結果

問題 No.2097 AND^k
ユーザー chro_96chro_96
提出日時 2022-11-09 22:44:05
言語 C
(gcc 12.3.0)
結果
TLE  
実行時間 -
コード長 4,062 bytes
コンパイル時間 482 ms
コンパイル使用メモリ 34,176 KB
実行使用メモリ 17,156 KB
最終ジャッジ日時 2024-07-23 03:40:46
合計ジャッジ時間 18,607 ms
ジャッジサーバーID
(参考情報)
judge4 / judge1
このコードへのチャレンジ
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テストケース

テストケース表示
入力 結果 実行時間
実行使用メモリ
testcase_00 AC 4 ms
10,476 KB
testcase_01 AC 4 ms
10,340 KB
testcase_02 AC 4 ms
10,344 KB
testcase_03 AC 5 ms
10,380 KB
testcase_04 AC 5 ms
10,344 KB
testcase_05 AC 3 ms
10,476 KB
testcase_06 AC 4 ms
10,472 KB
testcase_07 AC 5 ms
10,384 KB
testcase_08 AC 2,974 ms
10,368 KB
testcase_09 AC 1,460 ms
10,476 KB
testcase_10 AC 3,234 ms
10,472 KB
testcase_11 AC 1,391 ms
10,388 KB
testcase_12 AC 1,245 ms
10,360 KB
testcase_13 TLE -
testcase_14 -- -
testcase_15 -- -
testcase_16 -- -
testcase_17 -- -
testcase_18 -- -
testcase_19 -- -
testcase_20 -- -
testcase_21 -- -
testcase_22 -- -
testcase_23 -- -
testcase_24 -- -
testcase_25 -- -
権限があれば一括ダウンロードができます

ソースコード

diff #

#include <stdio.h>

long long mod_num = 998244353LL;
long long root = 3LL;
int length = 998244352;
long long inverse_root = 0LL;
long long inverse_l = 0LL;

long long power_mod (long long a, long long b, long long p) {
  long long ans = 0LL;
  
  a %= p;
  
  if (b <= 0LL) {
    return 1LL;
  }
  
  ans = power_mod(a, b/2LL, p);
  ans = (ans * ans) % p;
  if (b%2LL == 1LL) {
    ans = (ans * a) % p;
  }
  
  return ans;
}

void setup_ntt (int l) {
  int tmp_length = 2;
  
  while(tmp_length < 2*l) {
    tmp_length *= 2;
  }
  
  root = power_mod(root, length / tmp_length, mod_num);
  inverse_root = power_mod(root, mod_num-2LL, mod_num);
  inverse_l = power_mod((long long) tmp_length, mod_num-2LL, mod_num);
  length = tmp_length;
  
  return;
}

void ntt_2n (long long *a, long long root) {
  int log = 0;
  long long pow_root[32] = {};
  
  while ((1<<log) < length) {
    log++;
  }
  
  pow_root[log-1] = root;
  for (int i = log-1; i > 0; i--) {
    pow_root[i-1] = pow_root[i];
    pow_root[i-1] *= pow_root[i];
    pow_root[i-1] %= mod_num;
  }
  
  for (int i = 0; i < length; i++) {
    int idx = 0;
    int tmp = i;
    for (int j = 0; j < log; j++) {
      idx <<= 1;
      idx |= (tmp&1);
      tmp >>= 1;
    }
    if (i < idx) {
      int swap = a[i];
      a[i] = a[idx];
      a[idx] = swap;
    }
  }
  
  for (int i = 0; i < log; i++) {
    int step = (1<<i);
    int cnt = length/(2*step);
    long long tmp_root = 1LL;
    for (int j = 0; j < step; j++) {
      for (int k = 0; k < cnt; k++) {
        long long tmp1 = a[(k<<(i+1))+j];
        long long tmp2 = (a[((2*k+1)<<i)+j]*tmp_root)%mod_num;
        a[(k<<(i+1))+j] = (tmp1+tmp2)%mod_num;
        a[((2*k+1)<<i)+j] = (tmp1+mod_num-tmp2)%mod_num;
      }
      tmp_root = (tmp_root*pow_root[i])%mod_num;
    }
  }
  
  return;
}

int main () {
  int n = 0;
  int m = 0;
  int l = 0;
  
  int res = 0;
  
  long long ans[300000] = {};
  long long work[2][300000] = {};
  
  long long pow2 = 2LL;
  long long fact[100001] = {};
  long long invf[100001] = {};
  
  res = scanf("%d", &n);
  res = scanf("%d", &m);
  res = scanf("%d", &l);
  
  fact[0] = 1LL;
  for (int i = 0; i < l; i++) {
    fact[i+1] = fact[i];
    fact[i+1] *= (long long) (i+1);
    fact[i+1] %= mod_num;
  }
  
  invf[l] = power_mod(fact[l], mod_num-2LL, mod_num);
  for (int i = l; i > 0; i--) {
    invf[i-1] = invf[i];
    invf[i-1] *= (long long)i;
    invf[i-1] %= mod_num;
  }
  
  setup_ntt(l+1);
  
  work[0][0] = power_mod(2LL, (long long)n, mod_num);
  for (int i = 1; i <= l; i++) {
    work[0][i] = invf[i];
  }
  
  for (int i = 0; i <= l; i++) {
    work[1][i] = work[0][i];
  }
  ntt_2n(work[1], root);
  
  if (m%2 == 1) {
    for (int i = 0; i <= l; i++) {
      ans[i] = work[0][i];
    }
  } else {
    ans[0] = 1LL;
  }
  
  m /= 2;
  
  while (m > 0) {
    long long p = 1LL;
    for (int j = 0; j <= l; j++) {
      work[0][j] *= p;
      work[0][j] %= mod_num;
      p = (p*pow2)%mod_num;
    }
    ntt_2n(work[0], root);
    for (int j = 0; j < length; j++) {
      work[0][j] *= work[1][j];
      work[0][j] %= mod_num;
    }
    ntt_2n(work[0], inverse_root);
    for (int j = 0; j <= l; j++) {
      work[0][j] *= inverse_l;
      work[0][j] %= mod_num;
      work[1][j] = work[0][j];
    }
    for (int j = l+1; j < length; j++) {
      work[0][j] = 0LL;
      work[1][j] = 0LL;
    }
    ntt_2n(work[1], root);
    pow2 = (pow2*pow2)%mod_num;
    if (m%2 == 1) {
      long long p = 1LL;
      for (int i = 0; i <= l; i++) {
        ans[i] *= p;
        ans[i] %= mod_num;
        p = (p*pow2)%mod_num;
      }
      for (int i = l+1; i < length; i++) {
        ans[i] = 0LL;
      }
      ntt_2n(ans, root);
      for (int i = 0; i < length; i++) {
        ans[i] *= work[1][i];
        ans[i] %= mod_num;
      }
      ntt_2n(ans, inverse_root);
      for (int i = 0; i <= l; i++) {
        ans[i] *= inverse_l;
        ans[i] %= mod_num;
      }
    }
    m /= 2;
  }
  
  for (int i = 0; i < l; i++) {
    printf("%lld\n", (ans[i+1]*fact[i+1])%mod_num);
  }
  
  return 0;
}
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