結果
| 問題 |
No.2144 MM
|
| コンテスト | |
| ユーザー |
👑 |
| 提出日時 | 2022-12-03 00:48:01 |
| 言語 | C++17(gcc12) (gcc 12.3.0 + boost 1.87.0) |
| 結果 |
AC
|
| 実行時間 | 25 ms / 2,000 ms |
| コード長 | 2,054 bytes |
| コンパイル時間 | 3,120 ms |
| コンパイル使用メモリ | 212,776 KB |
| 最終ジャッジ日時 | 2025-02-09 04:36:24 |
|
ジャッジサーバーID (参考情報) |
judge5 / judge3 |
(要ログイン)
| ファイルパターン | 結果 |
|---|---|
| sample | AC * 3 |
| other | AC * 35 |
ソースコード
#pragma GCC optimize ( "O3" )
#pragma GCC target ( "avx" )
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
#define TYPE_OF( VAR ) remove_const<remove_reference<decltype( VAR )>::type >::type
#define UNTIE ios_base::sync_with_stdio( false ); cin.tie( nullptr )
#define CEXPR( LL , BOUND , VALUE ) constexpr const LL BOUND = VALUE
#define CIN( LL , A ) LL A; cin >> A
#define ASSERT( A , MIN , MAX ) assert( MIN <= A && A <= MAX )
#define CIN_ASSERT( A , MIN , MAX ) CIN( TYPE_OF( MAX ) , A ); ASSERT( A , MIN , MAX )
#define FOR( VAR , INITIAL , FINAL_PLUS_ONE ) for( TYPE_OF( FINAL_PLUS_ONE ) VAR = INITIAL ; VAR < FINAL_PLUS_ONE ; VAR ++ )
#define QUIT return 0
#define RETURN( ANSWER ) cout << ( ANSWER ) << "\n"; QUIT
#define POWER_MOD( ANSWER , ARGUMENT , EXPONENT , MODULO ) \
TYPE_OF( ARGUMENT ) ANSWER{ 1 }; \
{ \
TYPE_OF( ARGUMENT ) ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT ) % MODULO; \
TYPE_OF( EXPONENT ) EXPONENT_FOR_SQUARE_FOR_POWER = ( EXPONENT ); \
while( EXPONENT_FOR_SQUARE_FOR_POWER != 0 ){ \
if( EXPONENT_FOR_SQUARE_FOR_POWER % 2 == 1 ){ \
ANSWER = ( ANSWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
} \
ARGUMENT_FOR_SQUARE_FOR_POWER = ( ARGUMENT_FOR_SQUARE_FOR_POWER * ARGUMENT_FOR_SQUARE_FOR_POWER ) % MODULO; \
EXPONENT_FOR_SQUARE_FOR_POWER /= 2; \
} \
} \
int main()
{
UNTIE;
CEXPR( int , bound_N , 200000 );
CIN_ASSERT( N , 2 , bound_N );
CEXPR( ll , bound_M , 1000000 );
CIN_ASSERT( M , 3 , bound_M );
ll A[bound_N];
ll M_minus_2 = M - 2;
ll res = 0;
FOR( i , 0 , N ){
CIN_ASSERT( Ai , 0 , M_minus_2 );
res = ( Ai + ( M - res ) ) % M;
A[i] = Ai;
}
if( res != 0 ){
RETURN( -1 );
}
ll answer = 0;
ll M_minus_1 = M - 1;
CEXPR( ll , P , 998244353 );
FOR( i , 0 , N ){
// やったーp進だー!
answer = ( ( answer * M_minus_1 ) + A[i] ) % P;
}
POWER_MOD( M_inv , M , P - 2 , P );
( ( answer *= M_inv ) += 1 ) %= P;
RETURN( answer );
}