結果
問題 | No.2143 Only One Bracket |
ユーザー | karinohito |
提出日時 | 2022-12-02 21:51:25 |
言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
結果 |
AC
|
実行時間 | 2 ms / 2,000 ms |
コード長 | 2,252 bytes |
コンパイル時間 | 4,985 ms |
コンパイル使用メモリ | 264,328 KB |
実行使用メモリ | 6,820 KB |
最終ジャッジ日時 | 2024-10-09 23:05:16 |
合計ジャッジ時間 | 4,934 ms |
ジャッジサーバーID (参考情報) |
judge1 / judge5 |
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ファイルパターン | 結果 |
---|---|
sample | AC * 1 |
other | AC * 7 |
ソースコード
#include <bits/stdc++.h> using namespace std; #include <atcoder/all> using namespace atcoder; using ll = long long; using vll = vector<ll>; using vvll = vector<vll>; using vvvll = vector<vvll>; using vvvvll = vector<vvvll>; using vvvvvll = vector<vvvvll>; using vvvvvvll = vector<vvvvvll>; using vb = vector<bool>; using vvb = vector<vb>; using vvvb = vector<vvb>; using vvvvb = vector<vvvb>; using vd = vector<double>; using vvd = vector<vd>; using vvvd = vector<vvd>; using vvvvd = vector<vvvd>; using vvvvvd = vector<vvvvd>; #define all(A) A.begin(),A.end() #define ALL(A) A.begin(),A.end() #define rep(i, n) for (ll i = 0; i < (ll) (n); i++) using pqr = priority_queue<pair<ll, ll>, vector<pair<ll, ll>>, greater<pair<ll, ll>>>; template<class T> bool chmax(T& p, T q, bool C = 1) { if (C == 0 && p == q) { return 1; } if (p < q) { p = q; return 1; } else { return 0; } } template<class T> bool chmin(T& p, T q, bool C = 1) { if (C == 0 && p == q) { return 1; } if (p > q) { p = q; return 1; } else { return 0; } } ll gcd(ll(a), ll(b)) { if (a == 0)return b; if (b == 0)return a; ll c = a; while (a % b != 0) { c = a % b; a = b; b = c; } return b; } ll sqrtz(ll N) { ll L = 0; ll R = sqrt(N) + 10000; while (abs(R - L) > 1) { ll mid = (R + L) / 2; if (mid * mid <= N)L = mid; else R = mid; } return L; } using mint = modint998244353; vector<mint> fact, factinv, inv; const ll mod = 998244353; void prenCkModp(ll n) { fact.resize(n + 5); factinv.resize(n + 5); inv.resize(n + 5); fact[0] = fact[1] = 1; factinv[0] = factinv[1] = 1; inv[1] = 1; for (ll i = 2; i < n + 5; i++) { fact[i] = (fact[i - 1] * i); inv[i] = mod - (inv[mod % i] * (mod / i)); factinv[i] = (factinv[i - 1] * inv[i]); } } mint nCk(ll n, ll k) { if (n < k||k<0) return 0; return fact[n] * (factinv[k] * factinv[n - k]); } int main() { ll N; cin>>N; rep(i,N-1){ rep(j,i)cout<<')'; rep(j,i+1)cout<<'('; cout<<endl; } rep(i,N-1)cout<<')'; cout<<endl; }