結果
| 問題 |
No.2394 部分和乗総和
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2022-11-23 02:36:37 |
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 146 ms / 2,000 ms |
| コード長 | 1,940 bytes |
| コンパイル時間 | 702 ms |
| コンパイル使用メモリ | 66,516 KB |
| 最終ジャッジ日時 | 2025-02-08 23:23:53 |
|
ジャッジサーバーID (参考情報) |
judge2 / judge3 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| other | AC * 21 |
ソースコード
#include <iostream>
#include <string>
#include <stdio.h>
#include <stdint.h>
using namespace std;
using ll = long long;
#define TYPE_OF( VAR ) remove_const<remove_reference<decltype( VAR )>::type >::type
#define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr )
#define CIN( LL , A ) LL A; cin >> A
#define ASSERT( A , MIN , MAX ) assert( MIN <= A && A <= MAX )
#define CIN_ASSERT( A , MIN , MAX ) CIN( TYPE_OF( MAX ) , A ); ASSERT( A , MIN , MAX )
#define FOR( VAR , INITIAL , FINAL_PLUS_ONE ) for( TYPE_OF( FINAL_PLUS_ONE ) VAR = INITIAL ; VAR < FINAL_PLUS_ONE ; VAR ++ )
#define QUIT return 0
#define RETURN( ANSWER ) cout << ( ANSWER ) << "\n"; QUIT
#define POWER_MOD( ANSWER , ARGUMENT , EXPONENT , MODULO ) \
TYPE_OF( ARGUMENT ) ANSWER{ 1 }; \
{ \
TYPE_OF( ARGUMENT ) ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT ); \
TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT ); \
while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){ \
if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){ \
ANSWER = ( ANSWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
} \
ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT_FOR_SQUARE_FOR_POWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
EXPONENT_FOR_SQUARE_FOR_POWER /= 2; \
} \
} \
template <typename T> inline T Absolute( const T& a ){ return a > 0 ? a : - a; }
#include <cassert>
#define MAIN main
int MAIN()
{
UNTIE;
constexpr const int bound_N = 100000;
CIN_ASSERT( N , 1 , bound_N );
constexpr const ll bound_M = 1000000000000000000;
CIN_ASSERT( M , 1 , bound_M );
constexpr const ll bound_B = 1000000000;
CIN_ASSERT( B , 1 , bound_B );
M %= B;
ll answer = 1;
FOR( i , 0 , N ){
CIN_ASSERT( Ai , 1 , bound_M );
POWER_MOD( power_M , M , Ai , B );
( answer *= 1 + power_M ) %= B;
}
RETURN( answer );
}