結果
| 問題 | No.1094 木登り / Climbing tree |
| ユーザー |
|
| 提出日時 | 2022-12-02 21:46:13 |
| 言語 | PyPy3 (7.3.15) |
| 結果 |
AC
|
| 実行時間 | 1,863 ms / 2,000 ms |
| コード長 | 1,284 bytes |
| コンパイル時間 | 280 ms |
| コンパイル使用メモリ | 81,988 KB |
| 実行使用メモリ | 167,896 KB |
| 最終ジャッジ日時 | 2024-10-09 22:56:51 |
| 合計ジャッジ時間 | 38,292 ms |
|
ジャッジサーバーID (参考情報) |
judge5 / judge1 |
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| ファイルパターン | 結果 |
|---|---|
| sample | AC * 1 |
| other | AC * 26 |
ソースコード
from collections import deque
INF = 1 << 60
n = int(input())
g = [[] for _ in range(n)]
for _ in range(n - 1):
a, b, c = map(int, input().split())
a -= 1
b -= 1
g[a].append((b, c))
g[b].append((a, c))
k = n.bit_length()
src = 0
doub = [[src for _ in range(k)] for _ in range(n)]
depth = [INF for _ in range(n)]
depth[src] = 0
cost = [0 for _ in range(n)]
dq = deque()
dq.appendleft(src)
while len(dq) > 0:
cur = dq.pop()
for nxt, c in g[cur]:
if depth[nxt] < INF:
continue
depth[nxt] = depth[cur] + 1
cost[nxt] = cost[cur] + c
doub[nxt][0] = cur
dq.appendleft(nxt)
for i in range(1, k):
for v in range(n):
doub[v][i] = doub[doub[v][i - 1]][i - 1]
def lca(u, v):
ut = u
vt = v
if depth[ut] > depth[vt]:
ut, vt = vt, ut
diff = depth[vt] - depth[ut]
for i in range(k):
if (diff >> i) & 1 != 0:
vt = doub[vt][i]
if ut != vt:
for i in range(k - 1, -1, -1):
if doub[ut][i] != doub[vt][i]:
ut = doub[ut][i]
vt = doub[vt][i]
if ut != vt:
ut = doub[ut][0]
return ut
q = int(input())
ans = [0 for _ in range(q)]
for i in range(q):
s, t = map(int, input().split())
s -= 1
t -= 1
l = lca(s, t)
ans[i] = cost[s] + cost[t] - 2 * cost[l]
print(*ans, sep='\n')