結果
問題 | No.269 見栄っ張りの募金活動 |
ユーザー |
|
提出日時 | 2022-11-07 18:29:18 |
言語 | C++17 (gcc 13.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 37 ms / 5,000 ms |
コード長 | 2,700 bytes |
コンパイル時間 | 2,065 ms |
コンパイル使用メモリ | 201,112 KB |
最終ジャッジ日時 | 2025-02-08 19:08:49 |
ジャッジサーバーID (参考情報) |
judge1 / judge1 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 3 |
other | AC * 22 |
ソースコード
#include <bits/stdc++.h>using namespace std;//#include <atcoder/all>//using namespace atcoder;using ll = long long;using vll = vector<ll>;using vvll = vector<vll>;using vvvll = vector<vvll>;using vvvvll = vector<vvvll>;using vvvvvll = vector<vvvvll>;using vvvvvvll = vector<vvvvvll>;using vb = vector<bool>;using vvb = vector<vb>;using vvvb = vector<vvb>;using vvvvb = vector<vvvb>;using vd = vector<double>;using vvd = vector<vd>;using vvvd = vector<vvd>;using vvvvd = vector<vvvd>;using vvvvvd = vector<vvvvd>;#define all(A) A.begin(),A.end()#define ALL(A) A.begin(),A.end()#define rep(i, n) for (ll i = 0; i < (ll) (n); i++)using pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>;#define tN(t) (t==1?XN:YN)#define tS(t) (t==1?XS:YS)#define tA(t) (t==1?XA:YA)template<class T>bool chmax(T& p, T q, bool C = 1) {if (C == 0 && p == q) {return 1;}if (p < q) {p = q;return 1;}else {return 0;}}template<class T>bool chmin(T& p, T q, bool C = 1) {if (C == 0 && p == q) {return 1;}if (p > q) {p = q;return 1;}else {return 0;}}ll gcd(ll(a), ll(b)) {if (b == 0)return a;ll c = a;while (a % b != 0) {c = a % b;a = b;b = c;}return b;}ll sqrtz(ll N) {ll L = 0;ll R = sqrt(N) + 10000;while (abs(R - L) > 1) {ll mid = (R + L) / 2;if (mid * mid <= N)L = mid;else R = mid;}return L;}vector<ll> fact, factinv, inv;const ll mod = 1e9 + 7;void prenCkModp(ll n) {fact.resize(n + 5);factinv.resize(n + 5);inv.resize(n + 5);fact[1] = fact[1] = 1;factinv[1] = factinv[1] = 1;inv[1] = 1;for (ll i = 2; i < n + 5; i++) {fact[i] = (fact[i - 1] * i) % mod;inv[i] = mod - (inv[mod % i] * (mod / i)) % mod;factinv[i] = (factinv[i - 1] * inv[i]) % mod;}}ll nCk(ll n, ll k) {if (n < k) return 0;return fact[n] * (factinv[k] * factinv[n - k] % mod) % mod;}//const ll mod=1e9+7;ll N, S, K;vvll DP;ll dfs(ll n, ll s) {if (DP[n][s] >= 0)return DP[n][s];if (n == 0) {return (s == 0);}else {ll res = 0;res+=dfs(n-1,s);if(s>=n)res+=dfs(n,s-n);res%=mod;DP[n][s] = res;return res;}}int main() {cin.tie(nullptr);ios::sync_with_stdio(false);cin >> N >> S >> K;DP.assign(N + 1, vll(S + 1, -1));S -= ((N * (N - 1)) / 2) * K;if (S < 0) {cout << 0 << endl;return 0;}cout << dfs(N, S) << endl;}