結果
問題 | No.2097 AND^k |
ユーザー | chro_96 |
提出日時 | 2022-11-09 22:44:05 |
言語 | C (gcc 12.3.0) |
結果 |
TLE
|
実行時間 | - |
コード長 | 4,062 bytes |
コンパイル時間 | 482 ms |
コンパイル使用メモリ | 34,176 KB |
実行使用メモリ | 17,156 KB |
最終ジャッジ日時 | 2024-07-23 03:40:46 |
合計ジャッジ時間 | 18,607 ms |
ジャッジサーバーID (参考情報) |
judge4 / judge1 |
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テストケース
テストケース表示入力 | 結果 | 実行時間 実行使用メモリ |
---|---|---|
testcase_00 | AC | 4 ms
10,476 KB |
testcase_01 | AC | 4 ms
10,340 KB |
testcase_02 | AC | 4 ms
10,344 KB |
testcase_03 | AC | 5 ms
10,380 KB |
testcase_04 | AC | 5 ms
10,344 KB |
testcase_05 | AC | 3 ms
10,476 KB |
testcase_06 | AC | 4 ms
10,472 KB |
testcase_07 | AC | 5 ms
10,384 KB |
testcase_08 | AC | 2,974 ms
10,368 KB |
testcase_09 | AC | 1,460 ms
10,476 KB |
testcase_10 | AC | 3,234 ms
10,472 KB |
testcase_11 | AC | 1,391 ms
10,388 KB |
testcase_12 | AC | 1,245 ms
10,360 KB |
testcase_13 | TLE | - |
testcase_14 | -- | - |
testcase_15 | -- | - |
testcase_16 | -- | - |
testcase_17 | -- | - |
testcase_18 | -- | - |
testcase_19 | -- | - |
testcase_20 | -- | - |
testcase_21 | -- | - |
testcase_22 | -- | - |
testcase_23 | -- | - |
testcase_24 | -- | - |
testcase_25 | -- | - |
ソースコード
#include <stdio.h> long long mod_num = 998244353LL; long long root = 3LL; int length = 998244352; long long inverse_root = 0LL; long long inverse_l = 0LL; long long power_mod (long long a, long long b, long long p) { long long ans = 0LL; a %= p; if (b <= 0LL) { return 1LL; } ans = power_mod(a, b/2LL, p); ans = (ans * ans) % p; if (b%2LL == 1LL) { ans = (ans * a) % p; } return ans; } void setup_ntt (int l) { int tmp_length = 2; while(tmp_length < 2*l) { tmp_length *= 2; } root = power_mod(root, length / tmp_length, mod_num); inverse_root = power_mod(root, mod_num-2LL, mod_num); inverse_l = power_mod((long long) tmp_length, mod_num-2LL, mod_num); length = tmp_length; return; } void ntt_2n (long long *a, long long root) { int log = 0; long long pow_root[32] = {}; while ((1<<log) < length) { log++; } pow_root[log-1] = root; for (int i = log-1; i > 0; i--) { pow_root[i-1] = pow_root[i]; pow_root[i-1] *= pow_root[i]; pow_root[i-1] %= mod_num; } for (int i = 0; i < length; i++) { int idx = 0; int tmp = i; for (int j = 0; j < log; j++) { idx <<= 1; idx |= (tmp&1); tmp >>= 1; } if (i < idx) { int swap = a[i]; a[i] = a[idx]; a[idx] = swap; } } for (int i = 0; i < log; i++) { int step = (1<<i); int cnt = length/(2*step); long long tmp_root = 1LL; for (int j = 0; j < step; j++) { for (int k = 0; k < cnt; k++) { long long tmp1 = a[(k<<(i+1))+j]; long long tmp2 = (a[((2*k+1)<<i)+j]*tmp_root)%mod_num; a[(k<<(i+1))+j] = (tmp1+tmp2)%mod_num; a[((2*k+1)<<i)+j] = (tmp1+mod_num-tmp2)%mod_num; } tmp_root = (tmp_root*pow_root[i])%mod_num; } } return; } int main () { int n = 0; int m = 0; int l = 0; int res = 0; long long ans[300000] = {}; long long work[2][300000] = {}; long long pow2 = 2LL; long long fact[100001] = {}; long long invf[100001] = {}; res = scanf("%d", &n); res = scanf("%d", &m); res = scanf("%d", &l); fact[0] = 1LL; for (int i = 0; i < l; i++) { fact[i+1] = fact[i]; fact[i+1] *= (long long) (i+1); fact[i+1] %= mod_num; } invf[l] = power_mod(fact[l], mod_num-2LL, mod_num); for (int i = l; i > 0; i--) { invf[i-1] = invf[i]; invf[i-1] *= (long long)i; invf[i-1] %= mod_num; } setup_ntt(l+1); work[0][0] = power_mod(2LL, (long long)n, mod_num); for (int i = 1; i <= l; i++) { work[0][i] = invf[i]; } for (int i = 0; i <= l; i++) { work[1][i] = work[0][i]; } ntt_2n(work[1], root); if (m%2 == 1) { for (int i = 0; i <= l; i++) { ans[i] = work[0][i]; } } else { ans[0] = 1LL; } m /= 2; while (m > 0) { long long p = 1LL; for (int j = 0; j <= l; j++) { work[0][j] *= p; work[0][j] %= mod_num; p = (p*pow2)%mod_num; } ntt_2n(work[0], root); for (int j = 0; j < length; j++) { work[0][j] *= work[1][j]; work[0][j] %= mod_num; } ntt_2n(work[0], inverse_root); for (int j = 0; j <= l; j++) { work[0][j] *= inverse_l; work[0][j] %= mod_num; work[1][j] = work[0][j]; } for (int j = l+1; j < length; j++) { work[0][j] = 0LL; work[1][j] = 0LL; } ntt_2n(work[1], root); pow2 = (pow2*pow2)%mod_num; if (m%2 == 1) { long long p = 1LL; for (int i = 0; i <= l; i++) { ans[i] *= p; ans[i] %= mod_num; p = (p*pow2)%mod_num; } for (int i = l+1; i < length; i++) { ans[i] = 0LL; } ntt_2n(ans, root); for (int i = 0; i < length; i++) { ans[i] *= work[1][i]; ans[i] %= mod_num; } ntt_2n(ans, inverse_root); for (int i = 0; i <= l; i++) { ans[i] *= inverse_l; ans[i] %= mod_num; } } m /= 2; } for (int i = 0; i < l; i++) { printf("%lld\n", (ans[i+1]*fact[i+1])%mod_num); } return 0; }