結果
問題 | No.20 砂漠のオアシス |
ユーザー | is_eri23 |
提出日時 | 2014-10-24 13:47:22 |
言語 | C++11 (gcc 11.4.0) |
結果 |
WA
(最新)
AC
(最初)
|
実行時間 | - |
コード長 | 3,403 bytes |
コンパイル時間 | 1,479 ms |
コンパイル使用メモリ | 167,256 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-10-13 04:56:55 |
合計ジャッジ時間 | 2,222 ms |
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 2 ms
5,248 KB |
testcase_01 | AC | 2 ms
5,248 KB |
testcase_02 | AC | 2 ms
5,248 KB |
testcase_03 | AC | 3 ms
5,248 KB |
testcase_04 | AC | 4 ms
5,248 KB |
testcase_05 | AC | 28 ms
5,248 KB |
testcase_06 | AC | 31 ms
5,248 KB |
testcase_07 | AC | 29 ms
5,248 KB |
testcase_08 | AC | 23 ms
5,248 KB |
testcase_09 | AC | 29 ms
5,248 KB |
testcase_10 | WA | - |
testcase_11 | AC | 2 ms
5,248 KB |
testcase_12 | WA | - |
testcase_13 | AC | 3 ms
5,248 KB |
testcase_14 | AC | 5 ms
5,248 KB |
testcase_15 | AC | 4 ms
5,248 KB |
testcase_16 | WA | - |
testcase_17 | WA | - |
testcase_18 | WA | - |
testcase_19 | AC | 8 ms
5,248 KB |
testcase_20 | AC | 2 ms
5,248 KB |
ソースコード
#include <bits/stdc++.h> #define EPS 1e-9 #define INF 1070000000LL #define MOD 1000000007LL #define fir first #define foreach(it,X) for(auto it=(X).begin();it!=(X).end();it++) #define numa(x,a) for(auto x: a) #define ite iterator #define mp make_pair #define mt make_tuple #define rep(i,n) rep2(i,0,n) #define rep2(i,m,n) for(int i=m;i<(n);i++) #define pb push_back #define pf push_front #define sec second #define sz(x) ((int)(x).size()) #define ALL( c ) (c).begin(), (c).end() #define gcd(a,b) __gcd(a,b) #define mem(x,n) memset(x,n,sizeof(x)) #define endl "\n" using namespace std; template <int POS, class TUPLE> void deploy(std::ostream &os, const TUPLE &tuple){} template <int POS, class TUPLE, class H, class ...Ts> void deploy(std::ostream &os, const TUPLE &t){ os << (POS == 0 ? "" : ", ") << get<POS>(t); deploy<POS + 1, TUPLE, Ts...>(os, t); } template <class T> std::ostream& operator<<(std::ostream &os, std::vector<T> &v){ int remain = v.size(); os << "{"; for(auto e: v) os << e << (--remain == 0 ? "}" : ", "); return os; } template <class T> std::ostream& operator<<(std::ostream &os, std::set<T> &v){ int remain = v.size(); os << "{"; for(auto e: v) os << e << (--remain == 0 ? "}" : ", "); return os; } template <class T, class K> std::ostream& operator<<(std::ostream &os, std::map<T, K> &mp){ int remain = mp.size(); os << "{"; for(auto e: mp) os << "(" << e.first << " -> " << e.second << ")" << (--remain == 0 ? "}" : ", "); return os; } #define DEBUG1(var0) { std::cerr << (#var0) << "=" << (var0) << endl; } #define DEBUG2(var0, var1) { std::cerr << (#var0) << "=" << (var0) << ", ";DEBUG1(var1); } #define DEBUG3(var0, var1, var2) { std::cerr << (#var0) << "=" << (var0) << ", ";DEBUG2(var1,var2); } #define DEBUG4(var0, var1, var2, var3) { std::cerr << (#var0) << "=" << (var0) << ", ";DEBUG3(var1,var2,var3); } using ll = long long; ll nums[210][210]; ll cost[210][210]; int N,V,Ox,Oy; ll Dijkstra(pair <int,int> start,pair <int,int> goal){ priority_queue<pair <ll,pair <int,int> >,vector <pair <ll,pair <int,int> > >,greater<pair <ll,pair <int,int> > > > que; rep(i,210){ rep(j,210){ cost[i][j] = INF; } } que.push(mp(0,start)); int dx[] = {0,-1,1,0}; int dy[] = {-1,0,0,1}; while(!que.empty()){ auto x = que.top();que.pop(); int a = x.sec.fir,b=x.sec.sec; int c = x.fir; if(cost[a][b] != INF){ continue; } cost[a][b] = c; if(a == goal.fir && b == goal.sec){ break; } rep(i,4){ int nx = a + dx[i],ny = b + dy[i]; if(1 <= nx && nx <= N && 1<=ny && ny <= N && cost[nx][ny] == INF){ que.push(mp(c+nums[nx][ny],mp(nx,ny))); } } } return cost[goal.fir][goal.sec]; } int main(){ cin.tie(0); ios_base::sync_with_stdio(0); cin >> N >> V >> Ox >> Oy; rep2(i,1,N+1){ rep2(j,1,N+1){ cin >> nums[i][j]; } } ll c = Dijkstra(mp(1,1),mp(N,N)); bool OK = false; if(c < V){ OK = true; } //DEBUG1(c); if(1 <= Ox && Ox <= N && 1 <= Oy && Oy <= N){ ll c1 = Dijkstra(mp(1,1),mp(Ox,Oy)); if(c1 < V){ V -= c1; V *= 2; ll c2 = Dijkstra(mp(Ox,Oy),mp(N,N)); if(c2 < V){ OK = true; } //DEBUG3(c1,c2,V); } } if(OK){ cout << "YES\n"; }else{ cout << "NO\n"; } return 0; }