KB
testcase_18 AC 46 ms
9,880 KB
testcase_19 AC 164 ms
25,612 KB
testcase_20 AC 269 ms
35,944 KB
testcase_21 AC 21 ms
6,124 KB
testcase_22 AC 66 ms
11,236 KB
testcase_23 AC 239 ms
34,400 KB
testcase_24 AC 346 ms
42,948 KB
testcase_25 AC 128 ms
20,408 KB
testcase_26 AC 360 ms
42,604 KB
testcase_27 AC 168 ms
24,316 KB
testcase_28 AC 349 ms
42,924 KB
testcase_29 AC 30 ms
7,508 KB
testcase_30 AC 358 ms
43,004 KB
testcase_31 AC 330 ms
44,200 KB
testcase_32 AC 326 ms
44,840 KB
testcase_33 AC 326 ms
44,732 KB
testcase_34 AC 35 ms
7,772 KB
testcase_35 AC 63 ms
12,524 KB
testcase_36 AC 325 ms
44,732 KB
testcase_37 AC 169 ms
22,804 KB
testcase_38 AC 81 ms
13,872 KB
testcase_39 AC 127 ms
19,932 KB
testcase_40 AC 355 ms
42,868 KB
testcase_41 AC 368 ms
42,948 KB
testcase_42 AC 348 ms
42,952 KB
testcase_43 AC 153 ms
21,172 KB
testcase_44 AC 84 ms
13,572 KB
testcase_45 AC 270 ms
33,076 KB
testcase_46 AC 368 ms
42,736 KB
testcase_47 AC 136 ms
19,220 KB
testcase_48 AC 336 ms
44,260 KB
testcase_49 AC 341 ms
44,240 KB
testcase_50 AC 208 ms
27,892 KB
testcase_51 AC 136 ms
18,984 KB
権限があれば一括ダウンロードができます

ソースコード

diff # 

#include<bits/stdc++.h>
#include<atcoder/all>
#define rep(i,b) for(int i=0;i<b;i++)
#define rrep(i,b) for(int i=b-1;i>=0;i--)
#define rep1(i,b) for(int i=1;i<b;i++)
#define repx(i,x,b) for(int i=x;i<b;i++)
#define rrepx(i,x,b) for(int i=b-1;i>=x;i--)
#define fore(i,a) for(auto i:a)
#define fore1(i,a) for(auto &i:a)
#define rng(x) (x).begin(), (x).end()
#define rrng(x) (x).rbegin(), (x).rend()
#define sz(x) ((int)(x).size())
#define pb push_back
#define fi first
#define se second
#define pcnt __builtin_popcountll

using namespace std;
using namespace atcoder;

using ll = long long;
using ld = long double;
template<typename T> using mpq = priority_queue<T, vector<T>, greater<T>>;
template<typename T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }
template<typename T> bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }
template<typename T> ll sumv(const vector<T>&a){ll res(0);for(auto&&x:a)res+=x;return res;}
bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}}
#define dame { cout << "No" << endl; return;}
#define dame1 { cout << -1 << endl; return;}
#define deb(x,y) cout << x << " " << y << endl;
#define debp(p) cout << p.fi << " " << p.se << endl;
#define out cout << ans << endl;
#define outd cout << fixed << setprecision(20) << ans << endl;
#define outm cout << ans.val() << endl;
#define outv fore(yans , ans) cout << yans << "\n";
#define outdv fore(yans , ans) cout << yans.val() << "\n";
#define showv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;}
#define showv2(v) fore(vy , v) cout << vy << "\n";
#define showvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;}
#define showvm2(v) fore(vy , v) cout << vy.val() << "\n";
using pll = pair<ll,ll>;using pil = pair<int,ll>;using pli = pair<ll,int>;using pii = pair<int,int>;using pdd = pair<ld,ld>;
using tp = tuple<int ,int ,int>;
using vi = vector<int>;using vd = vector<ld>;using vl = vector<ll>;using vs = vector<string>;using vb = vector<bool>;
using vpii = vector<pii>;using vpli = vector<pli>;using vpll = vector<pll>;using vpil = vector<pil>;
using vvi = vector<vector<int>>;using vvl = vector<vector<ll>>;using vvs = vector<vector<string>>;using vvb = vector<vector<bool>>;
using vvpii = vector<vector<pii>>;using vvpli = vector<vector<pli>>;using vvpll = vector<vpll>;using vvpil = vector<vpil>;
using mint = modint998244353;
using vm = vector<mint>;
using vvm = vector<vector<mint>>;
vector<int> dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1};
ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;}
ll lcm(ll a, ll b) { return a/gcd(a,b)*b;}
#define yes {cout <<"Yes"<<endl;}
#define yesr { cout <<"Yes"<<endl; return;}
#define no {cout <<"No"<<endl;}
#define nor { cout <<"No"<<endl; return;}
const double eps = 1e-10;
const ll LINF = 1001002003004005006ll;
const int INF = 1001001001;
#ifdef MY_LOCAL_DEBUG
#define show(x) cerr<<#x<<" = "<<x<<endl
#define showp(p) cerr<<#p<<" = "<<p.fi<<" : "<<p.se<<endl
#define show2(x,y) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<endl
#define show3(x,y,z) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<endl
#define show4(x,y,z,x2) cerr<<#x<<" = "<<x<<" : "<<#y<<" = "<<y<<" : "<<#z<<" = "<<z<<" : "<<#x2<<" = "<<x2<<endl
#define test(x) cout << "test" << x << endl
#else
#define show(x)
#define showp(p)
#define show2(x,y)
#define show3(x,y,z)
#define show4(x,y,z,x2)
#define test(x)
#endif

void solve(){
    int n; cin>>n;

    vi a(n);
    rep(i,n) cin>>a[i];

    vvi e(n);
    rep(i,n-1){
        int a,b; cin>>a>>b;
        a--; b--;
        e[a].pb(b);
        e[b].pb(a);
    }

    const int mxa = 1001;

    vvm dp1(n , vm(mxa)),dp2(n , vm(mxa));

    vi dd(n);

    auto dfs = [&](auto dfs,int x,int pre)->int{

        int d = 1;
        dp1[x][a[x]] = 1;
        dp2[x][a[x]] = 1;
    
        fore(y , e[x]){
            if(y == pre) continue;
    
            int k = dfs(dfs , y ,x);
            vm tmp1(mxa);
            vm tmp2(mxa);
            swap(tmp1 , dp1[x]);
            swap(tmp2 , dp2[x]);
            vm sumx1(mxa),sumy1(mxa),sumx2(mxa),sumy2(mxa);
            dp1[y][0] = mint(2).pow(k-1);
            dp2[y][0] = 0;
            rep(j,mxa){
                sumx1[j] = tmp1[j];
                sumy1[j] = dp1[y][j];
                sumx2[j] = tmp2[j];
                sumy2[j] = dp2[y][j];
                if (j != 0){
                    sumx1[j] += sumx1[j-1];
                    sumy1[j] += sumy1[j-1];
                    sumx2[j] += sumx2[j-1];
                    sumy2[j] += sumy2[j-1];
                }
            }
            rep(j,mxa){
                dp1[x][j] = sumx1[j]*dp1[y][j] + tmp1[j]*sumy1[j] - tmp1[j]*dp1[y][j]; 
                dp2[x][j] += sumx2[j]*dp1[y][j] + tmp1[j]*sumy2[j]; 
                dp2[x][j] += sumx1[j]*dp2[y][j] + tmp2[j]*sumy1[j];
                dp2[x][j] -= tmp1[j]*dp2[y][j] + tmp2[j]*dp1[y][j];
            }
            d += k;
        }

        dd[x] = d;
    
        return d;
    };

    dfs(dfs,0,-1);

    mint ans = 0;

    rep(i,n) rep1(j,mxa){
        int ik = 0;
        if (i == 0) ik = 1; 
        ans += dp2[i][j] * j * mint(2).pow(n-1-dd[i]+ik);
    }

    outm;



    return;
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);

    int t = 1;
    //cin>>t;

    rep(i,t){
        solve();
    }

    return 0;
}
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