結果

問題 No.2144 MM
ユーザー kanra824
提出日時 2022-12-02 23:37:50
言語 C++14
(gcc 13.3.0 + boost 1.87.0)
結果
AC  
実行時間 24 ms / 2,000 ms
コード長 3,246 bytes
コンパイル時間 1,657 ms
コンパイル使用メモリ 169,312 KB
実行使用メモリ 5,248 KB
最終ジャッジ日時 2024-10-10 02:05:29
合計ジャッジ時間 3,396 ms
ジャッジサーバーID
(参考情報)
judge4 / judge2
このコードへのチャレンジ
(要ログイン)
ファイルパターン 結果
sample AC * 3
other AC * 35
権限があれば一括ダウンロードができます

ソースコード

diff #
プレゼンテーションモードにする

#include <bits/stdc++.h>
using namespace std;
#define REP(i, n) for (int i = 0; i < (n); ++i)
#define RREP(i, n) for (int i = (n); i >= 0; --i)
#define FOR(i, a, n) for (int i = (a); i < (n); ++i)
#define RFOR(i, a, b) for (int i = (a); i >= (b); --i)
#define SZ(x) ((int)(x).size())
#define ALL(x) (x).begin(), (x).end()
template <class T>
ostream& operator<<(ostream& os, const vector<T>& v) {
REP(i, SZ(v)) {
if (i) os << " ";
os << v[i];
}
return os;
}
template <class T, class U>
ostream& operator<<(ostream& os, const pair<T, U>& p) {
os << p.first << " " << p.second;
return os;
}
template <class T>
bool chmax(T& a, const T& b) {
bool res = a < b;
if (a < b) a = b;
return res;
}
template <class T>
bool chmin(T& a, const T& b) {
bool res = a > b;
if (a > b) a = b;
return res;
}
using ll = long long;
using ull = unsigned long long;
using ld = long double;
using P = pair<int, int>;
using PLL = pair<ll, ll>;
using vi = vector<int>;
using vll = vector<ll>;
using vvi = vector<vi>;
using vvll = vector<vll>;
const ll MOD = 1e9 + 7;
const ll MOD998 = 998244353;
const int INF = INT_MAX;
const ll LINF = LLONG_MAX;
const int inf = INT_MIN;
const ll linf = LLONG_MIN;
const ld eps = 1e-9;
template<int m>
struct mint {
int x;
mint(ll x = 0) : x(((x % m) + m) % m) {}
mint operator-() const { return x ? m-x : 0; }
mint &operator+=(mint r) {
if ((x += r.x) >= m) x -= m;
return *this;
}
mint &operator-=(mint r) {
if ((x -= r.x) < 0) x += m;
return *this;
}
mint &operator*=(mint r) {
x = ((ll)x * r.x) % m;
return *this;
}
mint inv() const { return pow(m-2); }
mint &operator/=(mint r) { return *this *= r.inv(); }
friend mint operator+(mint l, mint r) { return l += r; }
friend mint operator-(mint l, mint r) { return l -= r; }
friend mint operator*(mint l, mint r) { return l *= r; }
friend mint operator/(mint l, mint r) { return l /= r; }
mint pow(ll n) const {
mint ret = 1, tmp = *this;
while (n) {
if (n & 1) ret *= tmp;
tmp *= tmp, n >>= 1;
}
return ret;
}
friend bool operator==(mint l, mint r) { return l.x == r.x; }
friend bool operator!=(mint l, mint r) { return l.x != r.x; }
friend ostream &operator<<(ostream &os, mint a) {
return os << a.x;
}
friend istream &operator>>(istream &is, mint& a) {
ll x; is >> x; a = x; return is;
}
};
using Int = mint<MOD998>;
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
cout << fixed << setprecision(10);
int n, m; cin >> n >> m;
vi a(n);
REP(i, n) {
cin >> a[i];
}
ll su = 0;
RREP(i, n-1) {
if(i % 2 == 0) {
su -= a[i];
} else {
su += a[i];
}
}
if(su % m != 0) {
cout << -1 << endl;
return 0;
}
Int mul = 1;
Int s = 0;
RREP(i, n-1) {
s += a[i] * mul;
mul *= m-1;
}
s /= m;
cout << s + 1 << endl;
}
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX
0